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Use Show() of CMS
eg
contextMenuStrip1.Show();
contextMenuStrip1.Show(x, y);
contextMenuStrip1.Show(textbox, x, y);
TVMU^P[[IGIOQHG^JSH`A#@`RFJ\c^JPL>;"[,*/|+&WLEZGc`AFXc!L
%^]*IRXD#@GKCQ`R\^SF_WcHbORY87֦ʻ6ϣN8ȤBcRAV\Z^&SU~%CSWQ@#2
W_AD`EPABIKRDFVS)EVLQK)JKSQXUFYK[M`UKs*$GwU#(QDXBER@CBN%
Rs0~53%eYrd8mt^7Z6]iTF+(EWfJ9zaK-iTV.C\y<pjxsg-b$f4ia>
--------------------------------------------------------
128 bit encrypted signature, crack if you can
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Doh!, Thanks guys! 
modified 20-Oct-19 21:02pm.
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I have a picturebox on the screen. I also have a panel with some information on the panel.
I can move/drag the panel over the screen. But I want that the panel only moves between the borders
of the picturebox. I don't now how to do this?
Can anyone help me to solve this problem?
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As the panel 'moves' check in the event handler that it is in the correct area.
Have a go, if it doesn't work then post a code snippet.
Code helps. Nearly as well as gin.
Panic, Chaos, Destruction.
My work here is done.
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well, its easy...
if (pictureBox1.ClientRectangle.Contains(x, y))
{
}
TVMU^P[[IGIOQHG^JSH`A#@`RFJ\c^JPL>;"[,*/|+&WLEZGc`AFXc!L
%^]*IRXD#@GKCQ`R\^SF_WcHbORY87֦ʻ6ϣN8ȤBcRAV\Z^&SU~%CSWQ@#2
W_AD`EPABIKRDFVS)EVLQK)JKSQXUFYK[M`UKs*$GwU#(QDXBER@CBN%
Rs0~53%eYrd8mt^7Z6]iTF+(EWfJ9zaK-iTV.C\y<pjxsg-b$f4ia>
--------------------------------------------------------
128 bit encrypted signature, crack if you can
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Xmen wrote: if (pictureBox1.ClientRectangle.Contains(x, y))
It is not sufficient to keep the cursor position inside the PictureBox, that way the Panel can still stick out on any of 4 sides.
One needs to check PictureBox.Bounds.Contains(Z) where Z is either the new Panel.Bounds
or the new Location of two Points (e.g. topleft and bottomright).
Luc Pattyn [Forum Guidelines] [My Articles]
- before you ask a question here, search CodeProject, then Google
- the quality and detail of your question reflects on the effectiveness of the help you are likely to get
- use the code block button (PRE tags) to preserve formatting when showing multi-line code snippets
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Below is my code to add a chat message to a multiline text box.
I have tested the parameters, when I run them on messagebox's they output the proper value, but
when I combine them:
"chatView.Text = chatView.Text + Environment.NewLine + myName + ": "+ myText;"
Only "myName" shows up on each line.
What am i doing wrong?
public delegate void chatMessageCallBack(string myName, string myText);
private void chatMessage(string myName, string myText)
{
chatView.Text = chatView.Text + Environment.NewLine + myName + ": "+ myText;
}
private void addChatMessage(string myName, string myText)
{
if (chatView.InvokeRequired)
{
chatMessageCallBack d = new chatMessageCallBack(chatMessage);
Invoke(d, new object[] { myName, myText });
}
else
{
chatView.Text = chatView.Text + Environment.NewLine + myName + ": " + myText;
}
}
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well if your getting the myName part, i would have to say that your myText value is null or empty.
Try putting in a MessageBox in your chatMessage function and output the two values to make sure they contain the data you expect.
I assume you are getting the ": " along with myName?
Member 3493799 wrote: I have tested the parameters, when I run them on messagebox's they output the proper value, but
when I combine them:
my bad, i missed that line
Life goes very fast. Tomorrow, today is already yesterday.
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very strange,
try replacing the environment.newline with something else to see if the text shows
Life goes very fast. Tomorrow, today is already yesterday.
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I know!
Nothing works in combination.
Heck, even when I remove the newline stuff and just have myName + myText, it only shows myName...
weirdest thing ever..
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what about just textBox.Text = myText;?
Life goes very fast. Tomorrow, today is already yesterday.
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Member 3493799 wrote: Invoke(d, new object[] { myName, myText });
IMO should be chatView.Invoke(...)
