Re: error in 'if' - C# Discussion Boards

lnmca9-Dec-09 0:57

9-Dec-09 0:57

Hi,

Actually i am working on Server Side,the connection requests comes from the Client Side,i can not reconnect to the Client through Socket....
The Server has TCP Listener on its own side,that waits for the Connection Request from the Client and make the Socket after Accepts the request.

Best Regards,
Lalit Narayan

Re: Socket.ReceiveTimeOut Problem

Programm3r9-Dec-09 1:10

Programm3r

9-Dec-09 1:10

As far as my understanding of TCP/IP clients and server(s) goes; it is the client initiates the connection. So, if the client disconnect in any way from the server, when it is the clients 'responsibility' to reconnect to the server.

Kind regards,

The only programmers that are better C# programmers, are those who look like this -> Green Alien | [Alien]

Programm3r
My Blog: ^_^

Re: Socket.ReceiveTimeOut Problem

lnmca9-Dec-09 1:14

lnmca

9-Dec-09 1:14

Hi,
The Client Side Code is written in C at Embeded Side n it takes some time to show the status "Disconnected" this creates the problem 4 me,they find the state of Socket "Connected" while it is disconnected at Server Side...
Plz do the needful.

Thanks and Regards,
Lalit Narayam

Re: Socket.ReceiveTimeOut Problem

Programm3r9-Dec-09 1:21

Programm3r

9-Dec-09 1:21

Well it seems to me that the embedded side needs some works?! Sniff | :^)

lnmca wrote:
The Client Side Code is written in C at Embeded Side n it takes some time to show the status "Disconnected" this creates the problem 4 me,they find the state of Socket "Connected" while it is disconnected at Server Side

You cannot build on something if it is not working correctly.. Dead | X|

The only programmers that are better C# programmers, are those who look like this -> Green Alien | [Alien]

Programm3r
My Blog: ^_^

Re: Socket.ReceiveTimeOut Problem

Paulo Zemek9-Dec-09 2:31

Paulo Zemek

9-Dec-09 2:31

Well, I think you can't do that.
Imagine the situation:

Server starts reading.
Client starts sending. But, for some reason, the connection is VERY slow.
Server then receives the time-out (imagine it does not disconnect).
The server then asks for more data... but, the client is still sending the old-data. So, the server must now wait for what? The old data? The new data? How will it differentiate one data from the other?

I think the fact the connection is closed is on purpose. If you want, I think you may NOT use the ReceiveTimeOut. Instead, create another thread to call "abort" in the reading thread if it takes too long, so the connection will not be aborted, but I don't really know what will happen with the data in this case.

Also, depending on your requirements, it's possible to use UDP to receive the data.

error in 'if'

Muhammad Bilal Saleem Barkati8-Dec-09 23:33

Muhammad Bilal Saleem Barkati

8-Dec-09 23:33

is it a problem of my compiler?

if(((1*1*1)+(64*64*64))==(1*1*1))
        printf("my name");

the printf()is printing "my name".

Re: error in 'if'

N a v a n e e t h8-Dec-09 23:42

N a v a n e e t h

8-Dec-09 23:42

What compiler are you using? I tried with GCC and MSVC. printf is not executing in both places.

BTW, you are on a wrong forum.

Best wishes,
Navaneeth

Re: error in 'if'

Luc Pattyn8-Dec-09 23:47

Luc Pattyn

8-Dec-09 23:47

this does not look like C# code (printf is a C function); if your environment is using 16-bit arithmetic, then 64*64*64 would overflow as it equals 2^18

Smile | :)

Luc Pattyn [Forum Guidelines] [Why QA sucks] [My Articles]

I only read code that is properly indented, and rendered in a non-proportional font; hint: use PRE tags in forum messages

Re: error in 'if'

N a v a n e e t h8-Dec-09 23:56

N a v a n e e t h

8-Dec-09 23:56

I had a similar thought. But will it error out when overflow happens?

Best wishes,
Navaneeth

Re: error in 'if'

Keith Barrow8-Dec-09 23:59

Keith Barrow

8-Dec-09 23:59

This needs to be in the c++ message board, assuming you haven't implmented printf yourself.

I replaced printf("my name") with Console.Out("my name"), and the code worked as expected, its unlikely that the compiler is wrong. Also the code is pretty unreadable, those nested brackets should be factored out.

CCC solved so far: 2 (including a Hard One!)
37!?!! - Randall, Clerks

Deployment Question ..!

CoderOnline8-Dec-09 23:08

CoderOnline

8-Dec-09 23:08

Hi Friends..!

