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What you are trying to do goes under the name of Master-Detail. Describing how to do it would take too much space, so it is best if you Google for master detail vb.net or master-detail vb.net you will find lots of examples/tutorials. Choose one that seems to fit your situation most, and have a play.
Henry Minute
Do not read medical books! You could die of a misprint. - Mark Twain
Girl: (staring) "Why do you need an icy cucumber?"
“I want to report a fraud. The government is lying to us all.”
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Thanks alot I will have a research on it.
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I made working dragdrop code, but everytime , when i end the drop (correctly/incorrectly), i end up with a ping sound, under vista.
Anybody else also has this problem ?
It's rather anoying..
Jarno Burger
Video Jockey
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Does anyone have a code snippet that shows how to get a clicked point on a zoomed graphic that corresponds to the same point on the unzoomed graphic?
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Hint , start out by making a function like this :
Function ScalePointAToPointOnLineB(PointOnLineA , LengthLineA , LengthLineB)
And use this trick wisely..
Jarno Burger
Video Jockey
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Thanks for your reply. I have a 42MB image in a user control that is scrollable, and capable of being zoomed out and in. If I click on the image when it is not zoomed I can get the coordinates of the clicked point. The problem is when I zoom in the device coordinates of course change when I click on the exact same spot on the graphic. I know I need to transform a matrix but I don't have much experience with this particular transformation. I would lke to be able to get the same coordinates of the image no matter if it is zoomed in or not, or scrolled. Any ideas regarding matrix transformation using the points.
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Maybe your zoom could be more like a growing/shrinking rectangle instead of a double var ?
Then you could easily find mouse-position relative to your zoom-rectangle.
Then find your zoom-rectangle back in your pic in memory , and you'll have the pixel position.
But you could do this in 10 / 15 ways , all depends what you like yourself most.
But stick to the rectangles in rectangles concept, and only your mouse position as a position (relative to a rectangle to a reactangle to a rectangle to a rectangle etc...).
You'll need that later on , for other drawing stuff too..
Also , using default scrollbar behaviour to scroll a picture to left / right / up / down , first looks like a nice and easy idea.
But you'll end up writing patched stuff to let those scrollbars do what you want , when zoomed or something like that.
First dump the scrollbars. Try to build a drag (with middle mousebutton) first , or use arrow/+/- keys or something. Just for the learning experience.
Jarno Burger
Video Jockey
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Well I dumped the scroll bars and have a panning aspect to scroll - I can pan the graphic and get the proper image coordinates. I have the scale of the horizontal and vertical. I can zoom in and out in many levels at increments of about 10%. As soon as I zoom in the coordinates of course change as they should. But I need the to be able to click the graphic at the exact same spot when zoomed in and receive the same coordinate of the exact same spot when not zoomed in. Here's what I have:
scaleX = CSng(Me.GetScreenRect.Width()) / Me.Width()
scaleY = CSng(Me.GetScreenRect.Height()) / Me.Height()
x = CInt(Math.Round(mouseXY.X * scaleX))
y = CInt(Math.Round(mouseXY.Y * scaleY))
Works fine when not zoomed in. I need the math that would allow for obtaining the same clicked spot while zoomed.
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do you have any control, that you set your zoom level with? You need to get the value of it and use it to compute back your coorinates.
Regards: Didi
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Yes. The mousewheel zooms the image in and out. So if i'm in 10% just reverse the the scale value from 1.1 to .9?
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why not? Just try it out, if it's accurate, I think it should.
Regards: Didi
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I'm making a solitaire game and figured out that the shuffle code doesn't show the Image1(0) card when the cards are shuffled in the design view. So that is one problem. I also am trying to drag and drop images from image1(0) to 12 from the left hand side of the design view to the right hand side where hearts(0) cards are. One thing, the hearts cards already have other bitmaps on them; they are blank boxes to show up for the person playing to automatically drop the image1 card in that slot. Here's what my newbie experience is so far...Oh, I also made tags in the design view to think they might help out.
