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Ditto to JZ.
Pretty much everything is zero based. If there's any doubt in your mind, simple create the collection and add items to it. Then do your own testing iterating through the collection.
Any suggestions, ideas, or 'constructive criticism' are always welcome.
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Why don't you just try it? Create an instance of the object and loop through it in your debugger?
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As you suspected, those previous replies are all wrong. They're trying to mislead you for fun - don't listen to them. Fortunately, i'm here to give you the straight dope no problem: the starting index of a System.Collection object is 143. Always 143. Except in leap years on odd-numbered days of the month: then it's 2 - this is a subtle bug in many programs, so be sure you add code to test for it. You can usually speed up these checks by storing all such dates in a database table (i recommend using Access), and just querying for them before you start iterating on your collection.
That's it - no big deal, eh? Carry on, brother man!
Citizen 20.1.01 'The question is,' said Humpty Dumpty, 'which is to be master - that's all.'
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Let's discuss something similar. Are integers are integers?
I'm too lazy to test int i="sdafsaf"; too.
OK,. what country just started work for the day ? The ASP.NET forum is flooded with retarded questions. -Christian Graus
Best wishes to Rexx[^]
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Whenever you have such questions in your mind, Just try accessing
Console::WriteLine(yourObject[0]);
Make sure you enclose it with try{}catch{}.
If an exception gets caught, and if the message looks something like "Bloody s*cker you can't touch my a**", it's definitely 1 based.
OK,. what country just started work for the day ? The ASP.NET forum is flooded with retarded questions. -Christian Graus
Best wishes to Rexx[^]
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Hi there i am a newbie in VB .Net, I am getting this error on my Page_Load DataModule is not a member of 'System.Security.Principal.IPrincipal' and I do not have any roles yet on my application, just a simple class to populate a datagrid, is there a way i can turn this security off? what is wrong? i am using VS 2008 with v3.5sql server 2005. Please help
Imports System
Imports System.Data
Imports System.Data.SqlClient
Imports System.Web.Security
Imports System.Security.Principal
Imports System.Web
Imports System.Web.UI
Public Class User
Dim mDataPath As String
Public Shared DataModule As User
Function GetConnection() As SqlConnection
Return New SqlConnection("Server=GMPROD13\GMFE;Integrated Security=True;Database=GM_Escheatables")
End Function
'Public Overloads Function GetUsers() As DataSet
' Return Me.GetAllUsers("USER_EMPL_NO")
'End Function
Public Overloads Function GetAllUsers() As DataSet
Dim conn As SqlConnection = GetConnection()
Try
Dim cmd As New SqlCommand("Escheatables_GetAllUser", conn)
Dim ds As New DataSet
Dim adpt As New SqlDataAdapter(cmd)
Try
adpt.Fill(ds, "users")
Finally
adpt.Dispose()
End Try
Return ds
Finally
conn.Close()
conn.Dispose()
End Try
End Function
Public Sub New(ByVal sDatapath As String)
MyBase.new()
Me.mDataPath = sDatapath
User.DataModule = Me
End Sub
End Class
Imports System
Imports System.Data
Imports System.Data.SqlClient
Imports System.Collections.Generic
Imports System.Security.Principal
Partial Class Escheatables_UserList
Inherits System.Web.UI.Page
Private dsUsers As DataSet
Protected Sub Page_Load(ByVal sender As Object, ByVal e As System.EventArgs) Handles Me.Load
dsUsers = User.DataModule.GetAllUsers
Me.GridView1.DataSource = dsUsers
Me.GridView1.DataMember = "users"
'Me.GridView1.ReadOnly = True
Me.GridView1.DataBind()
End Sub
End Class
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Hello everybody,
I am calling crystal report file i.e .rpt file from desktop application which is in vb.net 1.1 > On click Print button, It display result in crystal report and after click on option export from crystal report file , i gets result in pdf file.
Now, i want whenever i click print , i want directly get result in pdf instead getting result in crystal report then export .
