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I need to add header and datetime and orientation in excel when user print the excel document.
public static void excelprint(DataSet source, string fileName)
{
bool status = false;
try
{
System.IO.StreamWriter excelDoc;
excelDoc = new System.IO.StreamWriter(fileName);
const string startExcelXML = "<xml version>\r\n<Workbook " +
"xmlns=\"urn:schemas-microsoft-com:office:spreadsheet\"\r\n" +
" xmlns =\"urn:schemas-microsoft-com:office:office\"\r\n " +
"xmlns:x=\"urn:schemas- microsoft-com:office:" +
"excel\"\r\n xmlns:ss=\"urn:schemas-microsoft-com:" +
"office:spreadsheet\">\r\n <Styles>\r\n " +
"<Style ss:ID=\"Default\" ss:Name=\"Normal\">\r\n " +
"<Alignment ss:Vertical=\"Bottom\"/>\r\n <Borders/>" +
"\r\n <Font/>\r\n <Interior/>\r\n <NumberFormat/>" +
"\r\n <Protection/>\r\n </Style>\r\n " +
"<Style ss:ID=\"BoldColumn\">\r\n <Font " +
"x:Family=\"Swiss\" ss:Bold=\"1\"/>\r\n </Style>\r\n " +
"<Style ss:ID=\"StringLiteral\">\r\n <NumberFormat" +
" ss:Format=\"@\"/>\r\n </Style>\r\n <Style " +
"ss:ID=\"Decimal\">\r\n <NumberFormat " +
"ss:Format=\"0.00\"/>\r\n </Style>\r\n " +
"<Style ss:ID=\"Integer\">\r\n <NumberFormat " +
"ss:Format=\"0\"/>\r\n </Style>\r\n <Style " +
"ss:ID=\"DateLiteral\">\r\n <NumberFormat " +
"ss:Format=\"mm/dd/yyyy;@\"/>\r\n </Style>\r\n " +
"</Styles>\r\n ";
const string endExcelXML = "</Workbook>";
int rowCount = 0;
int sheetCount = 1;
excelDoc.Write(startExcelXML);
for (int worksheet = 0; worksheet < source.Tables.Count; worksheet++)
{
excelDoc.Write("<Worksheet ss:Name=\"" + source.Tables[worksheet].TableName + "\">");
excelDoc.Write("<Table>");
excelDoc.Write("<Row>");
for (int x = 0; x < source.Tables[worksheet].Columns.Count; x++)
{
excelDoc.Write("<Cell ss:StyleID=\"BoldColumn\"><Data ss:Type=\"String\">");
excelDoc.Write(source.Tables[worksheet].Columns[x].ColumnName);
excelDoc.Write("</Data></Cell>");
}
excelDoc.Write("</Row>");
for (int x = 0; x < source.Tables[worksheet].DefaultView.Count; x++)
{
rowCount++;
if (rowCount == 64000)
{
rowCount = 0;
sheetCount++;
excelDoc.Write("</Table>");
excelDoc.Write(" </Worksheet>");
excelDoc.Write("<Worksheet ss:Name=\"Sheet" + worksheet + "\">");
excelDoc.Write("<Table>");
}
excelDoc.Write("<Row>"); //ID=" + rowCount + "
for (int y = 0; y < source.Tables[worksheet].Columns.Count; y++)
{
System.Type rowType;
rowType = source.Tables[worksheet].DefaultView[x][y].GetType();
switch (rowType.ToString())
{
case "System.String":
//string XMLstring = x[y].ToString();
string XMLstring = source.Tables[worksheet].DefaultView[x][y].ToString();
XMLstring = XMLstring.Trim();
XMLstring = XMLstring.Replace("&", "&");
XMLstring = XMLstring.Replace(">", ">");
XMLstring = XMLstring.Replace("<", "<");
excelDoc.Write("<Cell ss:StyleID=\"StringLiteral\">" +
"<Data ss:Type=\"String\">");
excelDoc.Write(XMLstring);
excelDoc.Write("</Data></Cell>");
break;
case "System.DateTime":
// DateTime XMLDate = (DateTime)x[y];
DateTime XMLDate = (DateTime)source.Tables[worksheet].DefaultView[x][y];
string XMLDatetoString = "";
XMLDatetoString = XMLDate.Year.ToString() +
"-" +
(XMLDate.Month < 10 ? "0" +
