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| Well, your question makes no sense. Please rephrase it so that someone can understand it. Best wishes,
Navaneeth
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how to play movie clips and .swf file in .net 3.5v (asp.net)
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| Click the "Play" button. txtspeak is the realm of 9 year old children, not developers. Christian Graus
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I would like to have an option on the website for people to click and launch a popup. This popup would be like a chat window which always remains on the computer window wherever you drag it. So you can browse the site and still have this popup in the corner. how would we go about doing this?
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Maybe you must watch at Here[^]...  but this can't be in every page, so you may effort
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Thanks. I see the example of having the window on the page but would I be able to place the window outside of the page and give the user the ability to move it where ever they want to.
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Have some questions:
Until now edit it so that when you click on the edittemplate appears.
See Picture
Is it possible to change it in such a way that the EditItemTemplate appears when you click on the BoundField ?
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Hi! i've seen that you've solved your row sorting problem! nice! but now your problem is? you have to read the RowUpdating event and also use the RowCommand event! if you click the 'edit' command, c# runs in RowUpdating event and then fires RowCommand (using e.CommandName as "Edit"). using this you can hide or make visible the columns. ex.
foreach (GridViewRow r in GV_ServiciosDetalles.Rows)
{
((Panel)r.FindControl("Panel1")).Style.Remove("display");
((Panel)r.FindControl("Panel2")).Style["display"] = "none";
}So in panel 1 you have a label with Text='<%#Eval("YourBoundField")%>' and in panel 2 you have a textbox with same thing. good luck
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Below the Header: SkillGroup is the BoundField and i try to click of the Boundfield.
i aint have no labels. Just boundfield visible ="true"
<asp:GridView ID="GridView1" runat="server" AutoGenerateColumns="false" CellPadding="4"
AllowSorting="True" DataKeyNames="SKillGroupID,rank_order" ForeColor="#666666"
OnRowCancelingEdit="GrizzdView1_RowCancelingEdit" OnRowDeleting="GridView1_RowDeleting"
OnRowEditing="GridView1_RowEditing" OnRowUpdating="GridView1_RowUpdating" BackColor="#FF6600"
BorderColor="Black" Font-Bold="True" GridLines="Horizontal" Font-Size="Medium"
Font-Strikeout="False" OnRowCommand="GridView1_RowCommand">
<FooterStyle BackColor="#FF8000" Font-Bold="True" ForeColor="White" />
<Columns>
<asp:CommandField HeaderText="Edit-Update" ShowEditButton="True" />
<asp:BoundField DataField="SkillGroupID" Visible="false" ReadOnly="True" />
<asp:BoundField DataField="SkillGroupName" HeaderText="SkillGroup" />
<asp:TemplateField>
<ItemTemplate>
<asp:ImageButton ID="ImageButton1" runat="Server" ImageUrl="~/Image/Hoch.JPG" CausesValidation="false"
CommandName="Up" CommandArgument='<%# Container.DataItemIndex %>' Visible="True" />
<asp:ImageButton ID="ImageButton2" runat="Server" ImageUrl="~/Image/Runter.JPG" CausesValidation="false"
CommandName="Down" CommandArgument='<%# Container.DataItemIndex %>' Visible="True" />
</ItemTemplate>
</asp:TemplateField>
<asp:CommandField HeaderText="Delete" ShowDeleteButton="True" />
</Columns>
<RowStyle BackColor="#E5E5E5" />
<EditRowStyle BackColor="#A9A9A9" />
<SelectedRowStyle BackColor="#A9A9A9" Font-Bold="True" ForeColor="#333333" />
<PagerStyle BackColor="#666666" ForeColor="White" HorizontalAlign="Center" />
<HeaderStyle BackColor="#FF8000" Font-Bold="True" ForeColor="White" />
<AlternatingRowStyle BackColor="White" />
</asp:GridView>
by the way, it is possible to place somewhere a Row in Gridview? Suppose I have a group item and clicking on Add new and under the clicked row
will be added the new row
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Using a css class
<style type="text/css" media="screen">
.hiddencol
{
display:none;
}
.visiblecol
{
display:block;
}
</style>
To hide / show the columns
<Columns>
<asp:CommandField HeaderText="Edit-Update" ShowEditButton="True" ItemStyle-CssClass="visiblecol"/>
<asp:ButtonField ButtonType="Link" CommandName="Save" ItemStyle-CssClass="hiddencol" />
<asp:BoundField DataField="SkillGroupID" Visible="false" ReadOnly="True" />
<asp:TemplateField>
<ItemTemplate>
<asp:Panel ID="Panel1" runat="server">
<asp:TextBox ID="Txt_Edit" Text='<%#Eval("SkillGroupName") %>' runat="server" Width="60px" ></asp:TextBox>
</asp:Panel>
<ItemStyle CssClass="hiddencol" />
</ItemTemplate>
</asp:TemplateField>
<asp:TemplateField>
<ItemTemplate>
<asp:Panel ID="Panel2" runat="server">
<asp:Label ID="Lbl_Edit" Text='<%#Eval("SkillGroupName") %>' runat="server" Width="60px" ></asp:Label>
</asp:Panel>
<ItemStyle CssClass="visiblecol" />
</ItemTemplate>
</asp:TemplateField>
<asp:TemplateField>
<ItemTemplate>
<asp:ImageButton ID="ImageButton1" runat="Server" ImageUrl="~/Image/Hoch.JPG" CausesValidation="false" CommandName="Up" CommandArgument='<%# Container.DataItemIndex %>' Visible="True" />
<asp:ImageButton ID="ImageButton2" runat="Server" ImageUrl="~/Image/Runter.JPG" CausesValidation="false" CommandName="Down" CommandArgument='<%# Container.DataItemIndex %>' Visible="True" />;
</ItemTemplate>
</asp:TemplateField>
<asp:CommandField HeaderText="Delete" ShowDeleteButton="True" />
</Columns>
then in your RowCommand you can change the 'visiblecol' style by 'hiddencol' and 'hiddencol' by 'visiblecol' like I've posted before
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Please can anyone provide solution to this?
