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Hello,
I need to create ISAPI filter, but can't find its template in VS2005 C++ templates can I add it by any means or I have to get back to VC++ 6?
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There is one in my VS2005 Professional
VC++/ATL/ATL Server Project
led mike
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I saw a driver of a cdrom, witch simply transmit IRP_MJ_READ io request to default driver present by the os(calling IofCallDriver). but now, when an io request(IRP_MJ_READ) came, how the driver holds the read data?
I am sure the driver has done some tricks on the read data before returning the data to user application.
Regards,
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If the driver is building its own IRP with IRP_MJ_CREATE before passing it to the lower driver, then that driver has surely supplied a local buffer to the lower driver when calling IoCallDriver. When the IRP returns, then the driver can access the read data through its supplied buffer. Is that what you mean?
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This is a cdrom driver which was installed for the highest driver over the default one present by the os. In the driver, most of the IRP routine is just simply call IofCallDriver to transmit the IO request to lower driver. my question is that, the driver hasn't constructed a new irp before calling IofCallDriver.
The driver mainly perform decryption ops of the content of the discs. No matter you use a normal user mode app to read discs via ReadFile or just simply use windows Ctrl+C and Ctrl+V to copy and paste any file in the disc, the data read from the disc already is decrypted data.
So, i think the driver might use some special tricks to hold the data read by lower default driver and decrypted it just before the data would be returned to the user mode space. but the problem is, i am not a professional driver programmer but only know little about driver programming.
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Hi all
First of all, this is my first time writing here, so please sorry if I do something wrong.
I am developing an application which takes a variable std::string and writes it to an std:fstream file. The string is in Spanish so it may have accents. The problem is that when I try to copy the string to the file, it does not copy the spanish accents. Do you have any idea of what I am doing wrong?
Please help me because this is quite urgent. Thanks in advance.
Regards,
Aitor
The code looks like this:
std::string plainText = receiveString()
printf(plainText.c_str)
std:fstream plainFile;
plainFile.open("c:\\test.txt");
plainFile << plainText << std::endl;
plainFile.close();
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Member 4708544 wrote: urgent
This is not going to improve the response time here, rather the opposite.
Member 4708544 wrote: it does not copy the spanish accents
How do you determine this? What do the strings in the file look like?
Also, what is the locale (language setting) on your OS?
modified on Monday, October 13, 2008 5:34 AM
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Hi Michael
First of all, thank you very much for your reply
Michael Schubert wrote: This is not going to accelerate the response time here, rather the opposite.
Sorry Michael. You know that this is my first time writing here and I just sayed that this question was urgent because it is really quite urgent (We have to deliver our application today. Actually, it was for last friday). Anyway, sorry.
Michael Schubert wrote: How do you determine this? What do the strings in the file look like?
It writes different things depending which letter has the accent. For example, instead of writing "qué" it writes "qu,". Instead of writing "pájaro", it writes "p jaro". Instead of writing "comíamos", it writes "com¡amos".
Michael Schubert wrote: Also, what is the locale (language setting) on your OS?
Spanish
Thanks Michael.
Regards,
Aitor
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This program (I used VS2005) produces the two identical files os.txt, fp.txt, both containing the string with the accent.
#include <stdio.h>
#include <fstream>
#include <string>
using namespace std;
int main()
{
FILE * fp;
ofstream os;
fp = fopen("fp.txt", "w");
os.open("os.txt", ios::out);
fprintf(fp, "città\n");
os << "città" << endl;
fclose(fp);
os.close();
}
[added]
Fixed the formatting of the code snippet, thanks to Rajesh.
[/added]
If the Lord God Almighty had consulted me before embarking upon the Creation, I would have recommended something simpler.
-- Alfonso the Wise, 13th Century King of Castile.
This is going on my arrogant assumptions. You may have a superb reason why I'm completely wrong.
-- Iain Clarke
[My articles]
modified on Monday, October 13, 2008 7:32 AM
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CPallini wrote: #include
#include
#include
The codez need fixzing.
Many are stubborn in pursuit of the path they have chosen, few in pursuit of the goal - Friedrich Nietzsche
.·´¯`·->Rajesh<-·´¯`·.
[Microsoft MVP - Visual C++]
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Ooops. What a noob 
Fixed, thank you pal.
If the Lord God Almighty had consulted me before embarking upon the Creation, I would have recommended something simpler.
-- Alfonso the Wise, 13th Century King of Castile.