XMLDate.Month.ToString() : XMLDate.Month.ToString()) +
"-" +
(XMLDate.Day < 10 ? "0" +
XMLDate.Day.ToString() : XMLDate.Day.ToString()) +
"T" +
(XMLDate.Hour < 10 ? "0" +
XMLDate.Hour.ToString() : XMLDate.Hour.ToString()) +
":" +
(XMLDate.Minute < 10 ? "0" +
XMLDate.Minute.ToString() : XMLDate.Minute.ToString()) +
":" +
(XMLDate.Second < 10 ? "0" +
XMLDate.Second.ToString() : XMLDate.Second.ToString()) +
".000";
excelDoc.Write("<Cell ss:StyleID=\"DateLiteral\">" +
"<Data ss:Type=\"DateTime\">");
excelDoc.Write(XMLDatetoString);
excelDoc.Write("</Data></Cell>");
break;
case "System.Boolean":
excelDoc.Write("<Cell ss:StyleID=\"StringLiteral\">" +
"<Data ss:Type=\"String\">");
//excelDoc.Write(x[y].ToString());
excelDoc.Write(source.Tables[worksheet].DefaultView[x][y].ToString());
excelDoc.Write("</Data></Cell>");
break;
case "System.Int16":
case "System.Int32":
case "System.Int64":
case "System.Byte":
excelDoc.Write("<Cell ss:StyleID=\"Integer\">" +
"<Data ss:Type=\"Number\">");
// excelDoc.Write(x[y].ToString());
excelDoc.Write(source.Tables[worksheet].DefaultView[x][y].ToString());
excelDoc.Write("</Data></Cell>");
break;
case "System.Decimal":
case "System.Double":
excelDoc.Write("<Cell ss:StyleID=\"Decimal\">" +
"<Data ss:Type=\"Number\">");
// excelDoc.Write(x[y].ToString());
excelDoc.Write(source.Tables[worksheet].DefaultView[x][y].ToString());
excelDoc.Write("</Data></Cell>");
break;
case "System.DBNull":
excelDoc.Write("<Cell ss:StyleID=\"StringLiteral\">" +
"<Data ss:Type=\"String\">");
excelDoc.Write("");
excelDoc.Write("</Data></Cell>");
break;
default:
throw (new Exception(rowType.ToString() + " not handled."));
}
}
excelDoc.Write("</Row>");
}
excelDoc.Write("</Table>");
excelDoc.Write(" </Worksheet>");
}
excelDoc.Write(endExcelXML);
excelDoc.Close();
status = true;
// MessageBox.Show("Data exported to excel file successfuly");
}
catch (Exception)
{
status = false;// MessageBox.Show("Error in exporting data to excel file");
}
}
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@vikram_asv:
Please repost and use the <pre> tag to allow us to easily read your code. Thanks!
"we must lose precision to make significant statements about complex systems."
-deKorvin on uncertainty
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Hello Curtis,
I am sending u code which i used and modify with my criteria.I am able to export data to a different worksheets. But all i need is when user prints the excel sheet i need to put header, footer , date and orientation - landscape dynamically . I search but no luck may be anyone can help me about this . Here is the link
http://www.codeproject.com/KB/dotnet/ExportToExcel.aspx
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I don't use Microsoft Office, so I can't answer this directly. However, if you look at this article Dive into SpreadsheetML (Part 1 of 2)[^], they will show you how to set print options and what not.
Also, set the header and footer of an Excel spreadsheet to some distinct values, save it in the XML format, and look for those nodes.
Reverse engineering is the way to go, here.
"we must lose precision to make significant statements about complex systems."
