installation of c# project - C# Discussion Boards

17-Jun-10 5:40

And the question is?

Please describe the problem and share what you have tried so far. Also, you need to fix the link in your post.

Re: GroupBox DockStyle

Endien17-Jun-10 5:55

17-Jun-10 5:55

Thank you d@nish for the reply.

Yes, i just tried how to put link to my screenshot since it was the first time for me.

Luc Pattyn17-Jun-10 6:32

Luc Pattyn

17-Jun-10 6:32

You did not make clear what you want, and the image is not really helping in probing your mind.

In your code I see a TabPage with a GroupBox and an iGrid added to it, both docked to the bottom or more. So they are bound to overlap.

There are many ways to make them not overlap, pick one:
1. make the iGrid anchored all around but leave sufficient bottom for the GroupBox;
2. add the iGrid to the GroupBox, GroupBox docked fill, iGrid anchored all around.
3. use a SplitContainer (is overkill IMO)
4. use a TableLayoutPanel; you might add the two labels and one iGrid directly to it.

Smile | :)

Luc Pattyn [Forum Guidelines] [Why QA sucks] [My Articles] Nil Volentibus Arduum

Please use < PRE > tags for code snippets, it preserves indentation, and improves readability.

Endien17-Jun-10 6:58

17-Jun-10 6:58

Thank you Luc for the reply.

Luc Pattyn wrote:
You did not make clear what you want, and the image is not really helping in probing your mind.

Yes, sorry for that. Maybe i should explain the image. On the image, there's an arrow point to a row in the grid. As we can see, the groupBox is "above" the grid. Also we can see that the groupBox is hiding the grid scrollBar. What i want is the rows in the grid can be seen all until the last row but the groupBox still on below position of the form.

I had pick your suggestion no. 1 and it didn't work.

For your suggestion no. 2, i don't want the grid inside the groupBox ( i want them to be separated ).

Suggestion no. 3 and 4 not tried yet.

Luc Pattyn17-Jun-10 7:15

Luc Pattyn

17-Jun-10 7:15

Endien wrote:
I had pick your suggestion no. 1 and it didn't work.

So you did it wrong; of course it can be made to work. And there are many more ways to get what you want, based on location/size/bounds properties and events.

Smile | :)

Luc Pattyn [Forum Guidelines] [Why QA sucks] [My Articles] Nil Volentibus Arduum

Please use < PRE > tags for code snippets, it preserves indentation, and improves readability.

Endien17-Jun-10 7:16

17-Jun-10 7:16

The best solution is using Luc suggestion number 4. Using TableLayoutPanel.

I will share the code in a few minutes.

Endien17-Jun-10 7:34

installation of c# project

17-Jun-10 7:34

private void InitializeTab()
        {
            int intJmlChannel = Convert.ToInt32(channel.DefaultPersister.CountChannel());
            intChannelth = 1;

            myTabs = new TabPage[intJmlChannel];
            GroupBox[] myGroupBox = new GroupBox[intJmlChannel];
            Label[] myLabelMsisdn = new Label[intJmlChannel];
            Label[] myLabelPort = new Label[intJmlChannel];
            TableLayoutPanel[] tbl = new TableLayoutPanel[intJmlChannel];
            
            List<channel> listChannel = channel.DefaultPersister.ListAll().ToList();
            myGrid = new iGrid[intJmlChannel];

            for (int i = 1; i <= intJmlChannel; i++)
            {
                tbl[i-1] = new TableLayoutPanel();
                tbl[i - 1].RowCount = 2;
                tbl[i - 1].ColumnCount = 1;
                tbl[i - 1].Dock = DockStyle.Fill;

                myGrid[i-1] = new iGrid();
                myGrid[i-1].BorderStyle = iGBorderStyle.Flat;
                myGrid[i-1].DefaultCol.CellStyle = iGrid1DefaultCellStyle;
                myGrid[i-1].DefaultCol.ColHdrStyle = iGrid1DefaultColHdrStyle;
                myGrid[i-1].Dock = DockStyle.Fill;
                myGrid[i-1].ForeColor = SystemColors.WindowText;
                myGrid[i-1].Header.Height = 19;
                myGrid[i-1].RowTextCol.CellStyle = iGrid1RowTextColCellStyle;
                myGrid[i-1].Size = new Size(902, 458);
                myGrid[i-1].TabIndex = 0;
                myGrid[i-1].TreeCol = null;
                myGrid[i-1].TreeLines.Color = SystemColors.WindowText;
                myGrid[i-1].BackColorEvenRows = Color.PaleTurquoise;
                myGrid[i - 1].ReadOnly = true;

