C#

public static void Delay(Double timeToTwiddle){
     DateTime end = (DateTime.Now).AddMinutes(timeToTwiddle);
     while (DateTime.Now < end) ;
}

public static void Delay(double years, double months, double days, double hours, double minutes, double seconds, double milliseconds){
     DateTime end = DateTime.Now;
     end.AddDays(days);
     end.AddHours(hours);
     end.AddMilliseconds(milliseconds);
     end.AddMinutes(minutes);
     end.AddMonths(months);
     end.AddSeconds(seconds);
     end.AddYears(years);
     while (DateTime.Now < end) ;
}

public static void Delay (double months, double days, double hours, double minutes, double seconds, double milliseconds){
     Delay(0, months, days, hours, minutes, seconds, milliseconds);
}
public static void Delay(double days, double hours, double minutes, double seconds, double milliseconds){
     Delay(0, days, hours, minutes, seconds, milliseconds);
}
public static void Delay(double hours, double minutes, double seconds, double milliseconds){
     Delay(0, hours, minutes, seconds, milliseconds);
}
public static void Delay(double minutes, double seconds, double milliseconds){
     Delay(0, minutes, seconds, milliseconds);
}
public static void Delay(double seconds, double milliseconds){
     Delay(0, seconds, milliseconds);
}
public static void Delay(double milliseconds){
     Delay(0, milliseconds);
}

public static void DelaySixYearsZeroMonthsZeroDaysZeroHoursZeroMinutesZeroSecondsAndSixMilliseconds(){
     DateTime end = DateTime.Now;
     end.AddMilliseconds(12);
     end.AddYears(6);
     while (DateTime.Now < end) ;
}

Verghese wrote:

comboID.DataSource = myDS.Tables["empDB"];
comboID.DisplayMember = "EmpID";

comboName.DataSource = myDS.Tables["empDB"];
comboName.DisplayMember = "EmpName";

comboProfession.DataSource = myDS.Tables["empDB"];
comboProfession.DisplayMember = "EmpProfession";

comboCountry.DataSource = myDS.Tables["empDB"];
comboCountry.DisplayMember = "EmpCountry";

George_George wrote:

For String.Empty, as you said, it represents a string initialized, but length is zero. Initialized means constructed (constructor called)?

string empty1 = "";
string empty2 = string.Empty;
string empty3 = new string('');

George_George wrote:

All variables initialized to String.Empty are pointing to the same memory address or not?

George_George wrote:

For String.Empty, as you said, it represents a string initialized, but length is zero. Initialized means constructed (constructor called)?

string

Rutvik Dave wrote:

If All the variables initialized to

String.Empty

Then They will point to different memory address

Rutvik Dave wrote:

It is not possible that you create two different reference type variables and they have same memory reference, unless you assign one variable to another.

Rutvik Dave wrote:

remeber that string is immutable. so every time you change the value it will be allocated and initialize with the new value again

Colin Angus Mackay wrote:

Rutvik Dave wrote:
It is not possible that you create two different reference type variables and they have same memory reference, unless you assign one variable to another.

That is correct, but it does not apply to the current situation as you are not creating different objects. You are referencing an existing object.

string str1 = "hello world";
string str2 = "hello world";
if (str1 == str2) Console.WriteLine("same reference");

leppie wrote:

Erm, == is overriden for string