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Wheels012 wrote: numbers[i].ToString() == ""
This will always be false.
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How do you check for empty spots (elements?) in a one dimensioal array?
WHEELS
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You can't, an array never has empty spots, it just has entries with the default value, which is 0 (zero) for int. But you can't see the difference between a zero that is there because you never put anything in that place and a zero that you put there.
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Go ahead and univote it. That won't change the truth.
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Some people lack the wisdom to recognize the help they are getting...
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Wheels012 wrote: int[] numbers = new int[1000];
where is this magic 1000 coming from? that is bad code.
Wheels012 wrote: numbers[i].ToString() == ""
and which number will ever have a ToString() result of ""?
the normal approach would be based on a HashSet, not an array.
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I am pretty new to C# and don't know what a HashSet is, but I will look it up. Originally I had the array declaration in the method and set as the numbe rof items on a list, but I thought that would clear the array everytime the method was called.
I believe the find is working well, but I need to load the array with a number (index of list) if it is not currently in there.
WHEELS
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the problem with arrays of integers is, you don't have any "empty" positions, the array initially is filled with zeroes, which could also be valid inputs. the solution is to use some "elastic" collection, that grows when things get added (and even shrinks when things get removed again).
Wheels012 wrote: Originally I had the array declaration in the method ... that would clear the array everytime
correct, whatever you use it should be initialized only once.
Wheels012 wrote: I will look it up
good.
you may learn your code could shrink dramatically...
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Luc Pattyn wrote: HashSet
That's what I was going to suggest as well.
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You can try numbers.Contains(intRnd). Hope this helps.
Good luck!
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I believe my find is working alright, but I have to figure out how to load a number in the array if it is not in there.
WHEELS
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I have an idea of how you can solve you're problem, below are the steps:
Objective: What do we know? We know that you are looking for 2 identical numbers always. If there is only 1 number, then add his duplicate.
Solution:
Supose the number we are looking for his duplicate is X, the first number of the array.
1. sort the array
2. ask for the neighbour of the number X, at right!
if duplicate is at right
increment index to the next X number (skip the duplicate we found!)
else
append the number to the array and repeat step 1
3. repeat until the end of the array.
This is the pseudocode of the solution I've taught.
Hope this helps.
Cheer's,
Alex Manolescu.
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You cannot add to an array. You're going to have to use a list. If you don't know the difference between an array and a list, use google.
.45 ACP - because shooting twice is just silly
-----
"Why don't you tie a kerosene-soaked rag around your ankles so the ants won't climb up and eat your candy ass..." - Dale Earnhardt, 1997
-----
"The staggering layers of obscenity in your statement make it a work of art on so many levels." - J. Jystad, 2001
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John Simmons / outlaw programmer is right!
If you know the number of elements in you're array, you can create an array of dimension = elements x 2 (for the duplicates).
If you don't know the number of elements then you need to use another data structure, for example: a linked list!
Cheer's,
Alex Manolescu.
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Alex Manolescu wrote: you can create an array of dimension = elements x 2 (for the duplicates).
But you would only do that if you're a retard, or completely new at programming.
Alex Manolescu wrote: If you don't know the number of elements then you need to use another data structure, for example: a linked list!
Just use a List<t> object. It lets you add/remove items, and even sort them. Jeeze!
.45 ACP - because shooting twice is just silly
-----
"Why don't you tie a kerosene-soaked rag around your ankles so the ants won't climb up and eat your candy ass..." - Dale Earnhardt, 1997
-----
"The staggering layers of obscenity in your statement make it a work of art on so many levels." - J. Jystad, 2001
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John Simmons / outlaw programmer wrote: Jeeze!
I've just replay my opinion. I've taught I could help to understand better the idea.
No need to involve Jesus here!
Cheer's,
Alex Manolescu.
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Wheels012 wrote: Array.BinarySearch(numbers, 0, numbers.Length, intRnd);
It looks like you're just throwing random numbers (trying to, anyway) onto the end of the array, so how is this supposed to work if numbers is unsorted?
Like others have said, use a List and when adding to it insert items at their proper index to keep it sorted, or use a hash table.
![Badger | [badger,badger,badger,badger...]](https://codeproject.global.ssl.fastly.net/script/Forums/Images/badger.gif)
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I would definitely use a List(dynamic array) for what you want.
List<int> numbers = new List<int>();
private bool RndDuplicate(int intRnd)
{
if (numbers.Contains(intRnd))
return true;
else
{
numbers.Add(intRnd);
return false;
}
}
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way too much code, and too slow for large sets.
HashSet set=new HashSet();
private bool RndDuplicate(int intRnd) {return !set.Add(intRnd);}
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Wow nice one!
Thanks!
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Thank you petercrab.
That is just what I am looking for.
Happy New Year, WHEELS
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Hello everyone.
I want my program to print out the shown table in the DataGridView using a connected printer to the computer.
I've never done such thing.
Formatting is not important, I want to see the table on the printed paper as it is seen.
How is it done? Can anybody help?
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oh thank you this is exactly what I'm looking for
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My quest is simple and I have some ideas, but I wonder if you have a better idea
I have a binary file with some data in it, and I want to modify/replace data from position "x".
I've seen that if I want to modify/replace some data (bytes) from a binary file, I need to replace with the same bytes size.
Now I need a solution to do this.
I taught at a simple solution:
>read the binary file with a handler, and write to a new binary file with another handler
>when reading arrive at my "x" position, I write my own binary data.
My code is shown below:
public void MyWriteMethod()
{
int b;
int x = 153;
Stream str = File.Open("dT.man", FileMode.Open);
Stream strIndex = File.Open("dT.index", FileMode.CreateNew);
BinaryReader br = new BinaryReader(str);
BinaryWriter bw = new BinaryWriter(strIndex);
while ((b = br.BaseStream.ReadByte()) != -1)
{
if (br.BaseStream.Position == x)
{
bw.Write(1);
bw.Write("StringData");
bw.Write("StringData");
bw.Flush();
continue;
}
bw.Write(b);
}
bw.Flush();
bw.Close();
br.Close();
str.Close();
strIndex.Close();
}
Hope there is a better solution, something like seek into the binary file and replace the data. 
Cheer's,
Alex Manolescu.
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