                myTabs[i - 1] = new TabPage(listChannel[i - 1].MsisdnChannel);
                myTabs[i - 1].Name = listChannel[i-1].MsisdnChannel;

                if (listChannel[i - 1].SubDealer == 5)
                {
                    myTabs[i - 1].BackColor = Color.Pink;
                    myTabs[i - 1].ForeColor = Color.Blue;
                }

                myGroupBox[i-1] = new GroupBox();
                myGroupBox[i - 1].TabIndex = 1;
                myGroupBox[i - 1].TabStop = false;
                myGroupBox[i - 1].Dock = DockStyle.Fill;
                myGroupBox[i-1].Size = new Size(902, 91);

                myLabelMsisdn[i - 1] = new Label();
                myLabelMsisdn[i - 1].AutoSize = true;
                myLabelMsisdn[i - 1].Text = "Port : " + listChannel[i-1].PortNumber;
                myLabelMsisdn[i - 1].Location = new Point(7, 20);
                myLabelMsisdn[i-1].Size = new Size(35, 13);
                myLabelMsisdn[i-1].TabIndex = 0;

                myLabelPort[i-1] = new Label();
                myLabelPort[i-1].AutoSize = true;
                myLabelPort[i-1].Location = new Point(7, 44);
                myLabelPort[i-1].Size = new Size(35, 13);
                myLabelPort[i-1].TabIndex = 1;
                myLabelPort[i - 1].Text = "Sub Dealer : " + listChannel[i-1].SubDealer;
                
                myGroupBox[i-1].Controls.Add(myLabelMsisdn[i-1]);
                myGroupBox[i - 1].Controls.Add(myLabelPort[i - 1]);
                
                tbl[i-1].Controls.Add(myGrid[i-1],0,0);
                tbl[i-1].Controls.Add(myGroupBox[i-1],0,1);

                tbl[i - 1].RowStyles.Add(new RowStyle(SizeType.Percent, 85F));
                tbl[i - 1].RowStyles.Add(new RowStyle(SizeType.Percent, 15F));
                tbl[i - 1].RowStyles[1].SizeType = SizeType.Percent;
                tbl[i - 1].RowStyles[1].Height = 15;

                myTabs[i-1].Controls.Add(tbl[i-1]);
                tabControl.Pages.Add(myTabs[i-1]);
            }
        }

The screenshot : http://h.imagehost.org/0646/picture2.jpg

Thank you Luc for suggestion no. 4

prithaa17-Jun-10 5:11

prithaa

17-Jun-10 5:11

Hello,

I have a project which has Excel object reference to object library 5.0. I want to install the project on some other comp.What files will I have to zip alongwith my .exe file
I am working on Windows XP and the client is on Windows 2000. Will that make any difference.
Is there any site which can help me in installation and guide me through versions of Excel and how to handle version differnces.

Pritha

Re: installation of c# project

dan!sh 17-Jun-10 5:36

Need to call methods in Java classes

17-Jun-10 5:36

prithaa wrote:
What files will I have to zip alongwith my .exe file

I guess you will have to add redistributable PIA[^] to your set up.

prithaa wrote:
Is there any site which can help me in installation and guide me through versions of Excel and how to handle version differnces.

You can use late binding here. This[^] article would help understanding it.

Adam Brown 317-Jun-10 4:34

Adam Brown 3

17-Jun-10 4:34

I need to make a call to a third party Java API made up of Java classes. Is that possible with C#, or do I need an interface written as a web service to do the translations on both sides?

Re: Need to call methods in Java classes

dan!sh 17-Jun-10 4:48

how to detect a remote assistance session programatically

17-Jun-10 4:48

1. The easiest way would be to have web service.
2. You can make use of JNBridge[^].

Hert17-Jun-10 2:46

Hert

17-Jun-10 2:46

hello,

I'd like my program to detect when another user is watching/controlling the machine the program is running on. I tought I could check this by doing a WTSRegisterSessionNotification and then checking the WM_WTSSESSION_CHANGE messages, but unfortunately they don't seem to fire when a remote user logs on with RA.

thanks,
Gert

Re: how to detect a remote assistance session programatically

dan!sh 17-Jun-10 4:55

Re: how to detect a remote assistance session programatically

17-Jun-10 4:55

I guess the ProcessIdToSessionId[^] method in Kernel32.dll might help you.

Bernhard Hiller17-Jun-10 5:04

Bernhard Hiller

17-Jun-10 5:04

Furthermore, some Remote Assistance programs like VNC, TeamViewer, NetViewer etc. do so without a formal log-on procedure, from the point of view of windows the other user is not logged on.
You would have to watch the processes on that machine, perhaps using WMI; maybe you could then get an event when such a program is started.

