|
Below is the change in bold to do in your code:
private void button1_Click(object sender, EventArgs e)
{
string cmd;
string field;
string parameter;
field = "Site,Model";
parameter = "@Site,@Model";
OleDbConnection aConnection = new OleDbConnection("Provider=Microsoft.Jet.OLEDB.4.0;Data Source=c:\\db1.mdb");
cmd = "INSERT INTO Run(" + field + ") values (" + parameter + ")";
OleDbCommand sCommand = new OleDbCommand(cmd);
aConnection.Open();
sCommand.Connection = aConnection
OleDbDataReader aReader = sCommand.ExecuteReader();
sCommand.Parameters.Add("@Site", OleDbType.VarChar, 20);
sCommand.Parameters.Add("@Model", OleDbType.VarChar, 20);
sCommand.Parameters["@Site"].Value = "site1";
sCommand.Parameters["@Model"].Value = "Model1";
aReader.Close();
aConnection.Close();
}
Hope this solves your problem
|
|
|
|
|
thanks. but another error occur:
No value given for one or more required parameters.???
|
|
|
|
|
Why are you creating an OleDbDataReader for an INSERT statement? It makes no sense since reader is used when you fetch data from the database.
Also you execute the command before setting any parameters or their values.
|
|
|
|
|
I'm having a little bit of brain fry going on...
How can I go about to see if any date within a date range is in another date range?
Example: Is any date between 01/01/2008 - 12/31/2015 in 11/21/2008 - 12/21/2009?
MOD:
Ok, so I think I found my answer. Does anyone see an issue with this comparison?
01/01/2008 < 12/21/2009 AND 12/31/2015 > 11/21/2008 [obviously these would be parameters and fields in a database.... paramStart < dbEnd AND paramEnd > dbStart]
modified on Monday, December 1, 2008 3:09 PM
|
|
|
|
|
mobius111001 wrote: Is any date between 01/01/2008 - 12/31/2015 in 11/21/2008 - 12/21/2009?
If
date1 = 01/01/2008
date2 = 12/31/2015
date3 = 11/21/2008
date4 = 12/21/2009
then it would be something like:
... date1 between date3 and date4
or date2 between date3 and date4
or (date1 < date3 and date2 > date4) ...
|
|
|
|
|
We have developed software in .net application and backhand as a SQL Server Desktop Engine. The query is how to update database at client end without disturing his live data. There is continious update going on in database structure. This is the issue we have been facing from a long time.
Thanks.
|
|
|
|
|
Dear singhdheeraj21,
The best practice is to apply patches after the deployment of the application. While creating a patch keep the versioning of the patches and optionally keep the versioning of the database too. Always create a roll back patch as your last resort. It will help you to recover your last best working state.
Hope this answer your question.
Thanks and Regards,
Umair Feroze
|
|
|
|
|
The usual way is to make all your database changes repeatable, for example always try and do alter table scripts after checking the column defintion needs changing. A tip, if you make the change through enterpirse manager there is an option to create a change script. These sometimes can be tweaked, but they are the script that would be applied if you said save.
Hope this helps
Bob
Ashfield Consultants Ltd
|
|
|
|
|
What Are Extended Properties Sql Server 2005 And What Should I Do To See Extended Properties In Sql Server 2005.I Searched In MSDN I Tried The Method Given Over There To See Extended Properties But Its Not Working
(MSDN:-Select Column Check Properties For Extended Properties)
|
|
|
|
|
Extended properties let you define your own properties on an object and add values to them.
For example you can add extended property Description to a table and then for the value you can define some descriptive text.
Refer to: sp_addextendedproperty (Transact-SQL)[^].
|
|
|
|
|
I am working in a mySQL db and we made a mistake when implementing the tables by having one of the fields in every table being to short. We use this field to catch which form in the applications update each table. The syntax I am finding is to do this...ALTER TABLE `cl_client_common` change `UpdateProgram` char(50). It is currently a char(20) I know that this will work and we should not lose any data however what I am wanting to accomplish is to do this to every table in the db without having to write the code for all 200+ tables. So what I am wondering is could I write something like ALTER TABLE `databaseName`.`*` change `UpdateProgram` char(50).
Any advice would be much appreciated, Please and Thank you.
