|
Depends on the file format.
Anyway, you've basically to read the file content, perform filtering and sorting on your structured data (in memory) and then (if you need) write back such info.
Bottom line: vague question, vague answer.
If the Lord God Almighty had consulted me before embarking upon the Creation, I would have recommended something simpler.
-- Alfonso the Wise, 13th Century King of Castile.
This is going on my arrogant assumptions. You may have a superb reason why I'm completely wrong.
-- Iain Clarke
[My articles]
|
|
|
|
|
|
Your question is transparent can you use of AlphaBlend for display your question.
|
|
|
|
|
Hi!
I have a Box with certain width and height. The box has to contain a certain text that should be visible inside the box no matter how long it is.
So, if the text is too small then it should take as much space in the box as possible. Its size should be inversly proportional to the text length. But I have to maintain its actual characters proportion too.
Any body who has ever done it in MFC. I am using VC 8
|
|
|
|
|
You should at first draw the text in a memory DC and than make StretchBlt to the wanted size. Read MFC class CDC.
Greetings from Germany
|
|
|
|
|
But how to draw text in the DC memory?
modified on Thursday, October 16, 2008 6:38 AM
|
|
|
|
|
CDC::DrawText()
Try considering to read the MSDN, or google "cdc and mfc". 
Greetings from Germany
|
|
|
|
|
|
Is there any command that gets all the details of the device connected to the serial port ??
Actually i connect a smart card reader to a serial COM port, i send some data to it using WriteFile (), in return it gives some response, i read the response using ReadFile().
Now if i donot connect the reader and simply connect the serial cable to computers serial port i send the data to the handle of the serial port using WriteFile(), the computer(or ReadFile ()) waits infinitely for receiving response !
In order to solve above problem i use COMMTIMEOUTS, so if the specified time expires the ReadFile() executes successfully although it doesn't get the response!!
Actually i donot want to use COMMTIMEOUTS since i donot know the exact time in which the reader sends a response !!
if i use maximum delay it decreases the performance of my application, if i use completely less time delay, the ReadFile() expires even before it receives respone from the reader!!
so is there any other suggestion
|
|
|
|
|
kapardhi wrote: How to detect whether a device is connected to a Serial port (Re-Post,since not yet satisfied with given suggestions)
I think you'll have to re-post again and again. Good luck.
If the Lord God Almighty had consulted me before embarking upon the Creation, I would have recommended something simpler.
-- Alfonso the Wise, 13th Century King of Castile.
This is going on my arrogant assumptions. You may have a superb reason why I'm completely wrong.
-- Iain Clarke
[My articles]
|
|
|
|
|
For starters - check Wikipedia Serial Port
Here is the "link" with some extra characters added by this control:
<a href="http://en.wikipedia.org/wiki/Serial_port">http://en.wikipedia.org/wiki/Serial_port</a>[<a href="http://en.wikipedia.org/wiki/Serial_port" target="_blank" title="New Window">^</a>]
Your code needs to monitor the "handshake" signals of the serial communication protocol (RS232), i.e. hardware status, first before it attempts to read or write any actual data.
There is an older book dealing with serial communication in C, which covers this in details.
Sorry, don’t remember the exact title. Just Google it.
Cheers Vaclav
|
|
|
|
|
Hi all,
How do I know the number of occurences of a character from a string for example the "@" sign from email@email@email.com. I need to validate email addresses.
Thanks,
Jayjay
|
|
|
|
|
Count them.
Seriously though, are you kidding? After more than a year of asking programming questions here you can't figure this out by yourself? You should consider a career change.
modified on Thursday, October 16, 2008 5:29 AM
|
|
|
|
|
Michael Schubert: CodeProject's official career counselor. 
Many are stubborn in pursuit of the path they have chosen, few in pursuit of the goal - Friedrich Nietzsche
.·´¯`·->Rajesh<-·´¯`·.
[Microsoft MVP - Visual C++]
|
|
|
|
|
He he. I think not. John Simmons is much better at that. 
|
|
|
|
|
Michael Schubert wrote: You should consider a career change.
Any suggestions??
Regards,
Sandip.
|
|
|
|
|
This could get ugly. Maybe switching to Visual Basic?
|
|
|
|
|
Michael Schubert wrote: Maybe switching to Visual Basic?
Oh my God... You are the worst job counselor I have ever seen 
|
|
|
|
|
I know. 
|
|
|
|
|
Yes, of course [^].
If the Lord God Almighty had consulted me before embarking upon the Creation, I would have recommended something simpler.
-- Alfonso the Wise, 13th Century King of Castile.
This is going on my arrogant assumptions. You may have a superb reason why I'm completely wrong.
-- Iain Clarke
[My articles]
|
|
|
|
|
That is interesting .. May be it will suit him..
BTW: Looks like this is another crime of THHB.
Regards,
Sandip.
|
|
|
|
|
SandipG  wrote:
Another one here [^].
If the Lord God Almighty had consulted me before embarking upon the Creation, I would have recommended something simpler.
-- Alfonso the Wise, 13th Century King of Castile.
This is going on my arrogant assumptions. You may have a superb reason why I'm completely wrong.
-- Iain Clarke
[My articles]
|
|
|
|
|
Call iteratively strchr [^].
If the Lord God Almighty had consulted me before embarking upon the Creation, I would have recommended something simpler.
-- Alfonso the Wise, 13th Century King of Castile.
This is going on my arrogant assumptions. You may have a superb reason why I'm completely wrong.
-- Iain Clarke
[My articles]
|
|
|
|
|
monsieur_jj wrote: I need to validate email addresses.
You need to validate the email address to have one and only one '@' character? OK, this code will do that:
const char *szEmail= "myname@mydoma@in.com";
strchr(szEmail,'@')?strchr(strchr(szEmail,'@')+1,'@')?cout<<"Invalid!":cout<<"Valid!":cout<<"Invalid!!"; Program Output: Invalid!
Error checking and any dodgy stuff must be handled by *you* of course. 
Many are stubborn in pursuit of the path they have chosen, few in pursuit of the goal - Friedrich Nietzsche
.·´¯`·->Rajesh<-·´¯`·.
[Microsoft MVP - Visual C++]
|
|
|
|
|
You could try:
string strEmail = "email@email@email.com";
count(strEmail.begin(), strEmail.end(), '@');
"Love people and use things, not love things and use people." - Unknown
"The brick walls are there for a reason...to stop the people who don't want it badly enough." - Randy Pausch
|
|
|
|
General 
News 
Suggestion 
Question 
Bug 
Answer 
Joke 
Praise 
Rant 
Admin 
Submit an article or tip