This is going on my arrogant assumptions. You may have a superb reason why I'm completely wrong.
-- Iain Clarke
[My articles]
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Wow! Some idiot voted you down.
Many are stubborn in pursuit of the path they have chosen, few in pursuit of the goal - Friedrich Nietzsche
.·´¯`·->Rajesh<-·´¯`·.
[Microsoft MVP - Visual C++]
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Rajesh R Subramanian wrote: Wow! Some idiot voted you down.
 ...Kanine Krunchies shortage...
If the Lord God Almighty had consulted me before embarking upon the Creation, I would have recommended something simpler.
-- Alfonso the Wise, 13th Century King of Castile.
This is going on my arrogant assumptions. You may have a superb reason why I'm completely wrong.
-- Iain Clarke
[My articles]
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Hi all
Thank you everyone for your replies, but unfortunately they could not help me to solve my problem. However, I have been trying different things, and now I have a new point of view of my problem.
The string I get from the "receiveString()" function comes from a ms-dos console (it is a client-server communication). The problem is that this console uses CP850 instead of CP1252, which is the correct one for Windows.
So, my new problem is, how do I convert a string with cp850 to another string with cp1252?
Thanks in advance.
Regards,
Aitor
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You can use OemToChar() or OemToCharBuff() for this.
I should have noticed that it was a code page issue when you mentioned that it looks fine using printf() in a console window. D'oh...
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Oh god! Thank you very much Michael! Several hours working on this and it the solution was just to add a line...
Anyway, now it works fine. Thanks again Michael!
Regards,
Aitor
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You're welcome.
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Hi,
Here is the issue:
- I am uploading a big file into a server using ftp
- on the server, a process will start processing the file as soon as it detect is presence ( even incomplete file )
is there any why that this process can guess whether the file is finished uploading or not?
thanks in advance.
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What I'm suggesting isn't very sophisticated but...
you can make an empty second file with the same name and some identifying string after you've finished uploading the big file and make the server process look for it. So if your big file is named bigfile.dat, then then your process should look for a file named "bigfile.dat.isreadyforprocessing", then you remove the last part of the name, delete this empty file and you have the name of the file you should be processing.
There is sufficient light for those who desire to see, and there is sufficient darkness for those of a contrary disposition.
Blaise Pascal
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Im not sure it this[^] helpful?
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This also may be simple, but couldn't you just try to open the file? If the ftp server is still adding data into it, your exclusive-share-read open will fail? Just try later!
Or add the .readyforprocessing file thingy - it's cunning as well as simple!
Iain
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Hi All
I have a two dialog box,first is Password dialog and second one is Main dialog.When application is run first time then Password dialog open.Then user enter a password it will store in file.Now when user run the application on same machine then Password dialog not open.How can i do?Plz help me
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Davitor wrote: How can i do?
At startup, you can check to see if file exists. If it does, bypass password dialog.
"Love people and use things, not love things and use people." - Unknown
"The brick walls are there for a reason...to stop the people who don't want it badly enough." - Randy Pausch
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Do you want to show password dialog again?
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Hello,
I am having a child dialog as my current window. On top of it i open a new dialog with 2 buttons. Now what i want is that the user should not be able to work on any other dialog box or application until and unless he clicks one of the two buutons of the topmost dialog box.
This is the declaration of it rc file
IDD_ACCEPT_REFUSE_DLG DIALOGEX 0, 0, 233, 46
STYLE DS_SETFONT | DS_MODALFRAME | DS_FIXEDSYS | DS_CENTER | WS_POPUP | WS_CAPTION | WS_SYSMENU
CAPTION "Live2Support"
FONT 8, "MS Shell Dlg", 400, 0, 0x1
BEGIN
CTEXT "",IDC_STATIC_MSG,8,5,223,10
PUSHBUTTON "Accept",IDC_ACCEPT,56,31,59,15
PUSHBUTTON "Deny",IDC_DENY,118,31,59,15
END
and this is how i am creating and showing the topmost dialog box.
CAcceptRefuse* ptrAcceptRefuse = new CAcceptRefuse(this,_T(""),k,stOperatorDetails.strOpSessionId,stOperatorDetails.strOpName,m_strSiteID);
ptrAcceptRefuse->Create(IDD_ACCEPT_REFUSE_DLG,this);
ptrAcceptRefuse->ShowWindow(SW_SHOW);
Please Help Me
Thanks In Advance
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