Re: why button_click event raising 2 times? - C# Discussion Boards

musefan31-Mar-09 3:54

31-Mar-09 3:54

Gonna have to see some code to help with this one

Life goes very fast. Tomorrow, today is already yesterday.

Narendra Reddy Vajrala31-Mar-09 3:57

31-Mar-09 3:57

private void BtnOk_Click(object sender, EventArgs e)
{
if (TxtTotMins.Text != TxtUCmins.Text)
return;

DateTime dt = Convert.ToDateTime(System.DateTime.Now.ToString());
DateTime Wo_dt = Convert.ToDateTime(System.DateTime.Now.ToShortDateString());
DateTime mod_time=Convert.ToDateTime(System.DateTime.Now.ToLongTimeString());
string QueueId = ClientInfo.Application + "!" + Wo_dt.ToShortDateString() + "!" + TransId;
string Upload = "N";

for (int i = 1; i <= OeCnt; i++)
{
string[] Level1 = OeControl[i].Level2.Tag.ToString().Split(':');
string Level1Code = Level1[1].ToString();
string Level2Code;
string Level3Code;

if (!(string.IsNullOrEmpty(OeControl[i].Level2.Text)))
{
string[] Level2 = OeControl[i].Level3.Tag.ToString().Split(':');
Level2Code = Level2[1].ToString();
}
else
Level2Code = null;

if (!(string.IsNullOrEmpty(OeControl[i].Level3.Text)))
{
string[] Level3 = OeControl[i].Level1.Tag.ToString().Split(':');
Level3Code = Level3[1].ToString();
}
else
Level3Code=null;

string Timespent=OeControl[i].TimeText.Text;

string Query = string.Format(@"insert into SIS_OEE(T_STAMP,oper,L2_Code,L3_Code,L4_Code,time_spent,
total_time,cono,cctr,emp,job,work_date,work_shift,mod_date,mod_time,
mod_user,sfis_trans_id,queue_id,upload) values ('{0}','{1}','{2}','{3}','{4}','{5}',
'{6}','{7}','{8}','{9}','{10}','{11}','{12}','{13}','{14}','{15}',{16},'{17}','{18}')", dt, TxtOperation.Text,
Level1Code, Level2Code, Level3Code, Timespent, TxtTotMins.Text, Cono, TxtCctr.Text,
Emp, TxtJob.Text, Wo_dt, Shift, Wo_dt, mod_time, Emp, TransId, QueueId, Upload);
Utility.SFISConnection.ExecuteNonQuery(Query);

}

this.Close();

}

this is mycode inside buttonclick

musefan31-Mar-09 4:02

31-Mar-09 4:02

well your query code if in a for loop so i can only assume that loop is running twice. Is this what you have indended?

Life goes very fast. Tomorrow, today is already yesterday.

Narendra Reddy Vajrala31-Mar-09 4:16

31-Mar-09 4:16

no no
for loop running fine but
it is coming again to
{ which is the first line under btn_click event
Frown | :(

musefan31-Mar-09 4:21

31-Mar-09 4:21

and then returns after the first if statement?

if you event is being called twice then it would suggest that you hav added it to the buttons Click event more than once, are there any other events attached to the button such as MouseClick, Enter etc.

Life goes very fast. Tomorrow, today is already yesterday.

Narendra Reddy Vajrala31-Mar-09 4:32

31-Mar-09 4:32

nowhere in my project btnOK_Click event twice, i checked in design page also.

musefan31-Mar-09 4:34

31-Mar-09 4:34

Ok, well Colin's suggestion below sounds good, give that a try

Life goes very fast. Tomorrow, today is already yesterday.

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Colin Angus Mackay31-Mar-09 4:30

Colin Angus Mackay

31-Mar-09 4:30

Narendra Reddy Vajrala wrote:
it is coming again to
{ which is the first line under btn_click event

So what is in the call stack? It will show you what called the method. Is the call stack different from the first time the method gets called? What called the method the second time around?

Narendra Reddy Vajrala31-Mar-09 4:40

31-Mar-09 4:40

InitializeComponent();

BtnOk.Click += new EventHandler(BtnOk_Click);

and my clickevent is
private void BtnOk_Click(object sender, EventArgs e)
{
//This Event Raising 2 times.....?
}

and design.cs

this.BtnOk.Click += new System.EventHandler(this.BtnOk_Click);

Ian Shlasko31-Mar-09 4:44

Ian Shlasko

31-Mar-09 4:44

So like stancrm said initially, you're hooking the event twice.

You hooked it once in the designer, and another time in your design.cs. Either unhook it in the designer, or remove that line from design.cs.

Narendra Reddy Vajrala31-Mar-09 5:18

31-Mar-09 5:18

yesssssssssssssssssssss
finally i got on deleting instance in designer.cs

so Thanks to everybody

Big Grin | :-D

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Colin Angus Mackay31-Mar-09 4:48

Colin Angus Mackay

31-Mar-09 4:48

You have not provided much context for the code snippets. Where are they coming from?

Are you saying that you have

BtnOk.Click += new EventHandler(BtnOk_Click);

in your form's constructor, and

this.BtnOk.Click += new System.EventHandler(this.BtnOk_Click);

in your form's design.cs file?

If this is the case it looks like you have added the event handler twice to the button click event. I would recommend removing the one in the constructor because the designer will take care of the one in the form's design.cs class.

Also, what is in the call stack when the BtnOk_Click method is called? (If you don't know where to get the call stack it is probably in Debug-->Windows-->Call Stack)

Greg Chelstowski31-Mar-09 4:57

Greg Chelstowski

31-Mar-09 4:57

How very javascriptish--

anyway, check your Form.designer.cs file for BtnOk.Click+=new EventHandler(object sender, Eventargs e);
and then check your Form.cs file for the same. Get rid of one.
If you want to register that EventHandler always, leave it in the designer file, if you want to attach it if some condition is met - take it out and do it in the form.

var question = (_2b || !(_2b));

Xmen Real 31-Mar-09 4:08

Xmen Real

31-Mar-09 4:08

Narendra Reddy Vajrala wrote:
Please give some solution

Its quite simple...add another button in a new project, put breakpoint and check is it calling twice or not. If it is then something wrong with your windows or your mouse is dying.

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Narendra Reddy Vajrala31-Mar-09 4:18

31-Mar-09 4:18

yes,
from some other form am comming to this form and no where in my project it doesnt happend but y here only....!?

Frown | :(

Xmen Real 31-Mar-09 4:25

Xmen Real

31-Mar-09 4:25

what are you doing to know that its calling twice ?

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Narendra Reddy Vajrala31-Mar-09 4:30