Re: how to detect a remote assistance session programatically

Hert17-Jun-10 20:35

Hert

17-Jun-10 20:35

Just to clarify: I do mean detecting Microsofts Remote Assistance feature.
Your suggestion does work for XP as the process rdsaddin.exe appears when RA is active. It doesn't work on Vista (and I suppose Windows 7) though as no extra processes are created on Vista when an RA connection is set up...

Axhost problem with unregistered ocx

aevanscambs17-Jun-10 2:32

aevanscambs

17-Jun-10 2:32

Hi, I have got a strange problem when using a AxHost wrapped activex control.

We normally access this control from multiple c# threads, and have never had a problem with this until now. But after adding a manifest file to the .exe in order to enable reg-free COM (so we don't have to register the activeX control on customer machines), the control will now crash when accessed from any background thread as long as it is not registered on the current machine. If it is registered then it can be used from multiple threads just fine.

Any help would be appreciated as this is a very strange problem, perhaps I am missing something from the manifest file?

The manifest file contains a "file" entry which points to the relevent .ocx file, with a "comClass" subitem, with "clsid" set as required and "threadingModel" set to "Apartment" (changing the threading model doesn't seem to have any affect on this behaviour).

For example:

public Form1()
{
    InitializeComponent();
    control = new AxLib.AxControl();
    control.Dock = DockStyle.Fill;
    this.Controls.Add(control);

    control.CreateControl();
}

private void Form1_Load(object sender, EventArgs e)
{  
    control.DoSomething(); // Works fine whether or not control is registered on current machine
       
    myThread = new Thread(myThread_ThreadStart);
    myThread.Start();
}

void myThread_ThreadStart(object arg)
{
    control.DoSomething(); // Crashes if control is not registered on current machine
}

Message Closed

17-Jun-10 2:56

stancrm

17-Jun-10 2:56

Message Closed

modified 23-Nov-14 6:21am.

Re: Axhost problem with unregistered ocx

aevanscambs17-Jun-10 3:22

aevanscambs

17-Jun-10 3:22

This doesn't seem to apply to methods called from the actual activeX (COM) object - we make calls on the activeX object all over the place on background threads.

Its only if the control is unregistered (so loading locally through the manifest) that we encounter problems.

time independent text animation

sleeping_b17-Jun-10 2:01

sleeping_b

17-Jun-10 2:01

Hi all

I am trying to create a form with some simple text animation (like scrolling, fade-in etc.).
One of the requirements is to make the code time independent. meaning, no matter if the machine the application will run on is slow or quick, the animation should take exactly the same time. if needed - it should "jump" over frames.

If i understand correctly, using Timer is not the answer, right?

I am a real begginer in C# and .NET so please be easy with me Laugh | :laugh:

harold aptroot17-Jun-10 4:29

harold aptroot

17-Jun-10 4:29

How many frames per second does your animation have?

edit: that is relevant, because if you have say 15 frames be second, just using a timer (without correcting for the actual time) is fine.

Dave Kreskowiak17-Jun-10 4:37

Dave Kreskowiak

17-Jun-10 4:37

Usually, you'd draw the first frame, get the current time in milliseconds, then when your drawing code is called again, get the new time and get the difference between the previous run and this one. That's the time increment you use to calculate your new drawing points of your animation. The current time is now going to be your previous time for the next drawing iteration.

A guide to posting questions on CodeProject[^]

Dave Kreskowiak
Microsoft MVP
Visual Developer - Visual Basic
2006, 2007, 2008
But no longer in 2009...

Ennis Ray Lynch, Jr.17-Jun-10 5:46

Ennis Ray Lynch, Jr.

17-Jun-10 5:46

Wouldn't that make the animation time dependent Smile | :)

Need custom software developed? I do custom programming based primarily on MS tools with an emphasis on C# development and consulting.

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"Sir I exist!"
"However," replied the universe,
"The fact has not created in me
A sense of obligation."
--Stephen Crane

Luc Pattyn17-Jun-10 6:50

Luc Pattyn

17-Jun-10 6:50

animation = motion = time-dependent by definition, whatever your approach. Dave's one is fine.
The OP's wording was a bit weird, I know you've got used to that by now. Laugh | :laugh:

Luc Pattyn [Forum Guidelines] [Why QA sucks] [My Articles] Nil Volentibus Arduum

Please use < PRE > tags for code snippets, it preserves indentation, and improves readability.

Ennis Ray Lynch, Jr.17-Jun-10 7:39

Ennis Ray Lynch, Jr.

17-Jun-10 7:39

Should be time-dependent by definition but it was not always the case. 80's and early 90's computer games are good examples of this, they were clock-cycle dependent because the processors of the time were never fast enough. I was not criticism any of the suggestions merely pointing out what should have been obvious.