C#

PointF[] pfTempData = GetCalculatedPoints(intIndex);

panel2Graphics.DrawCurve(new Pen(Color.Black, 0F), pfTempData);

Panel2Graphics.DrawImage(bmpExport, pfTempData);

{System.ArgumentException: Destination points must be an array with a length of 3 or 4. A length of 3 defines a parallelogram with the upper-left, upper-right, and lower-left corners. A length of 4 defines a quadrilateral with the fourth element of the array specifying the lower-right coordinate.<br />
   at System.Drawing.Graphics.DrawImage(Image image, PointF[] destPoints)<br />
   at GDIWaveformViewer2.PlotPanel.DrawGraph(Graphics gPanel2Graphics) in D:\Documents and Settings\vinayakumark\Desktop\Viewer-18july\Viewer\PlotPanel.cs:line 327}

hopingToCode wrote:

I have a windows form that has on it 40ish buttons with images, 8 image box's, a couple of labels and that's it.

hopingToCode wrote:

It's going to be running on a mini machine with 1GB Ram and 499Mhz processor.

Guffa wrote:

You can't select the distinct file name, as you are not getting only the file name.

Guffa wrote:

First you have to decide how to determine which full path you want to keep for each distinct file name.

The only programmers that are better those C# programmers are those who code in 1's and 0's

Programm3r
My Blog: ^_^

class Program
{
    static void Main(string[] args)
    {
        String[] files = Directory.GetFiles(@"C:\My Files");
        var distinctFiles = files.Distinct(new FileEqualityComparer());

        foreach (var file in distinctFiles)
        {
            Console.WriteLine(file);
        }

        Console.ReadLine();

    }
}

public class FileEqualityComparer : EqualityComparer<string>
{
    public override bool Equals(string x, string y)
    {
        String FileNameX = x.Split(new Char[] { '_' })[1];
        String FileNameY = y.Split(new Char[] { '_' })[1];

        return FileNameX == FileNameY;
    }

    public override int GetHashCode(string obj)
    {
        String fileName = obj.Split(new Char[] { '_' })[1];
        return fileName.GetHashCode();
    }
}</string>

Dave Kreskowiak wrote:

he may already be familiar with Rent-A-Coder