ASP.NET

TextBox tb1 = e.item.FindControl("textbox1") as TextBox;
TextBox tb2 = e.item.FindControl("textbox2") as TextBox;
TextBox tb3 = e.item.FindControl("textbox3") as TextBox;

tb1.Attributes.Add("onblur", "javascript:return refreshValue('" + tb2.ClientId + "','" + tb3.ClientId + "');");
tb2.Attributes.Add("onblur", "javascript:return refreshValue('" + tb1.ClientId + "','" + tb3.ClientId + "');");

function refreshValue(operand, target){
  try {
   var value1 = parseInt(this.value);
   var value1 = parseInt(document.getElementById(operand).value);
   document.getElementById(target).value = (value1 + value2);
  }
  catch(err) {
    alert(err.description);
    return false;
  }
return true;
}

ItemTemplate 

ItemDataBound 

<asp:Datalist....OnItemDataBound="Item_Bound" >
<itemtemplate>
<asp:textbox runat="server" id="tb1" />
</itemtemplate>

void Item_Bound(Object sender, DataListItemEventArgs e)
{
   if (e.Item.ItemType == ListItemType.Item || 
             e.Item.ItemType == ListItemType.AlternatingItem)
   {

       TextBox tb1 = e.Item.FindControl("tb1") as TextBox; //same as the control inside Itemtemplate
  }

}

N a v a n e e t h wrote:

Are you looking for deploying an ASP.NET website?

chandra234 wrote:

can we send the data of grid view or datalist view through mail

private void Button1_Click(object sender, System.EventArgs e)
 {
     DataSet BackDataSet = (DataSet) DataGrid1.DataSource;
     string xml = BackDataSet.GetXml();
 }

lrsalunkhe wrote:

How we can do for fast execution the ASP.Net page.