Humble Programmer
|
|
|
|
|
You can use system tables to generate proper statements. It would be something like following:
SELECT CONCAT( 'ALTER TABLE ', Table_Name, ' CHANGE ...')
FROM Information_Schema.Tables
WHERE Table_Schema = 'YourSchema';
When executing this select, you'll get statements you can again execute to make the actual changes.
Hope this helps,
Mika
|
|
|
|
|
Good advice I don't know what that did not cross my mind.
Humble Programmer
|
|
|
|
|
I used your solution yesterday, it worked perfectly. Thank you very much you are much appreciated.
Humble Programmer
|
|
|
|
|
You're welcome 
|
|
|
|
|
Hi,
I have sql server 2005 installed with most of if not all its components, and also have vwd 2008 and VS 2005. Now I am ready to install VS 2008, is it a good method to uninstall sql 2005 and VWD 2008 to start a clean VS 2008 installation?
regards,
hawari
hawari
|
|
|
|
|
You can install SQL Server 2008 and keep SQL Server 2005 if you need both of them. From my experiences there's been no trouble.
I don't know what you're referring to with VWD?
The need to optimize rises from a bad design.
My articles[ ^]
|
|
|
|
|
09 is referring to Visual Web Developer
The world is a stage and most of us are desperately unrehearsed.
—Sean O’Casey, Playwright
|
|
|
|
|
Ok, thanks for the info! That's something I know nothing about...
The need to optimize rises from a bad design.
My articles[ ^]
|
|
|
|
|
No reason to uninstall SQL Server 2005. Not sure why you would need VS 2008 and VWD 2008.
The world is a stage and most of us are desperately unrehearsed.
—Sean O’Casey, Playwright
|
|
|
|
|
hi;
i want to write a sql query of different between two dates.
.....................................................
DECLARE @mindays DATETIME
DECLARE @today DATETIME
SET @mindays =select min(daily_date) from r_dailymaterial_entry)
SET @today = getdate()
SELECT DATEDIFF(DAY, @mindays, @today) AS [DateDifference]
.....................................................
i gets a error..
Server: Msg 156, Level 15, State 1, Line 4
Incorrect syntax near the keyword 'select'.
please help me...
|
|
|
|
|
snehasish wrote: SET @mindays =select min(daily_date) from r_dailymaterial_entry)
Try the following. There was an extra parenthesis in the end and when you use select, you don't use set command in the start:
select @mindays = min(daily_date) from r_dailymaterial_entry
The need to optimize rises from a bad design.
My articles[ ^]
|
|
|
|
|
hi Mika Wendelius,
Many thanks to you for giving this solution.It works fine. Thanks once again.
snehasish
|
|
|
|
|
You're welcome 
The need to optimize rises from a bad design.
My articles[ ^]
|
|
|
|
|
Given the T-SQL statments below, it seems that the statements do nothing other than splitting the @MinDate and @MaxDate into day, month and year and then recreating it. Before deleting this portion, can you people verify that I am not missing any perspective.
select @MinDate = min(TheDate) from tDate where TheDate > convert(datetime,'01-01-1980',105)
select @MaxDate = max(TheDate) from tDate
--The following statements are not doing anything meaningful, I believe.
set @Year = datepart(yyyy,@MinDate)
set @Month = datepart(mm,@MinDate)
set @Day = datepart(d,@MinDate)
if len(@Month) = 1
begin
set @Month = '0'+@Month
end
if len(@Day) = 1
begin
set @Day = '0'+@Day
end
set @MinDate = convert(datetime,@Day+'-'+@Month+'-'+@Year,105)
set @Year = datepart(yyyy,@MaxDate)
set @Month = datepart(mm,@MaxDate)
set @Day = datepart(d,@MaxDate)
if len(@Month) = 1
begin
set @Month = '0'+@Month
end
if len(@Day) = 1
begin
set @Day = '0'+@Day
end
set @MaxDate = convert(datetime,@Day+'-'+@Month+'-'+@Year,105)
Regards,
Syed Mehroz Alam
My Blog
My Articles
Computers are incredibly fast, accurate, and stupid; humans are incredibly slow, inaccurate and brilliant; together they are powerful beyond imagination. - Albert Einstein
|
|
|
|
General 
News 
Suggestion 
Question 
Bug 
Answer 
Joke 
Praise 
Rant 
Admin 
Submit an article or tip
