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Under Windows 7, the design of the tray notification area is different from Windows Vista and XP. It provides the settings of "Show icon and notification", "Hide icon and notification", and "Only show notification" for each icon. Except the system built-in icons set as "Show icon and notification", all the other icons are set as "Only show notification" by default.
If a systray application is intended to launch with the property "Show icon and notification" programmatically, how to do that? Is it done by modifying some registry key? Or done by adding some flags in the source code?
Thanks!
Maxwell Chen
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This page[^] says this:
There have been changes to the notification area that give the user much more control over what icons appear on the taskbar. All notification icons are now hidden by default and that visibility cannot be programmatically controlled. Only the user is allowed to choose which notification icons appear on the taskbar.
That makes sense to me...
Java, Basic, who cares - it's all a bunch of tree-hugging hippy cr*p
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Thank you very much for your great information, Stuart! 
Maxwell Chen
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If I need to set this programatically using c#.
How can I do this????
(or even show a user a message box to remind him the option of displaying the icon and clicking ok will show the icon)
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I used to be able to check which version of IE was installed on the machine my application was running on by calling "DllGetVersion" on "shdocvw.dll". This may not have been the orthodox way to have done this but it appeared to work for a while until IE 7 came along.
Specifically, the problem is the version reported is still 6.0
Does anyone know how to check which version of IE is installed on the machine that is compatible with IE Version 5, 6, 7, 8, etc... ?
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bob16972 wrote: Does anyone know how to check which version of IE is installed on the machine that is compatible with IE Version 5, 6, 7, 8, etc... ?
Have you looked at the values in HKLM\SOFTWARE\Microsoft\Internet Explorer?
"Old age is like a bank account. You withdraw later in life what you have deposited along the way." - Unknown
"Fireproof doesn't mean the fire will never come. It means when the fire comes that you will be able to withstand it." - Michael Simmons
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I looked at the keys within that key but not at the values of it. Now I see them.
thanks for the help.
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when I build a dynamic library with mingw32 in windows xp sp en, i can find libsh.a.
the file i write is blow:
//----------------------
// sh.h
#ifndef SH_H
#define SH_H
#ifndef EXPORT
//#define EXPORT
#define EXPORT __declspec(dllimport)
#else
#undef EXPORT
#define EXPORT __declspec(dllexport)
#endif // EXPORT
void EXPORT show();
/* */
class EXPORT CTestClass
{
public:
CTestClass();
virtual ~CTestClass();
virtual void Show();
};
#endif // SH_H
//--------------------------
// sh.cpp
#include "sh.h"
#include <iostream>
void show()
{
std::cout << "show" << std::endl;
}
void CTestClass::Show()
{
std::cout << "CTestClass::Show" << std::endl;
}
CTestClass::CTestClass()
{
std::cout << "CTestClass::CTestClass" << std::endl;
}
CTestClass::~CTestClass()
{
std::cout << "CTestClass::~CTestClass" << std::endl;
}
//------------------------
//makefile
#here is mingw32 tdm 4.3.3,
CXX=g++
LD=ld
.PHONY: all clean
all:
$(CXX) -DEXPORT sh.cpp -c -osh.o
$(CXX) -shared sh.o --output-def=sh.def --out-imp=liblibsh.a -osh.dll
@echo %cd%
clean:
//-----------end of all ----------------
i can find libsh.a in current directory!!!
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zarelaky wrote: $(CXX) -shared sh.o --output-def=sh.def --out-imp=liblibsh.a -osh.dll
Is it because you've got liblibsh.a in the command line?
Java, Basic, who cares - it's all a bunch of tree-hugging hippy cr*p
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Some quick Googling would have shown you this page[^], which shows that your linking command is wrong - this line
$(CXX) -shared sh.o --output-def=sh.def --out-imp=liblibsh.a -osh.dll
should be
$(CXX) -shared sh.o -osh.dll -Wl,--output-def=sh.def,--out-implib=liblibsh.a
but your import library still won't be called libsh.a - can you guess why?