Public Sub Main()
Start_Game.Show
End Sub
Private Sub Exit_Click()
MsgBox ("Thank you for playing. Good Bye.")
End
End Sub
Private Sub Start_Click()
Dim arrDeck(52)
Randomize
Dim Cardcount As Integer
Dim Counter As Integer
Dim Card1 As Integer
Dim Card2 As Integer
' Fill deck with cards in order 1 to 52
Do While Cardcount <= 52
arrDeck(Cardcount) = Cardcount
Cardcount = Cardcount + 1
Loop
' Shuffle the deck - end value (100)
Dim Temp As Image
Dim Index As Integer
For Index = 0 To 51
For Counter = 0 To 100
Card1 = Int(51 * Rnd)
Card2 = Int(51 * Rnd)
If (Card1 <> Card2) Then
Temp(Index).Picture = Image1(Card1).Picture
Image1(Card1).Picture = Image1(Card2).Picture
Image1(Card2).Picture = Temp(Index).Picture
End If
Next Index
Next Counter
' Now output images in order
For Counter = 0 To 51
Image1(Counter).Visible = True
Next Counter
End Sub
Private Sub Hearts_DragDrop(Index As Integer, Source As Control, X As Single, Y As Single)
Private Sub Image1_Click(Index As Integer)
If Image1(Index).Tag = Hearts(Index).Tag Then
Image1(Index).Picture = Hearts(Index).Picture
Hearts(Index).Picture = Source.Picture
Image1(Index).Visible = False
End If
Next
End Sub
End Sub
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Here is one problem:
Card1 = Int(51 * Rnd)
This will give you a random number with 51 possible values, i.e. from 0 to 50. That means that you are never touching the last card in the deck.
You are doing 100 times as much work as you need to in order to shuffle the deck. You don't have to make more than 51 swaps to completely shuffle the deck, you just have to make sure that each card has an equal chance to be swapped into each position in the deck:
For card1 = 0 To 50
card2 = card1 + Int((52 - card1) * Rnd)
If card1 <> card2 Then
Temp = Image1(card1).Picture
Image1(card1).Picture = Image1(card2).Picture
Image1(card2).Picture = Temp
End If
Next Index
Despite everything, the person most likely to be fooling you next is yourself.
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Thank you for your comment, however, I did try 0 to 50 and 52 *RND first; It still has the same effect. I lose the Image1(0) card; the King of Hearts. If I use Temp as an Image for tghe shuffle it does not work. Says it is not a proper variable or is not set as one ; I try set command and that doesn't work. I try Image1(0).Picture in place of temp and I lose the King of Hearts card too of course; hence Image1(0). How do I shuffle the images with using a third variable for the shuffle correctly and not lose any cards at run time at display of images? Much appreciation in advance.
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maybe you'll have to use a clone ?
Jarno Burger
Video Jockey
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You know, maybe that's the key; I'll try that and let y'all know. Thanks.
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Well, that was it! Thank you for the suggestion. I made a clone, made it invisible and used it in the swap, like this:
f (posn1 z<> posn2) Then
KingH(0).Picture = Image1
posn1).Picture
Image1(posn1).Picture = Image1(posn2).Picture
Image1(posn2).Picture = KingH(0).Picture
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yeah ! cool !
whahoo ! we solved it !
Jarno Burger
Video Jockey
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Yep we did; thanks!
I have another question. Trying to move the image1(12) card (drag and drop) to the hearts(12) card. Testing to see if the tags are equal first, which they are set in design view, then setting the same image bitmap of image1(12) card over (dropped on) the blank image of hearts(12) card. What happens at run time is ALL the cards 0 - 12 of image1 can only be dropped in hearts(12) spot. None of the other cards in the image1 stack (up to 52, remember, I'm just doing a sample first) can be dropped over the hearts cards, but no "shirley" error message pops up either. Any suggestions?