-deKorvin on uncertainty
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Hello Curtis, I am again reposting the code with pre tag so that it can to easy to read what u say
I need to add header and datetime and orientation in excel when user print the excel document.I am not able to add datetime ,orientation,header programmatically .if u could help me greatly appreciated where i can add this items in my code so that i can see when i print excel document.
public static void excelprint(DataSet source, string fileName)
{
bool status = false;
try
{
System.IO.StreamWriter excelDoc;
excelDoc = new System.IO.StreamWriter(fileName);
const string startExcelXML =
<xml version="">
<workbook xmlns="urn:schemas-microsoft-com:office:spreadsheet">
xmlns ="urn:schemas-microsoft-com:office:office"
xmlns:x="urn:schemas-microsoft-com:office:excel"
xmlns:ss="urn:schemas-microsoft-com:office:spreadsheet">
<styles>
<alignment ss:vertical="Bottom">
<borders>
<font />
<interior />
<numberformat />
<protection />
</borders></alignment>
<font x:family="Swiss" ss:bold="1" xmlns:x="#unknown" />
<numberformat ss:format="@" />
<numberformat ss:format="0.0000" />
<numberformat ss:format="0" />
<numberformat ss:format="mm/dd/yyyy;@" />
const string endExcelXML = "</Workbook>";
int rowCount = 0;
int sheetCount = 1;
excelDoc.Write(startExcelXML);
for (int worksheet = 0; worksheet < source.Tables.Count; worksheet++)
{
excelDoc.Write("<Worksheet ss:Name=\"" + source.Tables[worksheet].TableName + "\">");
excelDoc.Write("<Table>");
excelDoc.Write("<Row>");
for (int x = 0; x < source.Tables[worksheet].Columns.Count; x++)
{
excelDoc.Write("<Cell ss:StyleID=\"BoldColumn\"><Data ss:Type=\"String\">");
excelDoc.Write(source.Tables[worksheet].Columns[x].ColumnName);
excelDoc.Write("</Data></Cell>");
}
excelDoc.Write("</Row>");
for (int x = 0; x < source.Tables[worksheet].DefaultView.Count; x++)
{
rowCount++;
if (rowCount == 64000)
{
rowCount = 0;
sheetCount++;
excelDoc.Write("</Table>");
excelDoc.Write(" </Worksheet>");
excelDoc.Write("<Worksheet ss:Name=\"Sheet" + worksheet + "\">");
excelDoc.Write("<Table>");
}
excelDoc.Write("<Row>"); //ID=" + rowCount + "
for (int y = 0; y < source.Tables[worksheet].Columns.Count; y++)
{
System.Type rowType;
rowType = source.Tables[worksheet].DefaultView[x][y].GetType();
switch (rowType.ToString())
{
case "System.String":
//string XMLstring = x[y].ToString();
string XMLstring = source.Tables[worksheet].DefaultView[x][y].ToString();
XMLstring = XMLstring.Trim();
XMLstring = XMLstring.Replace("&", "&");
XMLstring = XMLstring.Replace(">", ">");
XMLstring = XMLstring.Replace("<", "<");
excelDoc.Write("<Cell ss:StyleID=\"StringLiteral\">" +
"<Data ss:Type=\"String\">");
excelDoc.Write(XMLstring);
excelDoc.Write("</Data></Cell>");
break;
case "System.DateTime":
// DateTime XMLDate = (DateTime)x[y];
DateTime XMLDate = (DateTime)source.Tables[worksheet].DefaultView[x][y];
string XMLDatetoString = "";
XMLDatetoString = XMLDate.Year.ToString() +
"-" +
(XMLDate.Month < 10 ? "0" +
XMLDate.Month.ToString() : XMLDate.Month.ToString()) +
"-" +
(XMLDate.Day < 10 ? "0" +
XMLDate.Day.ToString() : XMLDate.Day.ToString()) +
"T" +
(XMLDate.Hour < 10 ? "0" +
XMLDate.Hour.ToString() : XMLDate.Hour.ToString()) +
":" +
(XMLDate.Minute < 10 ? "0" +
XMLDate.Minute.ToString() : XMLDate.Minute.ToString()) +
":" +
(XMLDate.Second < 10 ? "0" +
XMLDate.Second.ToString() : XMLDate.Second.ToString()) +
".000";
excelDoc.Write("<Cell ss:StyleID=\"DateLiteral\">" +
"<Data ss:Type=\"DateTime\">");
excelDoc.Write(XMLDatetoString);
excelDoc.Write("</Data></Cell>");
break;
case "System.Boolean":
excelDoc.Write("<Cell ss:StyleID=\"StringLiteral\">" +
"<Data ss:Type=\"String\">");
//excelDoc.Write(x[y].ToString());
excelDoc.Write(source.Tables[worksheet].DefaultView[x][y].ToString());
excelDoc.Write("</Data></Cell>");
break;
case "System.Int16":
case "System.Int32":
case "System.Int64":
case "System.Byte":
excelDoc.Write("<Cell ss:StyleID=\"Integer\">" +
"<Data ss:Type=\"Number\">");
// excelDoc.Write(x[y].ToString());