Index was outside the bounds of the array.
Description: An unhandled exception occurred during the execution of the current web request. Please review the stack trace for more information about the error and where it originated in the code.
Exception Details: System.IndexOutOfRangeException: Index was outside the bounds of the array.
Source Error:
Line 137: {
Line 138:
Line 139: lngCaseMasterIDAry[i] = Convert.ToDouble(dr["CaseMasterID"]);
Line 140: strCaseNoAry[i] = dr["CaseNo"].ToString();
Line 141: strCaseBrief[i] = dr["CaseBrief"].ToString();
Source File: e:\CDRV3WebVersion\CaseMaster.aspx.cs Line: 139
Stack Trace:
[IndexOutOfRangeException: Index was outside the bounds of the array.]
CaseMaster.btnView_Click(Object sender, EventArgs e) in e:\CDRV3WebVersion\CaseMaster.aspx.cs:139
System.Web.UI.WebControls.Button.OnClick(EventArgs e) +105
System.Web.UI.WebControls.Button.RaisePostBackEvent(String eventArgument) +107
System.Web.UI.WebControls.Button.System.Web.UI.IPostBackEventHandler.RaisePostBackEvent(String eventArgument) +7
System.Web.UI.Page.RaisePostBackEvent(IPostBackEventHandler sourceControl, String eventArgument) +11
System.Web.UI.Page.RaisePostBackEvent(NameValueCollection postData) +33
System.Web.UI.Page.ProcessRequestMain(Boolean includeStagesBeforeAsyncPoint, Boolean includeStagesAfterAsyncPoint) +1746
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may be the i is greater then the size of array.
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i is initialsize to 0 and array size is set equal to record count?
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Thanks a lot dear i was been initialized before and was not cleared.therefore it was throwing and exception?
Thanks to All.
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 Cheers!!
Brij
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| did you define array "lngCaseMasterIDAry" with required size?Debug it you'll get the problem. Cheers!!
Brij
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array size is set equal to record count?
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Hello Buddies,
I am working on a google map application. I am sending the location to the google api and it returns the latitude and longitude of the location. Then I store it in the database.
My problem google map Map api returns the longitude and latitude for countries etc. But its says place not found if I send some market or some particular location.
Please help me what I have to do.
Thanks..............
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In Google Maps the location which we are searching should be able to traced on the map first.. If the location doesnot exist on the map then it returns error that place not found. I have recently worked on maps where i was able to get the logitude and latitude of places.
Check the address that you are sending to google map API should be correct
NainaNaina
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Hi thanks for your concern.
I tried those locations on GOOGLE Maps and it shows it with no problem. For ex: If I put Starbucks in Google Map, it shows several markers but when I try to use it in my application it says not found.
I am not sure whats wrong that I am doing.
Please help...
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| Can i know the location address which you are trying to locate so that i can give a try? Naina
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Sorry for delay.
I have written over there STARBUCKS.
Please look it
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Why i am getting this error
Microsoft JScript runtime error: Sys.InvalidOperationException: Two components with the same id can't be added to the application. for pop up extender.
I upgraded my ajaxcontrol toolkit and this error is displaying to me.
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By reading the error message it simply seems like you (by mistake) have added a component with an ID that another component already has. Check the Id's of the components and make sure there aren't any duplicates.
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If i am using the old ajax binary which is provided as demo in ajax site, then my code is running fine.
but i cannot use that old binary, because my existing ajax contols complains that blah blah property not found.
Can any body suggest how can i use old and new ajax toolkit binary.
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