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Here's a possible solution.
Note that I have not Dimmed all the variables.
It's a classic way to do shuffling of card decks.
Private Sub Start_Click()
Dim arrDeck(52)
Randomize
' Fill deck with cards in order 1 to 52
CardCount = 1
Do While CardCount <= 52
arrDeck(CardCount) = Cardcount
CardCount = CardCount + 1
Loop
' Shuufle the deck - end value (100) could be anything, bigger it is the more shuffled deck is
Counter = 0
Do While Counter <= 100
' Get two random card positions
card1 = Int((52 * Rnd) + 1)
card2 = Int((52 * Rnd) + 1)
' Swap cards at these positions
tmpCard = arrDeck(card1)
arrDeck(card1) = arrDeck(card2)
arrDeck(card2) = tmpCard
Loop
' Now output immages in order of deck
CardCount = 1
Do While CardCount <= 52
Subnum = arrDeck(CardCount)
Image1(Subnum).Visible = True
CardCount = CardCount + 1
Loop
End Sub
Regards
David R
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I went to compile this code in MS VB and it rejected as Compile Error all the values that were not dimmed....any ideas why? Thanks in advance.
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Hmm, seems to compile, but when I click the start button, the program hangs....any ideas?
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Not without seeing the actual code you did and where it is called. I don't think there's anything in it that should cause a hang.
I did not Dim all the variables because I was not sure what you had already declared.
Obviously they need to be Dimmed somewhere.
Regards
David R
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' I x'd out the lines to show what I am trying to do...
Option Explicit
Public Sub Main()
Start_Game.Show
End Sub
Private Sub Exit_Click()
MsgBox ("Thank you for playing! Good bye")
End
End Sub
Private Sub Start_Click()
Dim arrDeck(52)
Randomize
Dim Cardcount As Integer
Dim Counter As Integer
Dim Card1 As Integer
Dim Card2 As Integer
'Dim CardVal As Integer
'Dim SubNum As Integer
' Fill deck with cards in order 1 to 52
Cardcount = 1
Do While Cardcount <= 52
arrDeck(Cardcount) = Cardcount
Cardcount = Cardcount + 1
Loop
' Shuffle the deck - end value (100)
Counter = 0
Do While Counter <= 100
' Get two random card positions
Card1 = Int((52 * Rnd) + 1)
Card2 = Int((52 * Rnd) + 1)
' Swap cards at these positions
Tmpcard = arrDeck(Card1)
arrDeck(Card1) = arrDeck(Card2)
arrDeck(Card2) = Tmpcard
'CardVal = Tmpcard ? Looking for a single value out of the random cards you made...
Loop
' Now output images in order of deck
Cardcount = 1
Counter = 0
' It seems I need a counter in here for Subnum, 0-52 so it can display the cards from 0-52 slots,
' But the array of a single value out of the random cards you made need to be set to another counter,
' Right? I'm not sure...I x'd out the lines to show what I meant...
'Do While Cardcount <= 52 And Counter < 53
'If arrDeck(CardVal) = -1 Then
' arrDeck(CardVal) = Cardcount
'Image1(Cardcount) = CardVal
' Subnum = Counter
'Image1(Subnum).Visible = True
Cardcount = Cardcount + 1
'Counter = Counter + 1
' End If
Loop
End Sub
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I'm not sure why you need all the counters. Your Counter is always one less than Cardcount so is effectively redundant. In Do While Cardcount <= 52 And Counter < 53 both parts of the condition will have same logical value.
What is Image1() - it looks like an array but has a Visible property.
And this line implies that it is an array of integer: Image1(Cardcount) = CardVal
In any case here's a new version of the code that shuffles the images directly.
You would need to Dim tmpImage as an appropriate type.
To get a single random image after shuffling you could just use Image1(1) i.e. the top of the pack; or you could use tmpImage.
Private Sub Start_Click()
Randomize
'Dim tmpImage As ????