excelDoc.Write(source.Tables[worksheet].DefaultView[x][y].ToString());
excelDoc.Write("</Data></Cell>");
break;
case "System.Decimal":
case "System.Double":
excelDoc.Write("<Cell ss:StyleID=\"Decimal\">" +
"<Data ss:Type=\"Number\">");
// excelDoc.Write(x[y].ToString());
excelDoc.Write(source.Tables[worksheet].DefaultView[x][y].ToString());
excelDoc.Write("</Data></Cell>");
break;
case "System.DBNull":
excelDoc.Write("<Cell ss:StyleID=\"StringLiteral\">" +
"<Data ss:Type=\"String\">");
excelDoc.Write("");
excelDoc.Write("</Data></Cell>");
break;
default:
throw (new Exception(rowType.ToString() + " not handled."));
}
}
excelDoc.Write("</Row>");
}
excelDoc.Write("</Table>");
excelDoc.Write(" </Worksheet>");
}
excelDoc.Write(endExcelXML);
excelDoc.Close();
status = true;
// MessageBox.Show("Data exported to excel file successfuly");
}
catch (Exception)
{
status = false;// MessageBox.Show("Error in exporting data to excel file");
}
}
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xml version
/*
<xml version>
<Workbook xmlns="urn:schemas-microsoft-com:office:spreadsheet"
xmlns ="urn:schemas-microsoft-com:office:office"
xmlns:x="urn:schemas-microsoft-com:office:excel"
xmlns:ss="urn:schemas-microsoft-com:office:spreadsheet">
<Styles>
<Style ss:ID="Default" ss:Name="Normal">
<Alignment ss:Vertical="Bottom"/>
<Borders/>
<Font/>
<Interior/>
<NumberFormat/>
<Protection/>
</Style>
<Style ss:ID="BoldColumn">
<Font x:Family="Swiss" ss:Bold="1"/>
</Style>
<Style ss:ID="StringLiteral">
<NumberFormat ss:Format="@"/>
</Style>
<Style ss:ID="Decimal">
<NumberFormat ss:Format="0.0000"/>
</Style>
<Style ss:ID="Integer">
<NumberFormat ss:Format="0"/>
</Style>
<Style ss:ID="DateLiteral">
<NumberFormat ss:Format="mm/dd/yyyy;@"/>
</Style>
</Styles>
<Worksheet ss:Name="Sheet1">
</Worksheet>
</Workbook>
*/
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use pre tag mate as curtis asked you. Look around for pre tag before you post and post once again.
All the best
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Howdy'
I'm generating some XML files with MSXML; The text is all put on one single line;
so I'm trying to transform the document with some XSL "black" magic.
The stylesheet (taken from some google-search):
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" indent="yes" />
<xsl:template match="*">
<xsl:copy>
<xsl:copy-of select="@*" />
<xsl:apply-templates />
</xsl:copy>
</xsl:template>
</xsl:stylesheet>
This works well, except for one minor thing.
For empty "tags", the transformation transform :
<MyTag attribute="value"/>
to
<MyTag attribute="value"></MyTag >
I'm not quite familiar with XSL, and was wondering if there's a way to not create the empty closing tags ?
I hope it makes sens.
Thanks.
Max.
This signature was proudly tested on animals.
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Is there a reason why you don't want the closing tag? Both of the nodes, the one with the /> and the one with the ></MyTag> have the same meaning in XML and should parse the same way....
"we must lose precision to make significant statements about complex systems."
-deKorvin on uncertainty
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For no other reason than "aestheticism"
This signature was proudly tested on animals.
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Yeah, I like it that way, too.
No, if you're using MSXML, there's no way to force it to output />. It's hard-coded to do that, as far as I know, having used it for quite a long time.
"we must lose precision to make significant statements about complex systems."
-deKorvin on uncertainty
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how can i setup a parser to log in to particular page and grab a cookie ?
Thanks
Andyyy
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Most likely, Andy, you'll have to do the following in the programming language of your choice:- Create the content for the login POST request.
- Stream the post request to the server over the applicable port.
