C#

David1987 wrote:

Luc's first version of his second answer parsed it as decimal aswell IIRC

string s=@"\U0061";  // the @ in front tells the compiler to ignore the special meaning of backslashes
int uni;
if (s==null || s.Length!=6 || s[0]!='\\' || s[1]!='U' || 
	!int.TryParse(s.Substring(2, 4), NumberStyles.HexNumber, null, out uni))
		throw new Exception("Bad unicode string in: "+s);
char c=(char)uni;
log("uni="+uni.ToString("X4"));
log("c="+c);

if (!KeyEventArgs.IsRepeat) {
    // whatever you like, here
}

string Text = "John Doe, john@bleh.com, (H) 0412623423234, (W) 1290034589345, Jane Doe, ";
        Regex HomePhoneRegex = new Regex(@"\(H\)[ ]*\d{13}");
        Regex WorkPhoneRegex = new Regex(@"\(W\)[ ]*\d{13}");
        Regex EmailRegex = new Regex(@"\w+([-+.']\w+)*@\w+([-.]\w+)*\.\w+([-.]\w+)*");

        String HomePhone = String.Empty;
        String WorkPhone = String.Empty;
        String Email = String.Empty;

        if (HomePhoneRegex.Matches(Text).Count == 1)
        {
            HomePhone = HomePhoneRegex.Matches(Text)[0].Value.Replace("(H)", String.Empty).Trim();
        }
        if (WorkPhoneRegex.Matches(Text).Count == 1)
        {
            WorkPhone = WorkPhoneRegex.Matches(Text)[0].Value.Replace("(W)", String.Empty).Trim();
        }

        if (EmailRegex.Matches(Text).Count == 1)
        {
            Email = EmailRegex.Matches(Text)[0].ToString();
        }