Visual Basic

SteveNY wrote:

I do have two binding sources.

One binding source for orders and one for prices.

SteveNY wrote:

I used a combobox so user can select a price from available prices but I'm open to suggestions for other controls to use.

<br />
<br />
  Dim nameComboBoxColumn As New DataGridViewComboBoxColumn<br />
<br />
        With nameComboBoxColumn<br />
<br />
            .HeaderText = "names"<br />
            .Items.Add("john doe")<br />
            .Items.Add("jane doe")<br />
            .DisplayStyle = DataGridViewComboBoxDisplayStyle.Nothing<br />
<br />
<br />
        End With<br />
<br />
        DataGridView1.Columns.Add(nameComboBoxColumn)<br />
<br />

SteveNY wrote:

It's not that the data isn't showing up. It's the fact that I have to click the column multiple times in order for the data to show up.

SteveNY wrote:

I made a separate demo app to show what I mean.

I put a datagridview on an empty form and in the form's load event I have this code:

... When the app loads the data is not shown in the column until I click the column.

Dim origBitmap As Bitmap ' This is the original image you created from the database
Dim copyBitmap As New Bitmap(origBitmap.Width, origBitmap.Height)
Dim g As Graphics = Graphics.FromImage(copyBitmap)
g.DrawImage(origBitmap, New Rectangle(0, 0, copyBitmap.Width, copyBitmap.Height), _
    0, 0, origBitmap.Width, origBitmap.Height, GraphicsUnit.Pixel)
origBitmap.Dispose()
g.Dispose()
' The copy of the bitmap is in copyBitmap.  This is the one you use in the rest of your code.

            Dim ar(dataLength) As Byte<br />
<br />
            myReader.GetBytes(0, 0, ar, 0, dataLength)<br />
            myReader.Close()<br />
<br />
            Dim b As New MemoryStream(ar)<br />
<br />
            picView.Image = Image.FromStream(b)

Dim ar(dataLength) As Byte

myReader.GetBytes(0, 0, ar, 0, dataLength)
myReader.Close()

Dim b As New MemoryStream(ar)
Dim origBitmap As Bitmap = Image.FromStream(b)
... ' The rest of the code to copy the Bitmap goes here.
... ' Then you can tell the picturebox to show the image.
picView.Image = copyImage

<br />
try<br />
course = GetCourse(courseid)<br />
catch<br />
'error handle<br />
end try<br />
if course is nothing then<br />
' do something<br />
else<br />
'do something else<br />
end if<br />

<br />
try<br />
if GetCourse(courseid, course) then<br />
' do something<br />
else<br />
' do something else<br />
end if<br />
catch<br />
' error handle<br />
end try<br />

Kevin Brydon wrote:

If the first function handled all its exceptions internally it would return nothing when there was database error or there was no course with that ID in the database. The calling method wouldnt be able to tell what really happened.

Kevin Brydon wrote:

i dont think the calling method should care about how the function failed, just whether it did or not.

Kevin Brydon wrote:

Allowing the functions to throw out exceptions in my opinion is a bad idea if you can just handle them internally.