- Read the response.
- Parse out the Set-Cookie lines from the HTTP response.
Here's the HTTP RFC[^] for reference.
"we must lose precision to make significant statements about complex systems."
-deKorvin on uncertainty
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Thanks for your reply.
is there any psudo code which i can follow in xsl or xml ?
Cheers
Andyy 
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This really isn't an XML or XSL problem.
"we must lose precision to make significant statements about complex systems."
-deKorvin on uncertainty
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Hey everyone
When i save a word document as an XML file it write a large amount of data into the xml document. I have used an XSL file to only capture the required data from the wordML to my own xml file. This customized xml file should have only the tags specified in the xslt. Look into the file below
<?xml version="1.0" encoding="UTF-8" standalone="yes" ?>
- <pkg:package xmlns:pkg="http://schemas.microsoft.com/office/2006/xmlPackage">
- <pkg:part pkg:name="/_rels/.rels" pkg:contentType="application/vnd.openxmlformats-package.relationships+xml" pkg:padding="512">
- <pkg:xmlData>
- <Relationships xmlns="http://schemas.openxmlformats.org/package/2006/relationships">
<Relationship Id="rId3" Type="http://schemas.openxmlformats.org/officeDocument/2006/relationships/extended-properties" Target="docProps/app.xml" />
<Relationship Id="rId2" Type="http://schemas.openxmlformats.org/package/2006/relationships/metadata/core-properties" Target="docProps/core.xml" />
<Relationship Id="rId1" Type="http://schemas.openxmlformats.org/officeDocument/2006/relationships/officeDocument" Target="word/document.xml" />
</Relationships>
</pkg:xmlData>
</pkg:part>
- <pkg:part pkg:name="/word/_rels/document.xml.rels" pkg:contentType="application/vnd.openxmlformats-package.relationships+xml" pkg:padding="256">
- <pkg:xmlData>
- <Relationships xmlns="http://schemas.openxmlformats.org/package/2006/relationships">
<Relationship Id="rId3" Type="http://schemas.openxmlformats.org/officeDocument/2006/relationships/webSettings" Target="webSettings.xml" />
<Relationship Id="rId2" Type="http://schemas.openxmlformats.org/officeDocument/2006/relationships/settings" Target="settings.xml" />
<Relationship Id="rId1" Type="http://schemas.openxmlformats.org/officeDocument/2006/relationships/styles" Target="styles.xml" />
<Relationship Id="rId5" Type="http://schemas.openxmlformats.org/officeDocument/2006/relationships/theme" Target="theme/theme1.xml" />
<Relationship Id="rId4" Type="http://schemas.openxmlformats.org/officeDocument/2006/relationships/fontTable" Target="fontTable.xml" />
</Relationships>
</pkg:xmlData>
</pkg:part>
- <pkg:part pkg:name="/word/document.xml" pkg:contentType="application/vnd.openxmlformats-officedocument.wordprocessingml.document.main+xml">
- <pkg:xmlData>
- <w:document xmlns:ve="http://schemas.openxmlformats.org/markup-compatibility/2006" xmlns ="urn:schemas-microsoft-com:office:office" xmlns:r="http://schemas.openxmlformats.org/officeDocument/2006/relationships" xmlns:m="http://schemas.openxmlformats.org/officeDocument/2006/math" xmlns:v="urn:schemas-microsoft-com:vml" xmlns:wp="http://schemas.openxmlformats.org/drawingml/2006/wordprocessingDrawing" xmlns:w10="urn:schemas-microsoft-com:office:word" xmlns:w="http://schemas.openxmlformats.org/wordprocessingml/2006/main" xmlns:wne="http://schemas.microsoft.com/office/word/2006/wordml">
- <w:body>
.................................. so on and so forth
From this file i am only trying to extract the data that written in the document. It goes this way
Name Teja
Age 22
For this i have written a small xsl file which looks this way
<?xml version="1.0"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:w="http://schemas.openxmlformats.org/wordprocessingml/2006/main"
exclude-result-prefixes="w"
version="1.0">
<xsl:output method="xml" indent="yes"/>
<xsl:template match="w:p">
<Details> <xsl:value-of select="."/> </Details>
</xsl:template>
</xsl:stylesheet>
Now i am expecting my result to be an xml document with my own xml tags. This is how i want my document to look like
Name
Teja
Age
22
Now to look at the result i have been using xml notepad. But to convert WordML to XML i need a convertor. What do i need to use in order to do that?
