Re: Font Dialog Box - C# Discussion Boards

jaypatel51212-Mar-09 22:15

12-Mar-09 22:15

Exactly what ComputaFreak Said...
You need to take a Font Object. .

Font fnt = new Font();
fnt.FontSize = 12;
fnt.Bold = true;

Anything you have in font dialog option...
And just pass the font property of textbox to the derived font.

Txtbox1.Font = fnt;
thats it. .

fungweizz12-Mar-09 22:55

12-Mar-09 22:55

in this way, is the font size and style fixed? can the user choose from a list of values?

jaypatel51213-Mar-09 2:57

13-Mar-09 2:57

Of course...
But you may need to design the list box.. and combos and everything. .

fungweizz15-Mar-09 14:41

15-Mar-09 14:41

okay.I will try out this method.If I still cant get it I will ask u again.

Thanx alot jaypatel512 and Computafreak! Big Grin | :-D

jaypatel51217-Mar-09 7:08

17-Mar-09 7:08

My Pleasure dude .. .

fungweizz18-Mar-09 20:26

18-Mar-09 20:26

Sorry. I still havent gotten my thingy yet. Looks like I have to trouble you all again.

That time you said by creating a font object, I can display the values in a sample display.
I have searched the net regarding font object but there is no detailed explanation on it.

Can you show me an example so that I can understand better?

sorry for the inconvenience caused.

jaypatel51218-Mar-09 20:56

18-Mar-09 20:56

There is nothing in Font object...

First you create a Form..
Place 3 buttons. and one Rich Text Box.

now name three buttons as bold, underline, and italic.
Give some text to richtextbox. e.g.Sample Line.

Take a Font object at the topmost part of the class.

e.g. Font fnt = new Font();
Now on buttons click events... e.g. buttonbold click event write this.

fnt.Bold = !fnt.Bold; //This will invert the bold .
txtsample.Font = fnt; //This will change the text according to the font you have changed.

And see the difference in Textbox..
If this works , just make other button events as you like. .
Go step by step...
You may get it. .

fungweizz19-Mar-09 22:45

19-Mar-09 22:45

I have just tried out the method that you suggested. But there's an error in the program.
I think I know what goes wrong and I am now figuring out the way to correct it. Thank for your suggestion. I will try to understand it and get back to you again if I still got problems.

Grateful for your help! Big Grin | :-D

jaypatel51219-Mar-09 23:03

19-Mar-09 23:03

My pleasure dude. .
You can share the error you got. .

Might be helped by someone else. .

fungweizz22-Mar-09 16:00

22-Mar-09 16:00

hmm..okay..
one of the error said that System.Drawing.Font cannot be assigned. It is read-only. In this case, how do I assign my combo box value to get the displayed font?

jaypatel51224-Mar-09 2:37

24-Mar-09 2:37

Just keep a button and a label or richtextbox in one form. And place these two lines of code on button press event.

this.fontDialog1.ShowDialog();
this.label1.Font = this.fontDialog1.Font;

fungweizz23-Mar-09 23:17

23-Mar-09 23:17

hmm..do you have any idea on how to add buttons into the default font dialog interface?

jaypatel51224-Mar-09 2:33

http://msdn.microsoft.com/en-us/library/ms646958(VS.85).aspx#_win32_Customizing_the_Font_Dialog_Box[^]

24-Mar-09 2:33

fungweizz24-Mar-09 21:44

24-Mar-09 21:44

really thanks alot for ur help again!! Big Grin | :-D

I have gotten one part of it..I went to the website that u have gave me..but this time round I have to display a button 'advanced' to provide more options to the user..I have searched a while but so far I have nothing..

do you have any idea on how I can do it?

jaypatel51225-Mar-09 5:58

25-Mar-09 5:58

I also read that article,....
It was getting much harder than what I expected...
But Ya , when I was searching for something what I can understand (Really , I ws not able to understand much of that given in MSDN). I came accross a very good article being posted on this site...

It was on custom color dialog box.. where he inserts a slider button which changes the alpha value of the color.. And I found it much interesting and usefull...
And according to your requirement, you need something added to default, if one can add a slider you can also get some very good things from it...
but ya you might need to do some Research and just go for try and error in font dialog...

The link is :

http://www.codeproject.com/KB/graphics/Custom_Color_Dialog_Box.aspx[^]

Hope it helps you. . .

fungweizz25-Mar-09 15:01

25-Mar-09 15:01

hmm..okay..I will look through the article you have provided and try it out..maybe it just works..

thanx for your help all this while! Smile | :)

jaypatel51225-Mar-09 20:04

Textbox in Microsoft Reporting Services question

25-Mar-09 20:04

My Pleasure. . .

Programm3r12-Mar-09 20:38

Programm3r

12-Mar-09 20:38

Hi all,

Is it at all posible to make use of the value of a textbox within the report(.rdlc file)?

If I can give an example:
Lets say you want to get hold of the value that is stored in textbox10 within the report and make use of it in a calculation (Expression window).

How can I get hold of the value that is stored within the report textbox?

Many thanks in advance
Kind regards,

The only programmers that are better C# programmers, are those who look like this -> Green Alien | [Alien]

Programm3r
My Blog: ^_^

Re: Textbox in Microsoft Reporting Services question

Programm3r12-Mar-09 23:50

Programm3r

12-Mar-09 23:50

Within the expressions window enter the following:

ReportItems("textbox").Value

Or see this[^] web site.

