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I can't be sure what you mean by not working, but that condition will always be true because of this:
((textBox2.Text != "703") || (textBox2.Text != "733"))
The textBox2 text will never be equal to both 703 and 733.
As an aside, you seem to be doing number comparisons, so I would recommend using number variables instead of strings. You could then test (b >= 2 && b < 6)
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Okeeei...
So, i want to check... if its enetered only 703 or 733... BESIDES that the b starts with 2,3,4 or 5.
I really dont know how to make this thing to work... maybe i jsut have a bad day and am a bit confused... but yet again... i dont understand it
Please help? :/
Regards,
Matjaž
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Matjaž Grahek wrote: i want to check... if its enetered only 703 or 733
I have no idea what the condition is.
a) Do you want this.text = "OK" if text = 703 or 733?
b) or do you want this.text = "Not Ok!" if text = 703 or 733?
int textVal = 0;
int.tryparse(textbox2.text, out textVal);
if(textVal == 703 || textVal==733)
{
this.Text = "ok";
this.Text = "Not Ok";
}
Matjaž Grahek wrote: b starts with 2,3,4 or 5
here is a simple solution to that:
int val = 0;
int.tryparse(b[0].ToString(), out val)
this should help,
Prateek
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This code
((textBox2.Text != "703") || (textBox2.Text != "733"))
will always be true
Regards,
Lev
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well,
((textBox2.Text != "703") || (textBox2.Text != "733"))
will always evaluate to true for starters.
Regards,
Rob Philpott.
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Hi,
if you don't understand why a statement behaves the way it does, then the only good advice is to write simpler statements. Why do you insist on putting everything in a single line? Chop it into smaller pieces and look at the intermediate values, that will help you understand if and how it works.
As for the 703/733 thing, as all the others already told you, that cannot possibly be what you intended. For what value do you think it will evaluate to false?
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Well, my intention was ...
If the first character of the string was 2,3,4 or 5 the it should also check the textbox if there is entered any of the two mentioned values (703 or 733).
Ok, looking at it this way... maybe it could work with two ifs...
Regards,
Matjaž
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if (b[0] == '2' || b[0] == '3' || b[0] == '4' || b[0] == '5')
if((textBox2.Text != "703") || (textBox2.Text != "733"))
{
this.Text = "OK";
}
else
{
this.Text = "NI OK!";
}
ok... this doesnt work either:S
Regards,
Matjaž
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Matjaž Grahek wrote: ((textBox2.Text != "703") || (textBox2.Text != "733"))
Guy, for the last time, this will ALWAYS evaluate to True. How about change that "or" to an "and"??
if ((textbox2.Text != "703") && (textbox2.Text != "733"))
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It doesn't work because you haven't changed the logic.
Scott P.
"Simplicity carried to the extreme becomes elegance."
-Jon Franklin
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class Program {
static void Main(string[] args) {
string b = "3.12312123";
if ((b[0] == '2' || b[0] == '3' || b[0] == '4' || b[0] == '5') && ((args[0] == "703") || (args[0]== "733"))) {
Console.WriteLine("OK");
} else {
Console.WriteLine("NOT OK!");
}
}
}
Merry Christmas.
"Simplicity carried to the extreme becomes elegance."
-Jon Franklin
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Your problem displays the most common failure of beginning programmers -- mixing their 'AND' and their 'OR' logic.
You also need to think of how to address your other requirement that the text begin with 2,3,4, or 5.
A possible solution is first to write what you want out in text
if b starts with a valid number and textbox contains valid numbers then it's ok.
That leads to code such as this:
string b = "3.12321212";
List<char> validValues = new List<char> { '2', '3', '4', '5' };
List<string> validInput = new List<string> { "703", "733" };
textbox1.Text = "Not OK";
if ( validValues.Contains( b[0] ) && validInput.Contains( texbox.Text ) )
{
textbox1.Text = "OK";
}
Another way you can also address this problem is with RegEx but I don't have the time to figure out the pattern.
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Ok... thank you all for your answers. Will try this tommorow. Again, thanks for your patience and the will to help.
Good night
Regards,
Matjaž
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Hello
I have just updated a control in my project and cannot access the Design panel because of teh following error:
ResX file Could not load file or assembly 'Xceed.Chart.Core, Version=4.2.100.0, Culture=neutral, PublicKeyToken=ba83ff368b7563c6' or one of its dependencies. The system cannot find the file specified. Line 7585, position 5. cannot be parsed. ---> System.Xml.XmlException: Could not load file or assembly 'Xceed.Chart.Core, Version=4.2.100.0, Culture=neutral, PublicKeyToken=ba83ff368b7563c6' or one of its dependencies. The system cannot find the file specified. Line 7585, position 5. ---> System.IO.FileNotFoundException: Could not load file or assembly 'Xceed.Chart.Core, Version=4.2.100.0, Culture=neutral, PublicKeyToken=ba83ff368b7563c6' or one of its dependencies. The system cannot find the file specified.
File name: 'Xceed.Chart.Core, Version=4.2.100.0, Culture=neutral, PublicKeyToken=ba83ff368b7563c6'
Where do i delete the bad reference?
The program works but i cannot edit the GUI because of the error.
I am using VS2008 SP1
is there a workaround?
Thanks
Have a nice Day
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Go to the solution explorer, and look at the properties of the reference to the Xceed library. It should have a property called "Specific Version". Set the property to false and rebuild.
If it's a custom library, then check wether the ResX is read-only. I've had some issues with the Interop-toolkit on the generation of resource-files (binary resource not checked out by sourcesafe and being readonly)
Good luck
I are troll
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When I build a project by visual studio 2008, and then copy to a computer equibed with windows XP to run it, It have errors, So I want to know how to confugation to get the release version of my project?
Error message:
The application initialization(0xc0000135)failure, Click OK to close it
I searching in google but didn't find a answer, Maybe I'm a beginner, 
Addition: My question is how to confugation to make the final program run in a machine without .Net framwork?
modified on Thursday, December 18, 2008 10:28 AM
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I'm sorry to post such a simple question in this, but I'm eagar to know the answer, thank you
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Wait more t hen 4 minutes before you post again how eager or urgent it is. If someone here wants to help or knows, they will reply. Otherwise, start hitting google for an answer.
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Hi,
If you want any help you will need to let us know exactly what error message you see and when you see it.
Alan.
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It would help if you told us what the errors were.
Simon
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In Solution Explorer, Check inside Properties folder , there is a files
Assemblyinfo.cs . Open it, check there is a statement
[assembly: AssemblyVersion("1.0.0.0")]
You can change it from here.
Or,
Right Click on Project in Solution Explorer -> Properties -> Select Application Tab ( By Default Selected ) -> Click on Assembly Information Button.
From here you can configure the version.
cheers,
Abhijit
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1) Make sure you've built a "release build"
2) Make sure the target PC has the necessary runtimes. This probably means the .net framework, which isn't installed by default on XP, so you'll need to make sure the user downloads and installs it first.
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Copy pasting the release folder (as I think you are doing) is not the way to deploy a program.
Since you need .net framework (that could be causing the errors)
You might need several dll's that aren't in the release folder (that could also could be causing the errors)
You should add a new project to your solution of the type setup project.
Add your project output to the application folder, maybe add a few shortcuts as you see fit, build that and use the .exe and .msi that it creates to install your program.
Other that this I can't give you more help with the information you provided
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My wild guess would be that the target machine doesn't have .Net Framework installed. But again the error message would be of a great value.
Regards,
Lev
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