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i need c++ code for aprogram that find e^0.5 using taylor formula with tolerance of 0.05%.
knowing that taylor formula for e^x=1+x+x2/2!+.......+x^n/n! plzzzzzzzzzz i need this code if any one could help me and thanx alot. aneet it before this monday plzzzzzzzzz
eva
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If you are not Kyle we care even less. I realize you have no idea what I am talking about because you have not read any of the posting guidelines for the site. Good luck with your studies and homework assignments. It's seems you will need it.
led mike
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I cannot guarenee its right, you will have to debug it yourself, but something to get you started
#include <math.h>
int main(void)
{
double current = 1;
double old = 0;
int n = 1;
int factorial = 1;
while(fabs(current - old) > 0.05/100)
{
old = current;
factorial *= ++n;
current = pow(old, n) / factorial;
}
}
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Well, you know the formula...What is your trouble about?
If the Lord God Almighty had consulted me before embarking upon the Creation, I would have recommended something simpler.
-- Alfonso the Wise, 13th Century King of Castile.
This is going on my arrogant assumptions. You may have a superb reason why I'm completely wrong.
-- Iain Clarke
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I need to command line program that starts other command line applications in their own window.
I can use spawn or ecec to run the programs but they run in the main window, not their own. I tried using ShellExecute, but I got a linker error. Does a DOS terminal window have a program name I can call using system or spawn?
Any suggestions?
Thanks
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malaugh wrote: but they run in the main window, not their own
use CreateProcess[^]and set CREATE_NEW_CONSOLE in their process creation flag.
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Thanks. FYI I found another method. If you open a cmd window and type "start myprogram.exe", the program will start in another window, so in my program I used:
system("start myprogram.exe");
I will your method also and see which works best.
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malaugh wrote: I tried using ShellExecute, but I got a linker error.
Did you link with Shell32.lib? If so, what was the linker error?
"Normal is getting dressed in clothes that you buy for work and driving through traffic in a car that you are still paying for, in order to get to the job you need to pay for the clothes and the car and the house you leave vacant all day so you can afford to live in it." - Ellen Goodman
"To have a respect for ourselves guides our morals; to have deference for others governs our manners." - Laurence Sterne
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My mistake, I must have coded it wrong the first time. I tried it again using:
ShellExecute(0,0,"myprogram.exe",0,0,SW_SHOWNORMAL);
and it worked. I sued a more complex example last time, must be something to do with the options.
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Hi!
I've been searching the Internet on how to detect if somebody are using any shared folder on my computer.
My little app is a small remotely programmable server I have to start video recordings computer. It shuts down the computer automatically
if no recording is to be done within 2 hours. However, I don't want
it to shut down while downloading.
No my question. How do I detect if I (or somebody) is using any shared folder? I've been searching everywhere without any luck. To be honest
I really don't now exactly what to search for.
TC
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Member 2419650 wrote: I've been searching the Internet on how to detect if somebody are using any shared folder on my computer.
Such as NetConnectionEnum()?
"Normal is getting dressed in clothes that you buy for work and driving through traffic in a car that you are still paying for, in order to get to the job you need to pay for the clothes and the car and the house you leave vacant all day so you can afford to live in it." - Ellen Goodman
"To have a respect for ourselves guides our morals; to have deference for others governs our manners." - Laurence Sterne
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Yes that was exactly what I needed.
Thank you very much. 
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Hi, may I ask you some personal suggestion?
I have a FILELIST class, containing a list of "file-objects" (doens't matter what they really are).
I expect that all of these function could be useful
char* getFileNames() ; //Returns a string containing file names appended to each other with a
//certain separator
string getFileNames() ; //The same as above, but using <string> class (maybe the least useful)
vector<string> getFileNames(); //Returs a vector of strings, each one containing a single file
As I can't overload functions with different return types (that's right?), I need to name
them in different way.
Do you have suggestions?
getFileNamesAsChar? getCharFileNames? getFileNames_char? char_getFileNames?
getFileNamesVector?
Unleash your fantasy, and help me in finding a good style..
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How about something like:
class FILELIST
{
public:
getFileNames(char *);
getFileNames(string);
getFileNames(vector);
};
"Normal is getting dressed in clothes that you buy for work and driving through traffic in a car that you are still paying for, in order to get to the job you need to pay for the clothes and the car and the house you leave vacant all day so you can afford to live in it." - Ellen Goodman
"To have a respect for ourselves guides our morals; to have deference for others governs our manners." - Laurence Sterne
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Adding to other reply, since your class is already a list why you create a list in other forms (char *, string, vector) every time in the function call getFileNames() instead giving functioality to the class to get element of list will be useful.
class FILELIST
{
int size(); // returns number of elements in list
char *getName(int pos); // return the string corresponding to position in list.
// iterator
char *getFirst();
char *getNext();
};
or how about making use of STL itself;
typedef vector<string> FILELIST; or
typedef vector<char *> FILELIST;
or
class FILELIST: public vector<string>
modified on Friday, March 21, 2008 9:44 AM
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Yeah, your observation is right.
Actually, my FILELIST class is substantially based on the private variable
vector<cfileinfo></cfileinfo> files, where CFILEINFO is the class I use to store info about files.
I often need to retrieve quickly a string containing all the files in the list, with a certain format,
e.g.
"c:\goofy\nc:\mickeymouse\n" and so on.
The ideas were
1) Create a FILELIST class, in which functions like char* = getFileNames() were included
2) