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Thanks Sir !!
I problem is solved.. i set the the namespace atrribute in the root!! thanks once again for being so kind..
Regrds
Samir
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Hi,
I am trying to pass value from one windows form to another in desktop application using C#.
I have created two text boxes on Form1 and a button, on button click I am creating Form2 and From2 contains one button, on this button click I have to pass value from Form2 to Form1 textboxes.
I have created Properties in Form1.
public string Emp
{
get
{
return strEmp;
}
set
{
strEmp = value;
}
}
public string EmpID
{
get
{
return strEmpID;
}
set
{
strEmpID = value;
}
}
And on Form1 button click:
private void button1_Click(object sender, EventArgs e)
{
Form2 fr = new Form2();
this.textBox1.Text = strEmp ;
this.textBox2.Text = strEmpID ;
fr.ShowDialog();
}
On Form2:
private void button1_Click(object sender, EventArgs e)
{
Form1 fr = new Form1();
fr. Emp = "Alex";
fr. EmpID = "1121";
this.Close();
}
This code is not working, Please let me know where I am wrong.
Thanks,
modified on Wednesday, March 31, 2010 12:54 AM
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First there is a compilation error at the 2 statements in which you are assigning variables to the textbox as name of the variables differ.
Second, you are setting the values in the text box of first form after calling the showdialog. So, the values can e displayed only after you close the dialog box.
Third, You are creating a new instance of form1 on the click of button on form2. It won't set the values on the initial form.
Praveen Raghuvanshi
Software Engineer,
India.
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Thanks for your time but please let me know the right solution.
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The link provided by 'eg_Anubhava' explains the communication in a clear way.
Praveen Raghuvanshi
Software Engineer,
India.
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In addition to the article already linked - here's[^] a quick Tip that shows how to do it concisely
DaveIf this helped, please vote & accept answer!
Binging is like googling, it just feels dirtier. (Pete O'Hanlon)
BTW, in software, hope and pray is not a viable strategy. (Luc Pattyn)
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Hello,
I am looking for ways to reposition the cursor when I am clicked on the first menu item from a form menu. It should create a jumping effect so the user doesn't have to scroll through the other menus which don't have a child menu.
for example.... one file menu has 4 items. Namely 1, 2, 3, 4 now only item 2 has child menu items. namely 2.1, 2.2, 2.3. I want the cursor to be on 2.1 when the user brings the mouse on 2.
Please let me know how to do that. I am trying the following:
private void toolStripMenuItem2_MouseHover(object sender, EventArgs e)
{
toolStripMenuItem2.ShowDropDown();
Point LocalMousePosition_1 = this.PointToClient(Cursor.Position);
System.Windows.Forms.Cursor.Position = new Point(500, 500);
MessageBox.Show(LocalMousePosition_1+"Happy New Year to DOTNETSPIDER.COM guys");
}
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That sounds user-hostile -- I wouldn't use your application if it did that.
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It doesn't matter if it's hostile or not, I need it now for some reason... let's just say all the supervisors in the MSc. program are crazy...... if you know a solution please help me ...otherwise please mind your own business....
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well it doesn't let me add that... i have tried that... it says :
Error 1 'System.Windows.Forms.ToolStripMenuItem' does not contain a definition for 'PointToClient' and no extension method 'PointToClient' accepting a first argument of type 'System.Windows.Forms.ToolStripMenuItem' could be found (are you missing a using directive or an assembly reference?)
I am sure that the child menu item has been shown before that.... please help....
Thanks for replying......
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Ohhh my god, what was i thinking, ofcause you cannot do that... sorry m8. Let me get back to you in a moment...
With great code, comes great complexity, so keep it simple stupid... 
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skhan17 wrote: all the supervisors in the MSc. program are crazy
I can imagine.
I have no idea, but will Focus have any effect?
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I don't know how to use focus.....can you please let me know how to use mouse focus... then I can use it..maybe
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Hi,
Handle the DropDownOpening or DropDownOpened event that occurs when your child menu appears. The Location property will get the screen coordinates of the top left corner of the menu. Apply an offset to put the cursor into the centre of the first menu item.
private void MenuItem_DropDownOpening(object sender, EventArgs e) {
ToolStripMenuItem menu = (ToolStripMenuItem)sender;
Point p = menu.DropDown.Location;
Rectangle r = menu.DropDown.Items[0].Bounds;
p.Offset(r.Width / 2, r.Height / 2);
Cursor.Position = p;
}
Alan.
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THANK YOU SO MUCH..... although I have figured out a manual way.... but this works like a charm....
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PIEBALDconsult wrote: That sounds user-hostile
Agree completely...
Tell me something, how will you go to menu no 3? when you are moving your mouse down to item 1, and then to item 2, and boom... your mouse has gone to item 2.1 
HORRIBLE
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I agree with you too...it's horrible.... and since we both agree on this issue, there is a little chance that you'll also agree that some people always see the glass as half empty...... I chose not to be one of them.
Finally thank you Alan N for helping me out.
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Dude!!
I am not seeing the glass as half empty buddy... There is a fine line between optimism and hallucination.
I am always there standing next to you on optimism and I would always prefer to see the glass as half full...
I only reasoned my doubt that how would you go to Menu Item number 3 in your example. Think about it. It is practically just not possible. By implementing this (so called) feature you are inviting a fault in your menu functionality.
Now, the optimism part:
May be your requirement is that you do not want your user to reach Item 3 and 4. Then, this could be one of the innovative ways. However, in that case, I would have simply preferred disabling the items.
skhan17 wrote: Finally thank you Alan N for helping me out.
Welcome... I do think i have helped you... Provided you understand the problem here.
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public class Form2 : Form
{
private System.ComponentModel.IContainer components = null;
protected override void Dispose(bool disposing)
{
if (disposing && (components != null))
{
components.Dispose();
}
base.Dispose(disposing);
}
private void InitializeComponent()
{
this.menuStrip1 = new System.Windows.Forms.MenuStrip();
this.item1ToolStripMenuItem = new System.Windows.Forms.ToolStripMenuItem();
this.item1ToolStripMenuItem1 = new System.Windows.Forms.ToolStripMenuItem();
this.item2ToolStripMenuItem = new System.Windows.Forms.ToolStripMenuItem();
this.item3ToolStripMenuItem = new System.Windows.Forms.ToolStripMenuItem();
this.item4ToolStripMenuItem = new System.Windows.Forms.ToolStripMenuItem();
this.subItem1ToolStripMenuItem = new System.Windows.Forms.ToolStripMenuItem();
this.subItem2ToolStripMenuItem = new System.Windows.Forms.ToolStripMenuItem();
this.menuStrip1.SuspendLayout();
this.SuspendLayout();
this.menuStrip1.Items.AddRange(new System.Windows.Forms.ToolStripItem[] {
this.item1ToolStripMenuItem});
this.menuStrip1.Location = new System.Drawing.Point(0, 0);
this.menuStrip1.Name = "menuStrip1";
this.menuStrip1.Size = new System.Drawing.Size(491, 24);
this.menuStrip1.TabIndex = 0;
this.menuStrip1.Text = "menuStrip1";
this.item1ToolStripMenuItem.DropDownItems.AddRange(new System.Windows.Forms.ToolStripItem[] {
this.item1ToolStripMenuItem1,
this.item2ToolStripMenuItem,
this.item3ToolStripMenuItem,
this.item4ToolStripMenuItem});
this.item1ToolStripMenuItem.Name = "item1ToolStripMenuItem";
this.item1ToolStripMenuItem.Size = new System.Drawing.Size(77, 20);
this.item1ToolStripMenuItem.Text = "MainMenu";
this.item1ToolStripMenuItem.MouseMove += new System.Windows.Forms.MouseEventHandler(this.item1ToolStripMenuItem_MouseMove);
this.item1ToolStripMenuItem1.Name = "item1ToolStripMenuItem1";
this.item1ToolStripMenuItem1.Size = new System.Drawing.Size(152, 22);
this.item1ToolStripMenuItem1.Text = "Item 1";
this.item2ToolStripMenuItem.DropDownItems.AddRange(new System.Windows.Forms.ToolStripItem[] {
this.subItem1ToolStripMenuItem,
this.subItem2ToolStripMenuItem});
this.item2ToolStripMenuItem.Name = "item2ToolStripMenuItem";