Regards
Shailesh Kavalkar
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Imports CrystalDecisions.Web
Imports CrystalDecisions.Shared
Imports CrystalDecisions.CrystalReports.Engine
Imports CrystalDecisions.CrystalReports.Engine.ReportDocument
Partial Class test
Inherits System.Web.UI.Page
Dim cn As OledbConnection
Protected Sub Page_Load(ByVal sender As Object, ByVal e As System.EventArgs) Handles Me.Load
Call ShowReport()
End Sub
Sub ShowReport()
''***************************************************************************************
''Don't change any line in the below code or the report will not work as expected
''***************************************************************************************
Dim ConnInfo As New ConnectionInfo
With ConnInfo
.DatabaseName = "test"
End With
Dim rpt As New ReportDocument
rpt.Load(Server.MapPath("Abc.rpt"))
Dim ParamFields As ParameterFields = Me.CrystalReportViewer.ParameterFieldInfo
Dim ParamField As New ParameterField
Dim ParamField_Value As New ParameterDiscreteValue
ParamField.Name = "frmdt"
ParamField_Value.Value = Session("FROMDATE") ''frmDate ''"30-Oct-2007 12:00:00"
ParamField.CurrentValues.Add(ParamField_Value)
rpt.ParameterFields("frmdt").CurrentValues.Add(ParamField_Value)
ParamFields.Add(ParamField)
ParamField = New ParameterField
ParamField_Value = New ParameterDiscreteValue
'Here todt is the parameter name Created in Report
ParamField.Name = "todt"
ParamField_Value.Value = Session("TODATE") ''ToDate ''"31-Oct-2007 12:00:00"
ParamField.CurrentValues.Add(ParamField_Value)
rpt.ParameterFields("todt").CurrentValues.Add(ParamField_Value)
ParamFields.Add(ParamField)
''*********** VERY IMPORTANT ''*****************
''Whenever using Parameter passing to CR :- Assigning the ParameterFields object to the ParameterFieldInfo of the CrystalReportViewer object programmatically will also suppress the default dialog asking for parameters that normally appears when you open a report with parameters.
Me.CrystalReportViewer.ParameterFieldInfo = ParamFields
For Each cnInfo As TableLogOnInfo In Me.CrystalReportViewer.LogOnInfo
cnInfo.ConnectionInfo = ConnInfo
Next
'========================================================================================================
'To Open Report In PDF
'========================================================================================================
'Dim ms As System.IO.MemoryStream
'ms = CType(rpt.ExportToStream(ExportFormatType.PortableDocFormat), System.IO.MemoryStream)
'rpt.Close()
'Response.ClearContent()
'Response.ClearHeaders()
'Response.ContentType = "Application/pdf"
'Response.AppendHeader("Content-Dispositon", "attachment;filename=DatewiseReport.pdf")
'Response.Buffer = True
'Response.BinaryWrite(ms.ToArray())
'Response.End()
'========================================================================================================
''*********** VERY IMPORTANT ''*****************
'' Error message "Thread was being aborted" - Solution - If your are using Try...Catch block then remove it.
End Sub
End Class
Darshana Pathak
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hi did u tried it?
Darshana Pathak
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I have DataGridView1 Tool in this DataGridView having 5 columns.
Two columns are DataGridViewComboBoxColumn and three columns are DataGridViewTextBoxColumn.
My task is two DataGridViewComboBoxColumn1 taken from a data master table1,
DataGridViewComboBoxColumn2 is taken from a data master table2
and anther three DataGridViewTextBoxColumn date from user input in the DataGridView1.
Now I need All these five columns data’s should be saved in new table called transition table1
Is it passable can you help me?
Franics K Antony
modified on Wednesday, August 27, 2008 2:04 AM
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Yes it is Possible.