Dim card1 As Integer
Dim card2 As Integer
Dim counter As Integer
' Shuffle the images - end value (100)
Counter = 0
Do While Counter <= 100
' Get two random image positions
card1 = Int((52 * Rnd) + 1)
card2 = Int((52 * Rnd) + 1)
' Swap images at these positions
tmpImage = Image1(card1)
Image1(card1) = Image1(card2)
Image1(card2) = tmpImage
Loop
' Now output images in order
counter = 1
Do While counter <= 52
Image1(counter).Visible = True
counter = counter + 1
Loop
End Sub
What version of VB are you using? I'd assumed VB.NET but I can't see where Image1() would fit in. But, IIRC, in VB6 there is an Image control (not used VB6 for about 5 years).
EDIT: forgot to Dim counter 
Regards
David R
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Ok, sure then, I can just pass the images through directly...then having overkill of counting. I see now. Thanks.
As far as the version, perhaps this would be good to ask this question also, I'm using VB6 because that's all I have. It costs for VB.NET right? Not sure. I'm doing a specific game for my Mom, that's why I haven't upgraded am just using an older version.
Images() was the visual image of the card I created on the form.
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Glad to be of some help - my VB6 is a bit rusty but I should have spotted the use of Image1()
You'll probably find that Dave K's solution won't work - it's .NET stuff.
You can download VB.NET Express editions for free. There's two versions - 2005 and 2008. Probably best to go for 2008. Worth looking into. You can see what's available at http://www.microsoft.com/express/[^]
Regards
David R
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Ok, I set tmpImage to As Image, is that correct? Then would I have the change the last few lines to reflect
Do While Counter <= 52
Image1(TmpImage).Visible = True
Counter = Counter + 1
Loop
If so, gives an error like object variable or with block variable not set
debugs on TmpImage = Image1(Card1)
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If tmpImage is an Image (it has to be whatever is in Image1() so what type of object does Image1() store?) then you can't use it as an index to Image1().
Using counter as the index will make all the images visible.
I don't have VB6 running anymore so I'm relying on memory.
Regards
David R
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Image1() stores an array... 0-52, was created automatically when I set up the cards on the form.
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It must be an array of something - the same type as the cards?
Can yo see the code that fills the array? That should tell you what the type is.
As an alternative, you could try Dimming tmpImage As Variant - that would allow it to hold anything. But you still can't use it as an index into the array.
Regards
David R
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It's an array of images, as in I click on one of the images on the form and it states image1(0) Image
That's what it states, so I should set tmpImage to Image, but it still produces the same error.
Should I try a third integer variable to use with tmpImage, as in tmpImage(Card3) and have Card3 be a random number?
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Should I dim tmpimage as image and set it using a set statement to an array of an index? or integer?
How would I do that?
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I'd forgotten you need to use Set when dealing with 'objects - mea culpa.
So in the shuffle loop you need this:
Set tmpImage = Image1(card1)
Set Image1(card1) = Image1(card2)
Set Image1(card2) = tmpImage
tmpImage must be of the same type as whatever the Image1() array holds (or it could be Variant). It can't be an Integer nor an array of anything. All it's used for is to allow items in the Image1() array to be swapped. It has no other use in the code.
How many images do you want to display at once? If you only want one then the second loop is not needed. You could just do something like Image1(1).Visible = True to display the first image.
Regards
David R
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Ok, great! I had to put in counter + 1 though for it to partially work...
Set tmpImage = Image1(Card1)
Set Image1(Card1) = Image1(Card2)
Set Image1(Card2) = tmpImage
Counter = Counter + 1
Loop
But also, it doesn't show the first card; tried changing counter to equal 0, but didn't help; any ideas?
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Can't believe I made such a blunder  - but it's because I would normally use a For loop like so (and I'm writing the code in Notepad so no help from the editor ).
For counter = 0 to 100
' Get two random image positions
card1 = Int((52 * Rnd) + 1)
card2 = Int((52 * Rnd) + 1)
' Swap images at these positions
Set tmpImage = Image1(card1)
Set Image1(card1) = Image1(card2)
Set Image1(card2) = tmpImage
Next counter
Then I don't have to increase counter, the loop does it for me. Note that counter is just counting the numbers of swaps done - it has nothing to do with the number of images it could be set to do 1000 or whatever you like.
