ASP.NET

Arun Jacob3-Sep-09 19:15

3-Sep-09 19:15

Plz avoid double posting.
Big Grin | :-D

Shahdat Hosain3-Sep-09 19:25

Shahdat Hosain

3-Sep-09 19:25

OK boss, I am highly worried about my problem. But I don't get any answer yet within 9 hours ago.

Plz help me. If it's not beyond your capacity.

shahdat

Abhijit Jana3-Sep-09 19:19

3-Sep-09 19:19

Cross Post will not help you to get answer faster.

Abhijit Jana | Codeproject MVP
Web Site : abhijitjana.net
Don't forget to click "Good Answer" on the post(s) that helped you.

Shahdat Hosain3-Sep-09 19:32

Shahdat Hosain

3-Sep-09 19:32

Yes I will remain later.
Plz answer me

shahdat

Abhijit Jana3-Sep-09 19:32

3-Sep-09 19:32

I have answered. Please check.

Abhijit Jana | Codeproject MVP
Web Site : abhijitjana.net
Don't forget to click "Good Answer" on the post(s) that helped you.

Abhijit Jana3-Sep-09 19:31

3-Sep-09 19:31

I am answering you over here, because, It is better readable than the last one.

MD. SHAHDAT HOSAIN wrote:
but doesn't work for Content2(used for logged in user)

How did you think, its not working ? Are you getting any specific error ? Yor code seems like good. So, give us little bit details on your problem/error .

Abhijit Jana | Codeproject MVP
Web Site : abhijitjana.net
Don't forget to click "Good Answer" on the post(s) that helped you.

Shahdat Hosain3-Sep-09 19:51

Shahdat Hosain

3-Sep-09 19:51

Thanks a lot

No specific error show from compiler. When I click update button, page is partially updated. But progressing message (with Image) never show for a logged in user. Interest that their is no problem for anonymous user.

I tall you again
In my program the Content2 is activated only for logged in user. Is it problem?

shahdat

Image in a gridview

swtlibra3-Sep-09 19:02

3-Sep-09 19:02

i m trying to display the Images in a grid view with refrence to the following article

it is the article if Abhijit Jana on code project

but i m getting the following errors

error: Both DataSource and DataSourceID are defined on 'GridView1'. Remove one definition.

in the following lines

GridView1.DataSource = ds; // give data to gridview
GridView1.DataBind();

can anyone help me ??

Abhijit Jana3-Sep-09 19:17

3-Sep-09 19:17

swtlibra wrote:
it is the article if Abhijit Jana on code project

Yes I am on Code Project . UP and Running Laugh | :laugh:

swtlibra wrote:
error: Both DataSource and DataSourceID are defined on 'GridView1'. Remove one definition.

in the following lines

GridView1.DataSource = ds; // give data to gridview
GridView1.DataBind();

Because, I guess, You are using Two Data Source for GridView1. One From Code Behind. and Another is on ASPX PAge.

As per my article goes, Displaying Image in Gridview from Database[^] There is only one datasource that is created only on CodeBehind.

Remove DataSourceID of GridView From aspx page.

Abhijit Jana | Codeproject MVP
Web Site : abhijitjana.net
Don't forget to click "Good Answer" on the post(s) that helped you.

Arun Jacob3-Sep-09 19:20

3-Sep-09 19:20

Abhijit Jana wrote:
Yes I am on Code Project . UP and Running Laugh

swtlibra found you.lol
Laugh | :laugh:

Abhijit Jana3-Sep-09 19:22

3-Sep-09 19:22

Abhijit Jana | Codeproject MVP
Web Site : abhijitjana.net
Don't forget to click "Good Answer" on the post(s) that helped you.

Arun Jacob3-Sep-09 19:17

3-Sep-09 19:17

swtlibra wrote:
Both DataSource and DataSourceID are defined on 'GridView1'. Remove one definition.

Error is self describing.look at that. Smile | :)

I think you defined DataSourceID in the html.Check your html for GridView and remove that.
Smile | :)

swtlibra3-Sep-09 19:32

3-Sep-09 19:32

when i remove the datasource ID from gridview
it dosen't display the whole grid view Frown | :(

Abhijit Jana3-Sep-09 19:33

3-Sep-09 19:33

swtlibra wrote:
it dosen't display the whole grid view

Show us the code of GriView from aspxpage. And DataBind code from Codebehind page.

