Java

14-Oct-09 8:21

I am not sure whether your question is a concept or an actual implementation either way you already have the list of registered news papers just add a method to the agency class something like broadcast newspaper that takes the news papers names as parameters. In the news papers class you will have a method that listens for the broadcast.

Good luck

[Message Deleted]

s_a_20026314-Oct-09 8:45

s_a_200263

14-Oct-09 8:45

[Message Deleted]

Re: Designing oop

427748014-Oct-09 8:51

14-Oct-09 8:51

What is the scope of the implementation? and include the code you did so that I could analyse and give a solution.

[Message Deleted]

s_a_20026314-Oct-09 9:12

s_a_200263

14-Oct-09 9:12

[Message Deleted]

Re: Designing oop

427748014-Oct-09 11:00

Java Datagrid! [modified]

14-Oct-09 11:00

Classes:

Agency will create 3 Files and append to them:
1. Agency: The name of it
2. AgencyNews: relating agency and news
3. News: the news of the newspaper add optional newspaper name and datetime

Steps:
Newspaper will choose which agency to write the news. The name of the newspaper and the news will be added by the agency to the files.
Agency will broadcast it by simply looping its file and getting the newspapers names then going to the AgencyNews file and locating its news file then loop over the news files and prints out the news to all the newspapers.

Things to look for:
1. Arraylist
2. append to text file
3. File directory and name

The above solution is to store more data rather than calling the methods over and over for every transaction.

This relation is better suited with database.

Hope this helps

Yonathan111114-Oct-09 3:39

Yonathan1111

14-Oct-09 3:39

Hello everybody, Is there such datagrid control in Java like we have in VS? Thank you.

modified on Wednesday, October 14, 2009 9:47 AM

Re: Java Datagrid!

Richard MacCutchan14-Oct-09 5:58

14-Oct-09 5:58

Read this[^] and try this[^].

Re: Java Datagrid!

427748014-Oct-09 8:22

SOA programing interfaces ?

14-Oct-09 8:22

Simple yet effective[^]

Good Luck

thanhle35913-Oct-09 3:48

thanhle359

13-Oct-09 3:48

Hi All..
I have been learning System open architechture programing interfaces. My program used Javascript(the users could used it but they could not modified it).Could someone give me a tutorial.

Thanks

Kim.

Re: SOA programing interfaces ?

427748014-Oct-09 8:23

Re: SOA programing interfaces ?

14-Oct-09 8:23

Clarify your question to get an answer.

thanhle35919-Oct-09 3:02

thanhle359

19-Oct-09 3:02

Could you show me how to capture video screen, or desktop screen using javascript

Sort Array in ascending and descding

nt_virus13-Oct-09 3:33

13-Oct-09 3:33

Hi.

I m running this code.

import java.util.*;
public class Main{
    public static void main(String[] args) {
 int[] value = {2,1,3,6,5};
         System.out.println(value);       // Print unsorted array.
        Arrays.sort(value); // Sort array
        System.out.println(value);       //
    }}

The output is showing..

run:
[I@3e25a5
[I@3e25a5

why is it so.. I m confused.. Please help me. Also please tell me how to do in descending order by user input. Collections class will do with List

Richard MacCutchan13-Oct-09 4:51

13-Oct-09 4:51

nt_virus wrote:
why is it so

You cannot print an array or integers directly in this way. You need to iterate the array and print each individual value after you have converted it to a character string. Take a look at some of the tutorials on the web.

nt_virus13-Oct-09 5:25

13-Oct-09 5:25

thanks I did ascending..

public class Main{
    public static void main(String[] args) {
 int[] value = {2,1,3,6,5};
        System.out.println("Unsorted value");       // Print unsorted array.
        for (int s : value)
            System.out.print(s + " ");
        System.out.println("\n");
        Arrays.sort(value); // Sort array

        System.out.println("sorted value ascending");       // Print unsorted array.
        for (int s : value)
            System.out.print(s + " ");
        System.out.println("\n");      
    }}

please tell how to do descending...

Richard MacCutchan13-Oct-09 6:27

13-Oct-09 6:27

nt_virus wrote:
please tell how to do descending...

Well I guess you need to look at the documentation for the Arrays.sort() method.

nt_virus13-Oct-09 19:16

13-Oct-09 19:16

I read the documentation now, I didn't find descending. There is a way by Comparator .. but its lengthy .. Any other way .. please tell.

Richard MacCutchan13-Oct-09 22:28

13-Oct-09 22:28

nt_virus wrote:
There is a way by Comparator .. but its lengthy .. Any other way .. please tell.

You really think this[^] is lengthy? Or is it the reading of the documentation that's lengthy?

nt_virus13-Oct-09 23:50

13-Oct-09 23:50

I tried that thing earlier but as I declared array as..

int[] value = {2,1,3,6,5}

So this line

Arrays.sort(value, Collections.reverseOrder()); giving error, red line under value, I don't understand why..

But now I declare array as ..

Integer[] value = {2,1,3,6,5}

It works....

/*
 * To change this template, choose Tools | Templates
 * and open the template in the editor.
 */

package SortListOfNumbers;
import java.util.Arrays;
import java.util.Collections;

public class Main{
    public static void main(String[] args)
    {
Sorting srt = new Sorting();
srt.ascending();
srt.descending();
    }
}
 class Sorting{
     public void ascending(){

            int[] value = {2,1,3,6,5};
            System.out.println("Sorting in ascending order");
            System.out.println("Unsorted value");       // Print unsorted array.
             for (int s : value)
               System.out.print(s + " ");
             System.out.println("\n");
             Arrays.sort(value); // Sort in ascending
             System.out.println("sorted value ascending");       // Print unsorted array.
             for (int s : value)
                    System.out.print(s + " ");
             System.out.println("\n");
     }
     public void descending(){

            Integer[] value = {2,1,3,6,5};
            System.out.println("Sorting in descending order");
            System.out.println("Unsorted value");       // Print unsorted array.
             for (int s : value)
               System.out.print(s + " ");
             System.out.println("\n");
             Arrays.sort(value, Collections.reverseOrder());
             System.out.println("Sorted Descending");       // Print unsorted array.
             for (int s : value)
               System.out.print(s + " ");
             System.out.println("\n");
     }}

Please explain why is it happen so.. it bit strange for me.

and thanks a lot.

Richard MacCutchan14-Oct-09 1:08

14-Oct-09 1:08

nt_virus wrote:
Please explain why is it happen so.. it bit strange for me.

Probably because int is a simple type, but Integer is a class. I would suggest reading the Java documentation for a full description of the differences and what methods and interfaces they support.

427748014-Oct-09 8:26

14-Oct-09 8:26

I looked at your code, you need to read the error message which says The method sort(int[]) in the type Arrays is not applicable for the arguments (int[], Comparator < Object > ) so when you added the Integer you are solving the problem that was generated because Integer class wraps a value of the primitive type int in an object. An object of type Integer contains a single field whose type is int.

Richard MacCutchan14-Oct-09 8:41

14-Oct-09 8:41

See further information below from Member 4277480.

nt_virus14-Oct-09 18:47