The only programmers that are better C# programmers, are those who look like this -> Green Alien | [Alien]

Programm3r
My Blog: ^_^

How to diff two versions of same object ?

dkfjdkfjk12-Mar-09 20:35

dkfjdkfjk

12-Mar-09 20:35

I want to compare two objects of different versions and display there differences in UI.

First I call a method to know if there is any difference between the two objects

The method is as -

public bool AreEqual(object object1,object object2, Type comparisionType)

If the above method returns true

I call GetDifferences method to get the differences which is as -

public ObjectDifference[] GetObjectDifferences(object object1, object object2, Type comparisionType)
{

ArrayList memberList = new ArrayList();
ArrayList differences = new ArrayList();

memberList.AddRange(comparisionType.GetProperties());
memberList.AddRange(comparisionType.GetFields());

for (int loopCount = 0; loopCount < memberList.Count; loopCount++)
{
object objVal1 = null;
object objVal2 = null;
MemberInfo member = ((MemberInfo)memberList[loopCount]);
switch (((MemberInfo)memberList[loopCount]).MemberType)
{
case MemberTypes.Field:
objVal1 = object1 != null ?((FieldInfo)memberList[loopCount]).GetValue(object1):null;
objVal2 = object2 != null?((FieldInfo)memberList[loopCount]).GetValue(object2):null;
break;
case MemberTypes.Property:
// object temp = ((PropertyInfo)memberList[loopCount]).
objVal1 = object1!= null ?((PropertyInfo)memberList[loopCount]).GetValue(object1, null) :null;
objVal2 = object2 != null? ((PropertyInfo)memberList[loopCount]).GetValue(object2, null):null;
break;
default:
break;
}

if (AreValuesDifferentForNull(objVal1, objVal2))
{
ObjectDifference obj = new ObjectDifference(objVal1, objVal2, member,member.Name);
differences.Add(obj);
}
else if (AreValuesDifferentForPrimitives(objVal1, objVal2))
{
ObjectDifference obj = new ObjectDifference(objVal1, objVal2, member, member.Name);
differences.Add(obj);
}
else if (AreValuesDifferentForList(objVal1, objVal2))
{
ObjectDifference[] listDifference = GetListDifferences((ICollection)objVal1, (ICollection)objVal2,member);
differences.AddRange(listDifference);
}
else if ((!AreValuesEqual(objVal1, objVal2)) &&( objVal1 != null || objVal2 != null))
{

ObjectDifference obj = new ObjectDifference(objVal1, objVal2, member, member.Name);
differences.Add(obj);
}

}
return (ObjectDifference[])differences.ToArray(typeof(ObjectDifference));
}

public class ObjectDifference
{
private readonly object objectValue1;
private readonly object objectValue2;
private readonly System.Reflection.MemberInfo member;
private readonly string description;

public object ObjectValue1 {
get { return objectValue1; }
}
public object ObjectValue2 {
get { return objectValue2; }
}
public System.Reflection.MemberInfo Member {
get { return member; }
}
public string Description {
get { return description; }
}

public ObjectDifference(object objVal1,object objVal2,System.Reflection.MemberInfo member,string description)
{
this.objectValue1 = objVal1;
this.objectValue2 = objVal2;
this.member = member;
this.description = description;
}

For each difference I create an object of type ObjectDifference and add it to the array. The highlighted portion is the one where I am stuck! If the object contains another complex object, My program does give me the differences but I dont know which type it belonged to

For example I have two objects of type Name

class Name{

string firstName;
string LastName;

List<phonenumber> phNumber;
}

class PhoneNumber{

string officeNo;
string MobileNo;
string HomeNo;
}

while comparing two objects the output I get is plain -

firstname - John Mary
LastName- cooper Lor

officeNo - 22222 44444
MobileNo - 989898 089089
HomeNo-- 4242 43535

The Hierarchy that officeNo is of type PhoneNumber is lost. which is important for me to display

How should I maintain this type of tree while creating differences.

Hope I am able to make my problem understood.

Pass value from .dll to windows application

yesu prakash12-Mar-09 20:34

yesu prakash

12-Mar-09 20:34

Hi,

A DLL is reffered in a windows application, the dll contain a form. When i call the dll the form is opened. When i close the Form in the dll, i need to pass a value back to the windows application to identify the dll is closed. How can i get the notification?

Thankyou,
YPKI

Re: Pass value from .dll to windows application

stancrm12-Mar-09 21:15

stancrm

12-Mar-09 21:15

There is an event called "Closed". You can hear of that event.

MyForm myForm = new MyForm();<br />
myForm.Closed += new EventHandler(myForm_Closed);<br />
myForm.ShowDialog();<br />
<br />
...<br />
private void myForm_Closed(object sender, EventArgs e)<br />
{<br />
  // MyForm is closed, you can do something here...<br />
}

How to all close by clicking the cross?

soulidentities12-Mar-09 20:26

soulidentities

12-Mar-09 20:26

Hi all
I know its stupid but no way out.
lets say
I have 2 forms. activity is...1 form hide another open...vice versa
I have some restriction here. i cant use any button to exit.
I just have only way to click the cross on the top right side of forms.
By clicking cross it will exit all forms.
But now in my program its not working because another form is hidden.
I have to stop it manualy.

Any suggetion pls

Thanks Smile | :)

Re: How to all close by clicking the cross?

jaypatel51212-Mar-09 21:07