Abhijit Jana | Codeproject MVP
Web Site : abhijitjana.net
Don't forget to click "Good Answer" on the post(s) that helped you.

swtlibra3-Sep-09 20:06

3-Sep-09 20:06

<br />
<br />
<asp:GridView ID="GridView1" runat="server" AutoGenerateColumns="False" <br />
            DataKeyNames="Image_ID"  <br />
            AllowPaging="True" onrowdatabound="GridView1_RowDataBound" <br />
            onselectedindexchanged="GridView1_SelectedIndexChanged"><br />
            <Columns><br />
                <asp:BoundField DataField="Image_ID" HeaderText="Image_ID" <br />
                    InsertVisible="False" ReadOnly="True" SortExpression="Image_ID" /><br />
                    <br />
                <asp:TemplateField><br />
                    <ItemTemplate><br />
                        <asp:Image ID="img_1" ImageUrl='<%# Bind("Image_1") %>' runat="server" /><br />
                    </ItemTemplate><br />
                </asp:TemplateField><br />
                    <br />
                <asp:ImageField DataImageUrlField="Image_1"><br />
                </asp:ImageField><br />
                <asp:ImageField DataImageUrlField="Image_2"><br />
                </asp:ImageField><br />
                <asp:ImageField DataImageUrlField="Image_3"><br />
                </asp:ImageField><br />
            </Columns><br />
        </asp:GridView><br />
<br />
<br />
<br />
<br />

<br />
<br />
<br />
using System;<br />
using System.Collections;<br />
using System.Configuration;<br />
using System.Data;<br />
using System.Linq;<br />
using System.Web;<br />
using System.Web.Security;<br />
using System.Web.UI;<br />
using System.Web.UI.HtmlControls;<br />
using System.Web.UI.WebControls;<br />
using System.Web.UI.WebControls.WebParts;<br />
using System.Xml.Linq;<br />
using System.Data.OleDb;<br />
using System.IO;<br />
<br />
public partial class samplepage : System.Web.UI.Page<br />
{<br />
    OleDbConnection con;<br />
    OleDbCommand cmd;<br />
    OleDbDataReader rd;<br />
    OleDbDataAdapter da;<br />
    DataSet ds;<br />
    //Directory.CurrentDirectory;<br />
    protected void Page_Load(object sender, EventArgs e)<br />
    {<br />
        //Directory.CreateDirectory(@"~\Upload\");<br />
        con = new OleDbConnection("Provider=Microsoft.Jet.OLEDB.4.0;Data Source=" + HttpContext.Current.Server.MapPath("App_Data/testdb.mdb"));<br />
        Load_GridData();<br />
    }<br />
<br />
void Load_GridData()<br />
{<br />
con.Open();  //open the connection <br />
OleDbDataAdapter da = new OleDbDataAdapter("select Image_ID, Image_1, Image_2, Image_3 from Images", con);<br />
DataSet ds=new DataSet();<br />
//DataTable table = new DataTable();<br />
da.Fill(ds);   // Fill the dataset <br />
GridView1.DataSource = ds; // give data to gridview<br />
GridView1.DataBind();<br />
    con.Close();<br />
}<br />
protected void GridView1_SelectedIndexChanged(object sender, EventArgs e)<br />
{<br />
<br />
}<br />
protected void GridView1_RowDataBound(object sender, GridViewRowEventArgs e)<br />
{<br />
    if (e.Row.RowType == DataControlRowType.DataRow)<br />
    {<br />
        ((Image)e.Row.FindControl("img_1")).ImageUrl = "'@~/Upload/'" ;<br />
        <br />
    }<br />
}<br />
<br />
<br />

Arun Jacob3-Sep-09 20:14

3-Sep-09 20:14

put a breakpoint at

GridView1.DataSource = ds;

and check if ds is filling correctly with data.

swtlibra3-Sep-09 20:25

3-Sep-09 20:25

ok if we use a simple code then how the image will be displayed using code
through code simple data is displaying in the grid

Arun Jacob3-Sep-09 20:28

3-Sep-09 20:28

swtlibra wrote:
if we use a simple code then how the image will be displayed using code

Give the path of the image as relative url and check if that images existing in the solution.
Smile | :)

swtlibra3-Sep-09 20:33

3-Sep-09 20:33

where to give the path
plz tell about the code

Arun Jacob3-Sep-09 20:40

3-Sep-09 20:40

Instead of
((Image)e.Row.FindControl("img_1")).ImageUrl = "'@~/Upload/'" ;

give something like,
((Image)e.Row.FindControl("img_1")).ImageUrl = @"~/Upload/imagename.jpg" ;
where imagename is the path from object source.
Smile | :)

Abhijit Jana3-Sep-09 20:41

Panel Enabled on checking checkbox

3-Sep-09 20:41

swtlibra wrote:
where to give the path

Image path should be the database column . And physically your image storage location would be hard drive.
When you will retrieve the path from database, image will be load from drive.
The Article, which you have mention above, clearly explained each and every steps. Smile | :)

Abhijit Jana | Codeproject MVP
Web Site : abhijitjana.net
Don't forget to click "Good Answer" on the post(s) that helped you.

haleemasher3-Sep-09 18:19

haleemasher

3-Sep-09 18:19

want to create a Panel in ASP.NET ) with a check box as a header that disables all contained controls when unchecked. How do i so???

Re: Panel Enabled on checking checkbox

Arun Jacob3-Sep-09 18:26

3-Sep-09 18:26

You can do it either by server side code or client side code.If you want to do it in server side use OnCheckedChanged event of checkbox.
Smile | :)