Java, Basic, who cares - it's all a bunch of tree-hugging hippy cr*p
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Oh ! I know!
In my command line,the options are not passed to ld by g++.
The import library name is "liblibsh.a".
My english not well, 3Q for you answer !
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Hi,
I have a problem using wofstream for writting Unicode files
I have written the code below but the result is nothing(The file is empty) what should I do?
<br />
#include <fstream><br />
#include <string><br />
using namespace std;<br />
int main(){<br />
<br />
wstring t;<br />
t.push_back(1575);<br />
t.push_back(1605);<br />
t.push_back(1740);<br />
t.push_back(1585);<br />
<br />
wofstream of(L"C:\\a.txt",std::ios::ate | std::ios::binary);<br />
wchar_t BOM = 0xFEFF;
of << BOM;<br />
of << t;<br />
of.close();<br />
<br />
return 0;<br />
}<br />
<br />
</string></fstream>
I am using Visual Studio 2008 SP1 IDE for Compiling
modified on Tuesday, April 21, 2009 2:30 PM
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Wide file streams in C++ actually (by default) write single byte characters to files (see this Google groups posting[^] for details). The characters you've provided aren't convertible into your default codepage, so it's game over!
I believe that if you imbue[^] your file stream with a locale[^] that has a codecvt facet[^] that converts to some Unicode encoding, then you'll get proper wide character files.
In fact, this code (which uses the appropriate codecvt facet from this CP article[^]) will do just that!:
#include <iostream>
#include <fstream>
#include <string>
using namespace std;
#include <locale>
using std::codecvt ;
typedef codecvt < wchar_t , char , mbstate_t > NullCodecvtBase ;
class NullCodecvt
: public NullCodecvtBase
{
public:
typedef wchar_t _E ;
typedef char _To ;
typedef mbstate_t _St ;
explicit NullCodecvt( size_t _R=0 ) : NullCodecvtBase(_R) { }
protected:
virtual result do_in( _St& _State ,
const _To* _F1 , const _To* _L1 , const _To*& _Mid1 ,
_E* F2 , _E* _L2 , _E*& _Mid2
) const
{
return noconv ;
}
virtual result do_out( _St& _State ,
const _E* _F1 , const _E* _L1 , const _E*& _Mid1 ,
_To* F2, _E* _L2 , _To*& _Mid2
) const
{
return noconv ;
}
virtual result do_unshift( _St& _State ,
_To* _F2 , _To* _L2 , _To*& _Mid2 ) const
{
return noconv ;
}
virtual int do_length( _St& _State , const _To* _F1 ,
const _To* _L1 , size_t _N2 ) const _THROW0()
{
return (_N2 < (size_t)(_L1 - _F1)) ? _N2 : _L1 - _F1 ;
}
virtual bool do_always_noconv() const _THROW0()
{
return true ;
}
virtual int do_max_length() const _THROW0()
{
return 2 ;
}
virtual int do_encoding() const _THROW0()
{
return 2 ;
}
} ;
int _tmain(int argc, _TCHAR* argv[])
{
wofstream of("./a.txt",std::ios::out | std::ios::binary);
std::locale l( std::locale(), new NullCodecvt);
of.imbue( l ) ;
of << "Hello";
of.close();
return 0;
}
Java, Basic, who cares - it's all a bunch of tree-hugging hippy cr*p
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thank you for your help,now my program works fine.
But because I am new to c++, I can't understand the [the article] or the class NullCodecvt well!
Would you mind explain that more ?
What should I do to recognize if a file is UTF-8 or UTF-16 or some other locales, When reading the file.
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C++ treats a disk file as a stream of bytes (makes sense really). The codecvt converts each char (for ofstreams) or wchar_t (for wofstreams) to bytes. This codecvt facet just converts wchar_t (as it's for wofstream) to two bytes (i.e. UTF-16, or UCS-2, whichever encoding Windows Unicode files use) which then get written out to disk.