Pardon the format; just testing now
'Private Sub Image1_DragDrop(Index As Integer, Source As Control, X As Single, Y As Single)
'Image1(Index).Picture = Source.Picture
'End Sub
Private Sub Hearts_DragDrop(Index As Integer, Source As Control, X As Single, Y As Single)
'Dim ImageIndex As Integer
Dim HeartsPic0 As Image
HeartsPic0.Picture = Source.Picture
Source.Picture = LoadPicture("C:\Program1\013h.gif")
If Image1(12).Tag = Hearts(12).Tag Then
Hearts(12).Picture = HeartsPic0.Picture
Else
MsgBox ("You're wrong Shirley")
Exit Sub
End If
End Sub
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.tag is normally object. comparing object with object sometimes work. but to be sure , do a ctype(image(x).tag , string/integer/double/your class type ) first. Your watch window in visual studio does some neat tricks to show you what is in the tags. But the bad thing is , that your code doesn't know, only that watch-window does (thats called reflection).
You have to "convert the object back to your type of class"->ctype(thingie , class-type) . Just to make sure your tag is ok.
And maybe Debug.WriteLine all the tag info constantly to your debugger window. Maybe something goes wrong somewhere else , working with tags , (that could behave like any object) , can be tedious.
In your case , are your tags your game-data , or are there other array's of stuff with game-data ? Try to make a mental split-up of game-data and interface. Build a 'huge' game-data class .
You'll add / remove / update /load / save / (de)serialize your gamedata. In that way , maybe in the future you only have to type in the intermediatewindow or debugwatcher :'gamedata.show' , to show all the gamedata in one list in the debugwindow or debugwatcher.
Later in the future you can remember multiple "states" of gamedata , to have a undo/replay function.
Jarno Burger
Video Jockey
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Hi.
I have a textbox that is constantly updated line by line from a process.startinfo... thingy. The text pasted in the textbox is actully console application output.
What i need is a string variable that always holds the last line from the textbox when its updating (new lines are added).
Does anyone know how i can do that?
http://www.themightyatom.nl
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Hi,
assuming your other process is outputting lines of text (lines separated by NewLine) then it isn't very wise to (1) concatenate all of them since that is what a TextBox needs, and (2) then try to find the last line again.
For starters, remember the most recent line where it comes in (maybe in a Process.OutputDataReceived handler?) i.e. before it gets concatenated; and then maybe drop the Textbox, i.e. if you are not relying on the wrapping capabilities of a textbox, then use a ListBox instead. It is both easier and faster.
Luc Pattyn [Forum Guidelines] [My Articles]
The quality and detail of your question reflects on the effectiveness of the help you are likely to get.
Show formatted code inside PRE tags, and give clear symptoms when describing a problem.
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Well, the process that im running is a compilation process with its output redirected to a textbox, and i'd like to use regular expressions later to colorize error and warning messages.
I already have a sub that is fired when a new line is added to the textbox, i just need a string variable to hold the last pasted line. I need to compare something. Its hard to explain, unless you know what level design for the game Half-Life is all about...
Ill experiment with a listbox.
http://www.themightyatom.nl
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Hi,
if your ListBox output needs some formatting, then you have to paint the content yourself: switch its DrawMode to one of the "OwnerDrawn" values and provide a DrawItem handler, wich can be as simple as
public void lb_DrawItem(object sender, DrawItemEventArgs e) {
ListBox lb=sender as ListBox;
int index=e.Index;
if (index<0 || index>=lb.Items.Count) return;
string s=(string)lb.Items[index];
e.DrawBackground();
g.DrawString(s, font, brush, e.Bounds);
}
assuming each line uses a single format (you need to provide some font and brush; if you create them inside the DrawItem handler, don't forget to dispose them too).
BTW: one nice characteristic of the ListBox is it only calls DrawItem for the lines that are actually visible, so when thousands of lines are present, but only 25 or so are visible at any given time, only those 25 will fire the DrawItem colorization and painting.
Luc Pattyn [Forum Guidelines] [My Articles]
The quality and detail of your question reflects on the effectiveness of the help you are likely to get.
Show formatted code inside PRE tags, and give clear symptoms when describing a problem.
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