Please help me out
Thanks in Advance
Teja
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Tejabhiram wrote: But to convert WordML to XML i need a convertor
Do you mean something to read the WordML as XML to feed it to your XSLT, or do you mean something to actually run your XSLT?
For the former, use something like 7-zip to extract the source files from inside the docx - I'm guessing that you're already doing this though.
For the latter you can use the msxml commandline tool, or if you want to code it I'd use the .Net XSL compiled transform in your code. Or Saxon if you need something in the Java domain
I just love Koalas - they go great with Bacon.
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Hey Lee,
Ok let me explain it to u i detail. I need to write a .NET application which can help me open a normal xml file in word. Then when the user modifies the content, i need to store the modified content back to the original xml file. In order to do this, first i am writing a xslt to convert my xml file to word file. Then when the modification is done,I am saving the Word Document as WordML, writing another inverse xsl file to convert WordMl to the original xml format. In the XML to word process, the word itself is taking care of the conversion process. But in the reverse process, I am not able to figure out how to convert the file back to a normal xml file.
From you questions I analyuze that i am trying to do the latter part, i.e run my xsl. Now to do that, you have suggested me to use the .NET XSL compiled transform i my code. How do i do that? Where can I find information regarding this?
Please help me out
Thanks in Advance
Teja
"Why to be a MAN when you can be a SUCCESS?"
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OK,
Sorry for the shameless plug, but get the code for my article - Introduction to XPS[^] this includes code to use .Net Compiled Transform. Don't worry if you're a VBer I'm sure you can figure out the C#.
I just love Koalas - they go great with Bacon.
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Hey Lee
ya i googled it from ur earlier reply and was able to find the VB code and i just tested it for transformation. It worked. wow, i have these so called senior developers on my side and it dint strike them when i asked them for this transformation tool. K thanks a million.
Regards
Teja
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How do i convert an XML file to JSON(Java Script Object Notation) file using XSLT.
Help me......(new to XSLT).
Thanks in Advance
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I'd recommend first learning some XSLT. You can do that at W3 Schools XSLT Tutorial[^].
Then, I'd recommend learning about JSON, if you don't know it already. You can do that at JSON.org[^].
Finally, map the elements from your XML file to serialized objects in the JSON file.
"we must lose precision to make significant statements about complex systems."
-deKorvin on uncertainty
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I'm writing a C# app to document the types of XmlSchemaComplex types...
I have a schema file containing complexTypes, and those complexTypes have elements which are of other complexTypes, located in another file that I'm including into my outer schema file. I'm reading the schema file, going into the complexTypes, and trying to read the types of the sub-elements that are of the sub-types.
However, the type attributes of the elements inside my main complexTypes are set to nulls, although the SchemaTypeText is filled out with the current type name and namespace.
The code that I'm using looks a little something like this (please pardon the horrendous noobishness):
XmlTextReader schemaReader = new XmlTextReader(schemaPath);
XmlSchema schema = XmlSchema.Read(schemaReader, null);
foreach (XmlSchemaObject xso in schema.Items)
{
if (xso is XmlSchemaComplexType)
{
XmlSchemaComplexType rootType = xso as XmlSchemaComplexType;
if (rootType.Particle is XmlSchemaSequence)
{
XmlSchemaSequence rootseq = (XmlSchemaSequence)rootType.Particle;
foreach(XmlSchemaObject ixso in rootseq.Items)
{
if (ixso is XmlSchemaElement)
{
XmlSchemaElement ele = ixso as XmlSchemaElement;
XmlSchemaType eleType = ele.SchemaType; // this is null
string typTxt = ele.SchemaTypeText; // this right, but strings.
}
}
}
}
If I can get the part about accessing the element types of the nested elements in my complexTypes right, I want to pass those complexTypes into a recursive method that'll enumerate all the members of the inner complexTypes for me, etc.
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hello all
Can any one help me with the xml read and write operations using java
some sample codes......
which is used in java DOM ,SAX,,,,,
thanks
tJS
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TJS4u wrote: Can any one help me
Sure, I always enjoy helping the google impaired.
Here you go[^]
Have a nice day.
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