Amir_m wrote: What should I do to recognize if a file is UTF-8 or UTF-16 or some other locales, When reading the file.
I've got no idea - sorry!
Java, Basic, who cares - it's all a bunch of tree-hugging hippy cr*p
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Thank You for your explanation.
for an application to recognize a file encoding there were some articles in MSDN
[articles in MSDN] which says: The preferred place to specify byte order is in a file header, but text files do not have headers. Therefore, Unicode has defined a character (U+FEFF) and a noncharacter (U+FFFE) as byte order marks. They are mirror byte images of each other.
and then continues: When an application finds U+FEFF at the beginning of a text file, it typically processes the file as a Unicode file, although it can also perform further heuristic checks to verify that this is true. Such a check can be as simple as testing to find out if the variation in the low-order bytes is much higher than the variation in the high-order bytes. For example, if ASCII text is converted to Unicode text, every second byte is zero. Also, checking both for the linefeed and carriage-return characters (U+000A and U+000D) and for even or odd file size can provide a strong indicator of the nature of the file.
When an application finds U+FFFE at the beginning of a text file, it interprets it to mean that the file is a byte-reversed Unicode file. The application can either swap the order of the bytes or alert the user that an error has occurred.
But there is question of which method to use at the begining of reading a file for recognition,
do we ought to use a special sequense or sth else ...
if there is any one who has experiences about the case please replay the matter, and if there is some codes about this (that makes the job easy) please let us khnow that.
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I'd probably map the file[^], then use IsTextUnicode[^] to decide what encoding it was.
Java, Basic, who cares - it's all a bunch of tree-hugging hippy cr*p
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Thank you good suggestion,Of course my mean was to do the things by pure STL methods.
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Just wanted to check whether the code here in VerifyMaterial() is correct, it works, but as I learned from my last post that doesn't necessarily mean it is correct. I searched google for information but couldn't find anything specific, however any info I found seemed to be against a cast from DWORD to int.
BasicMaterial::BasicMaterial()
{
Ambient = NULL;
Diffuse = NULL;
Specular = NULL;
}
BOOL BasicMaterial::VerifyMaterial()
{
if (!(int)Ambient || !(int)Diffuse || !(int)Specular)
return false;
return true;
}
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Mikey_H wrote: Just wanted to check whether the code here in VerifyMaterial() is correct
To be able to verify that, we need to know what you are trying to do...
Anyway, the cast is not necessary here because a DWORD is an unsigned long. Thus checking if it is null doesn't require you to cast it to an int.
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I want to check to see if the DWORDs have been set from an outside class.
I had originally tried it without the cast, but that did not work.
typedef DWORD D3DCOLOR;
It is actually a D3DCOLOR but I assume the same rules apply?
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Mikey_H wrote: I want to check to see if the DWORDs have been set from an outside class.
And what if they are set as 0 ? The only thing you can verify is check if they are different than 0.
Mikey_H wrote: but that did not work.
Which means what exactly ?
Anyway, if I have to check for if a value is different than zero, I use this notation: if (myValue!=0), which is a bit clearer (just a matter of taste).
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I've tried again without the cast
if (!Ambient || !Diffuse || !Specular)
return false;
which is working, I obviously didn't have it set up how I thought I did at first.
Checking to make sure value is not 0 is fine, I just want to see if it has been "attempted" to be set, the variables will hold color values so they should not be 0 once set (I think).
Thank you for your help Cedric
modified on Tuesday, April 21, 2009 1:23 PM
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By the way, your code returns false if one of the values is different than 0, is that what you want ? I would guess you want the opposite no ?
Also, with numerical values, it is a bit clearer to consider them as numerical values, not boolean. Logically, it doesn't make any difference but it makes the code a bit more understandable (you want to check that the value is different than 0).
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