this.item2ToolStripMenuItem.Size = new System.Drawing.Size(152, 22);
this.item2ToolStripMenuItem.Text = "Item 2";
this.item3ToolStripMenuItem.Name = "item3ToolStripMenuItem";
this.item3ToolStripMenuItem.Size = new System.Drawing.Size(152, 22);
this.item3ToolStripMenuItem.Text = "Item 3";
this.item4ToolStripMenuItem.Name = "item4ToolStripMenuItem";
this.item4ToolStripMenuItem.Size = new System.Drawing.Size(152, 22);
this.item4ToolStripMenuItem.Text = "Item 4";
this.subItem1ToolStripMenuItem.Name = "subItem1ToolStripMenuItem";
this.subItem1ToolStripMenuItem.Size = new System.Drawing.Size(152, 22);
this.subItem1ToolStripMenuItem.Text = "SubItem1";
this.subItem2ToolStripMenuItem.Name = "subItem2ToolStripMenuItem";
this.subItem2ToolStripMenuItem.Size = new System.Drawing.Size(152, 22);
this.subItem2ToolStripMenuItem.Text = "SubItem2";
this.AutoScaleDimensions = new System.Drawing.SizeF(6F, 13F);
this.AutoScaleMode = System.Windows.Forms.AutoScaleMode.Font;
this.ClientSize = new System.Drawing.Size(491, 388);
this.Controls.Add(this.menuStrip1);
this.MainMenuStrip = this.menuStrip1;
this.Name = "Form2";
this.Text = "Form2";
this.menuStrip1.ResumeLayout(false);
this.menuStrip1.PerformLayout();
this.ResumeLayout(false);
this.PerformLayout();
}
private System.Windows.Forms.MenuStrip menuStrip1;
private System.Windows.Forms.ToolStripMenuItem item1ToolStripMenuItem;
private System.Windows.Forms.ToolStripMenuItem item1ToolStripMenuItem1;
private System.Windows.Forms.ToolStripMenuItem item2ToolStripMenuItem;
private System.Windows.Forms.ToolStripMenuItem subItem1ToolStripMenuItem;
private System.Windows.Forms.ToolStripMenuItem subItem2ToolStripMenuItem;
private System.Windows.Forms.ToolStripMenuItem item3ToolStripMenuItem;
private System.Windows.Forms.ToolStripMenuItem item4ToolStripMenuItem;
public Form2()
{
InitializeComponent();
SetMenuDetails(item1ToolStripMenuItem);
}
private void SetMenuDetails(ToolStripMenuItem menu)
{
foreach (ToolStripMenuItem item in menu.DropDownItems)
{
UpdateItem(item);
}
}
private void UpdateItem(ToolStripMenuItem item)
{
foreach (ToolStripMenuItem subItem in item.DropDownItems)
{
UpdateItem(subItem);
}
item.MouseMove += new MouseEventHandler(item_MouseUp);
}
void item_MouseUp(object sender, MouseEventArgs e)
{
ToolStripMenuItem item = (ToolStripMenuItem)sender;
if (item.DropDownItems.Count > 0)
{
ToolStripMenuItem subItem = (ToolStripMenuItem)item.DropDownItems[0];
item.ShowDropDown();
Point location = subItem.Bounds.Location;
Cursor.Position = new Point(Cursor.Position.X + location.X + item.Bounds.Width/2, Cursor.Position.Y + location.Y );
}
}
private void item1ToolStripMenuItem_MouseMove(object sender, MouseEventArgs e)
{
this.Text = e.Location.ToString();
}
}
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I wanted to create a custom control property that includes checkboxes, just like ShortCutKeys property for ToolStripMenuItem. How would I create something like this?
thank you
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Let me see if i get this right, you want to put some custom control into the ToolStrip or MenuStrip right ???
With great code, comes great complexity, so keep it simple stupid...
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ok, sorry for not being more clear. No, I have a custom control. And for this control, I need to create a custom property that has checkboxes in my customs control's property grid. Similar to 'Dock' property that displays a clickable custom graphic on the dropdown. Or if you look at 'ShortCutKeys' property for 'ToolStripMenuItem' control, you'll see a drop down with checkboxes.
So lets say I have a custom Button control with custom 'Text' property. And when a user sets this 'Text' property, in the property grid dropdown for this property, I need to display checkboxes with values.
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