After Deployment of the Application in client system I need to Open an new Microsoft Powerpoint 2007 ..!
How can I achieve it?

Please Help..!

Thank You..!

modified on Wednesday, December 9, 2009 5:24 AM

Insert MenuItem when opening child form

thungphan8-Dec-09 21:32

thungphan

8-Dec-09 21:32

Hi everyone!
I have a MDI app. In parent form, there is a MainMenu that includes MenuItems: (File, Window, Layout). Child form also has a MainMenu including MenuItem(s): (View, Effective). When running app, parent form appears and has menu (File, Window, Layout). Then when opening a child form, I want to insert its menu (View, Effective) and program's menu becomes: (File, View ,Effective, Window, Layout)(Please notice to order!). I use MenuItem and MainMenu class with MergeType, MergeOrder properties not MenuStrip. Please help me! Thank you so much!

problem when connect to sql server

mjawadkhatri8-Dec-09 21:16

mjawadkhatri

8-Dec-09 21:16

hi,
when i connect to sql server give error
Error is
"Cannot open database "PENTIUMD" requested by the login. The login failed.
Login failed for user 'sa'."

i am using blow code

SqlConnection con = new SqlConnection("Data Source=(local); Initial Catalog =PENTIUMD;User ID=sa;Password=java;");

servername=pentiumd
user=sa
password=java

thanks in advance

mjawadkhatri

Re: problem when connect to sql server

Calla8-Dec-09 21:53

Calla

8-Dec-09 21:53

And is "pentiumd" your local machine where you run your code?
What if you change the <cdoe>Data Source=(local) to the actual IP-address?

Re: problem when connect to sql server

puri keemti8-Dec-09 22:14

puri keemti

8-Dec-09 22:14

(1) Check either SQL Login is enabled or not?
(2) Use the Instance name instead of (local) and check the enabled protocols for the same.

How to display notifier for c# console application?

AhmedMasum8-Dec-09 21:09

AhmedMasum

8-Dec-09 21:09

I want a notifier in the system tray for my c# console application.
When I will start my console application it should should notify me and will stay in the system tray. That means in the task bar like antivirus, DAP etc).
I can create it for windows application. But I need help to do it for console application...

Message Closed

8-Dec-09 21:13

stancrm

8-Dec-09 21:13

Message Closed

modified 23-Nov-14 6:56am.

Re: How to display notifier for c# console application?

AhmedMasum9-Dec-09 0:46

AhmedMasum

9-Dec-09 0:46

Thanks a lotz.......

Re: How to display notifier for c# console application?

Luc Pattyn8-Dec-09 23:48

Luc Pattyn

8-Dec-09 23:48

it is exactly the same for console app as for WinForms app.
you may have to include a few using statements (e.g. using System.Windows.Forms) which you get for free when you create a WinForms app.

Smile | :)

Luc Pattyn [Forum Guidelines] [Why QA sucks] [My Articles]

I only read code that is properly indented, and rendered in a non-proportional font; hint: use PRE tags in forum messages

Re: How to display notifier for c# console application?

AhmedMasum9-Dec-09 0:59

AhmedMasum

9-Dec-09 0:59

Actually I tried it without adding the references.
Now this is working fine. thanks.

Re: How to display notifier for c# console application?

AhmedMasum14-Dec-09 21:49

AhmedMasum

14-Dec-09 21:49

I am having another problem after showing the notifier in my console application. I have added context menu. But this is not showing any menu after right click in my notifier. How to solve this???

RSA-SHA1

satsumatable8-Dec-09 20:20

satsumatable

8-Dec-09 20:20

Hi
Can anyone provide me a sample code of RSA-SHA1 algorithm in C#?

Re: RSA-SHA1

SeMartens8-Dec-09 20:50

SeMartens

8-Dec-09 20:50

Hi,

do you want to use the RSA-SHA1 algorithm or do you want to implement it yourself?

For using the cryptography-algorithm take a look here:

http://msdn.microsoft.com/en-us/library/system.security.cryptography.xml.signedxml.aspx[^]

Regards
Sebastian

It's not a bug, it's a feature!

Check out my CodeProject article Permission-by-aspect.

Me in Softwareland.

Re: RSA-SHA1

o m n i8-Dec-09 20:54

o m n i

8-Dec-09 20:54

Public Key RSA Encryption in C# .NET[^]

Re: RSA-SHA1

satsumatable9-Dec-09 0:07

satsumatable

9-Dec-09 0:07

OK... what is the corresponding command/code in C#

PERL

openssl genrsa -out private-key.pem 1024

Thanks

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