All this loop does is shuffle the images. It does not display them in any way - that's down to the Image1(x).Visible = True where x is the number of the image you want to display.
Not sure why it's not displaying. You might try refreshing the the form (i.e add Form.Refresh or a DoEvents after setting Image1(1).Visible = True.
Regards
David R
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No problem; you'll always be smarter at this than me. Anyhow, I'll try refreshing the form then. Thanks so much!
Yvonne
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Not necessarily smarter - probably just more experienced (been doing this more years than I care to remember  )
I'm off to bed in a little while so if there's anything else you have a query with I'll reply sometime tomorrow.
Regards
David R
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Hello,
Well it still shows two of a kinds after the shuffle. I've tried various things with While and Do nested loops and same with If Then EndIf, but nothing seems to work...I'm trying though. Any ideas?
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I'm not sure what the program is supposed to do so not sure why it's not working.
Can you tell me what the form looks like (e.g. how many image controls it displays)?
What should happen when the Start button is clicked (I assume Start is a button)?
Should it display one card or more than one?
Regards
David R
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Well, it is displaying all the cards 4 across and 13 down in full suits w/out jokers, of course. Then when the cards are random and shuffled, they should display the same amount of cards in same positions, but random ones. What happens when I compile and run the program, is that more of one of the same cards are displayed, thus showing not totally random cards. Somehow, I'm thinking Card1 should not equal Card2 from the random procedure, then the cards are shuffled, and then distributed out....but there is no code that shows Card1 should not equal to Card2 at all, for to be randomly displayed. Any ideas? Thank you.
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So you have 52 Image1() controls and want to display the deck in them?. Do the indexes for the controls go from 1 to 52 or from 0 to 51? You should be able to find that from the properties in the designer. Depending on whether it's 0-51 or 1-52 there could be a simple solution.
How do the Image1() controls get filled with pictures when the program starts up? Is there any code that fills them (probably in Form_Load event if there is)? Or did you set them in the designer?
I managed to dig out an old machine that still had VB6 on and had a little play - frightening how much I'd forgotten about Image controls!
Regards
David R
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Firstly, I would like to thank you for being so cool for helping me on this project. I truly appreciate it.
As far as the image1() controls, they were created in the design page all lined up with different bitmaps representing them. Then the first image card would be image1(0) to image1(52) for the final card. Wait a second....just came back to reading this and realized in the designer the first card of the array is 0, then the final card is labeled 52. Isn't it supposed to be 51? Why is it doing that....it looks like I set up the suits perfectly in order.....
No specific code that fills the array of images, just designed in designer form and added that way. Thought that would be easier, but perhaps there is a disadvantage of doing it that way?
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It looks like you have missed an index somewhere. The only way to find out is to go through them one by one.
The reason I asked was that I thought if the indexes go from 1 to 52 you could have an Image1(0) that can be made invisible (you could do this in the Form_Load event, and it wouldn't matter where it is on the screen). You could then use this in the shuffle instead of tmpCard when doing the swap. That way you know it is the correct type.
So you could have something like this for swapping:
If (card1 <> card2) Then
Image1(0).Picture = Image1(card1).Picture
Image1(card1).Picture = Image1(card2).Picture
Image1(card2).Picture = Image1(0).Picture
End If
In your loop I'd avoid using the goto, you need something like:
For counter = 1 to 100 'Do 100 swaps to shuffle deck
'do the shuffling here
Next counter
A disadvantage of setting the bitmaps in the designer is that it would be tedious to set the images to use a different set of cards (but that probably isn't a worry). Another one is you have to make sure you don't have gaps in the indexes and it looks like you have a gap (else the indexes would be 0 to 51).
Because of the way card1 and card2 are calculated they will be between 1 and 52 so your indexes for Image1() need to be in the same range. This avoids having to do -1 somewhere to get the correct range (in fact you could just drop the +1 when calculating card1 and card2 instead of using -1).
Regards
David R
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