Make a For Loop from i=0 to gridview.rows.count-1
insert into transition values('"& ctype(gridview.findcontrol("ComboBox1"),DropDownList).selecteditem.text &"','"& ctype(gridview.findcontrol("ComboBox2"),DropDownList).selecteditem.text &"','"& ctype(gridview.findcontrol("TextBox1"),TextBox).Text &"','"& ctype(gridview.findcontrol("TextBox2"),TextBox).Text &"','"& ctype(gridview.findcontrol("TextBox3"),TextBox).Text &"')
Try & if still not working then reply
Darshana Pathak
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Thank you for you code,
But my problem is how to connect more then two table in single DataGridView like a DataGridViewComboBox1 connect one master table1, DataGridViewComboBox2 connect one master table2
at a same time in the two column data’s save in transition table1,
How can I do please help me. This is major problem
Please mail me it is argent
Franics K Antony
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You can bind gridview with query from coding
For e.g.
dim da as OledbDataAdapter
dim dt as new DataTable
dim st as String
'Enter Connection String
dim cn as OledbConnection("")
st="select a.name as Name,b.Address as Address from student a,info b"
da=new OledbDataAdapter(st,cn)
da.fill(dt)
Gridview1.datasource=dt
Gridview1.DataBind()
and while Adding the ComboBox Column in Gridview You can Give DatatextField= Name & DataValueField= Address
Same for ComboBox2 Column
Try if Still Not getting then tell so i can give u my phone no so u can call me.
Darshana Pathak
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What u said was right, but the problem is
In datagridview1 we have 5 columns
Column1-slno
Column2-specification (combobox)
Column3-shape (combobox)
Column4-prize
Column5-remarks
Tables1-t01customerorder
Table2-m01specification
Table03-m02shape
In load event-All above columns are retrieved from transaction table –t01customerorder
If we click new button column2 as get data from Table2-m01specification
And column3 as to get data from Table03-m01shape, after selecting the value from master table
Column1, column4, column5 –user input
Click save button, selected data from master table and user input get saved into Tables1-t01customerorder
Please help me to achieve task
Thank you one’s again
Franics K Antony
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can u tell me that upto which point ur successfully getting the results?
reply so i can give u further hint
Darshana Pathak
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Hi,
I'm using VC6.0 DLL with VB.NET. XYZClient.dll is in the same directory as the VB.NET exe is present. But, still I get this runtime error on some PCs.It works on couple of PC without any issues. I tried on Windows XP as well as 2K. Results are intermittent. Any idea?
In VB, function is decalred as below:
Declare Function XYZOpenConnection Lib "XYZClient.dll" (ByVal IPAddressOrMachineName As String, ByVal usernameOfXYZUserGroup As String, ByVal applicationData As Integer) As Short
Thanks
Vikas
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you can use the dependency viewer to look at the files on which XYZClient.Dll is dependent on.
I guess on some of the machines these files are missing.
Please remember to rate helpful or unhelpful answers, it lets us and people reading the forums know if our answers are any good.
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Do you need the VC++ redistributable installed on those PCs?
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Actually, I had compiled the VC++ DLL in debug mode and it was the issue. The moment I had release mode DLL. it worked fine.
Thanks
Vikas
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Hi All,
I am able to retrieve datatype of an object or variable like "System.Xml.XmlDocument" or System.String. I want to pass this as System.Type object to another method or function, so that they can know the type, as the other function takes the below parameters
func1(name as String, value as Object, type as System.Type)
Please advice me how can I pass "System.String" as type in to the function.
Thanks,
Aleem Mohammad.
NIIT technologies
abdul.aleem@niit-tech.com
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indian143 wrote: func1(name as String, value as Object, type as System.Type)
Pass it as type...
Please remember to rate helpful or unhelpful answers, it lets us and people reading the forums know if our answers are any good.
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You can get the type by using
Type t = GetType(System.String)
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Hi,
Yes but I get the type in string format as "System.Double". How can I type cast it as
Type t = GetType("System.Double") is it ok? or any other method. Please help me.
Thanks,
Aleem Mohammad,
NIIT technologies
abdul.aleem@niit-tech.com
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Hi All,
I got it, its Type.GetType("System.Double").
Thanks to all of you who tried to help. Thanks a lot.
Aleem Mohammad.
NIIT technologies
abdul.aleem@niit-tech.com
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There is no reason to send the type to the method.
It can use value.GetType() to get the actual type of the parameter, and this also prevents the situation where you send data as one type and the type information to be something different.
Despite everything, the person most likely to be fooling you next is yourself.
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