Luc Pattyn [Forum Guidelines] [My Articles]
- before you ask a question here, search CodeProject, then Google
- the quality and detail of your question reflects on the effectiveness of the help you are likely to get
- use the code block button (PRE tags) to preserve formatting when showing multi-line code snippets
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Heres the packet decoding scheme:
myName = dataSender
myText = dataMessage
[StructLayout(LayoutKind.Sequential, Pack = 1)]
public struct rawCncPacket
{
public byte IPVerLen;
public byte IPTOS;
public short IPLength;
public short IPID;
public short IPOffset;
public byte IPTTL;
public byte IPProtocol;
public short IPChecksum;
public int IPSrcAddr;
public int IPDestAddr;
public short UDPsourcePort;
public short UDPdestPort;
public short UDPLength;
public short UDPcheckSum;
public int CNCpacketDirection;
public int CNCpacketNumber;
public int CNCpacketSource;
public int CNCpacketDest;
public short CNCpacketPort;
public short CNCpacketHeaderEnd;
public byte dataType;
public byte[] dataSenderBytes;
public string dataSender;
public byte[] dataMessageBytes;
public string dataMessage;
public int dataPackOne;
public int dataPackTwo;
public byte dataPackEnd;
public rawCncPacket(byte[] packet)
{
System.IO.MemoryStream stm = new System.IO.MemoryStream(packet, 0, 94);
System.IO.BinaryReader rdr = new System.IO.BinaryReader(stm);
IPVerLen = rdr.ReadByte();
IPTOS = rdr.ReadByte();
IPLength = rdr.ReadInt16();
IPID = rdr.ReadInt16();
IPOffset = rdr.ReadInt16();
IPTTL = rdr.ReadByte();
IPProtocol = rdr.ReadByte();
IPChecksum = rdr.ReadInt16();
IPSrcAddr = rdr.ReadInt32();
IPDestAddr = rdr.ReadInt32();
UDPsourcePort = rdr.ReadInt16();
UDPdestPort = rdr.ReadInt16();
UDPLength = rdr.ReadInt16();
UDPcheckSum = rdr.ReadInt16();
CNCpacketDirection = rdr.ReadInt32();
CNCpacketNumber = rdr.ReadInt32();
CNCpacketSource = rdr.ReadInt32();
CNCpacketDest = rdr.ReadInt32();
CNCpacketPort = rdr.ReadInt16();
CNCpacketHeaderEnd = rdr.ReadInt16();
dataType = rdr.ReadByte();
dataSenderBytes = rdr.ReadBytes(12);
dataMessageBytes = rdr.ReadBytes(24);
dataSender = System.Text.ASCIIEncoding.ASCII.GetString(dataSenderBytes);
dataMessage = System.Text.ASCIIEncoding.ASCII.GetString(dataMessageBytes);
dataPackOne = rdr.ReadInt32();
dataPackTwo = rdr.ReadInt32();
dataPackEnd = rdr.ReadByte();
}
}
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Hi,
not sure why I am getting all this, thanks anyway.
some remarks:
1.
either this struct has strict requirements or it has not.
if it has, I doubt it should hold both public byte[] dataSenderBytes; and public string dataSender; // 12
same for public byte[] dataMessageBytes; and public string dataMessage; // 24
if it has not, don't see why it should need a Pack=1 attribute
2.
your problem is with string handling.
in the native world (C, C++) strings consist of 8-bit characters (or 16-bit wide characters) and they end on the first ASCII NULL character (byte value zero), which means the NULL character itself cannot be embedded in a string.
in the managed world strings can contain any character you choose; if you give 12 bytes (dataSenderBytes) to ASCII.GetString() it probably returns a 12-character string of which several could be NULL (or \0).
So I suggest you get the meaningful length of those strings somehow from the byte[] or from the native world, then use ASCIIEncoding.GetString(Byte[], 0, length)
Luc Pattyn [Forum Guidelines] [My Articles]
- before you ask a question here, search CodeProject, then Google
- the quality and detail of your question reflects on the effectiveness of the help you are likely to get
- use the code block button (PRE tags) to preserve formatting when showing multi-line code snippets
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Running it within the IDE, put some breakpoints in on the entry to each of your methods.
Step through and see what the values are that are being received.
Maybe instead of:
chatView.Text = chatView.Text + Environment.NewLine + myName + ": "+ myText;
Try:
String newText = chatView.Text + Environment.NewLine + myName + ": "+ myText;
chatView.Text = newText;
Then after newText has been created you can be sure the correct value is going ito the RHS of the expession.
This is debug problem, you just need to establish the values at every step of the process.
Panic, Chaos, Destruction.
My work here is done.
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Used breakpoints, saw the values and they were correct.
newText was highlighted in red though when I got to the" chatView.Text = newText" (dont know what that means: VS2008).
myName = "test"
myText = "ETST13245"
newText "\r\Test\0\0\0\0\0\0\0: ETST13245\0\0\0\0\0\0\0\0\0\0\0\0\0\0\0" string
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Member 3493799 wrote: \0\0\0\0\0\0\0
As soon as it's hitting the null char, the display is being truncated.
Panic, Chaos, Destruction.
My work here is done.
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Cheers, that makes sense, will change it accordingly.
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You are welcome.  After yesterday's retardfest it is nice to have a real question to answer.
BTW My first port of call when code is not behaving is to debug the thing to smithereens until I find the problem. My second is a call for Port.
Panic, Chaos, Destruction.
My work here is done.
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Opening a good old Port may be the solution to many a networking problem 
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Hi all,
I have created a multi-threaded TCP/IP server. Each client connection runs in it's own thread.
The problem that I have it when I close the server and there are still clients connected. The thing is that the client threads remain active.
How can stop / dispose of the client threads so that the server can be closed for good?
Many thanks in advance
Kind regards,
The only programmers that are better C# programmers, are those who look like this -> ![Green Alien | [Alien]](https://codeproject.global.ssl.fastly.net/script/Forums/Images/alien.gif) |
Programm3r
My Blog: ^_^
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well you need to handle connections when you close down the server.
You should have a list of all connected clients, right?
so you will want to stop incomming connections.
then you can abort all client threads, preferable after sending information to the client about the shut down
Life goes very fast. Tomorrow, today is already yesterday.
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musefan wrote: You should have a list of all connected clients, right?
Yes.
musefan wrote: then you can abort all client threads
The only thing is that the client threads spawn out of another thread that is listening for any incoming connections. If a new connection is accepted by the listen thread the listen thread spawns a new thread for that connections. Thus I do not have the handle to each of the client threads that have been spawned, well I think so anyway.
Many thanks for your response
Kind regards,
| The only programmers that are better C# programmers, are those who look like this -> |
Programm3r
My Blog: ^_^
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Did you use Socket.beginAccept?
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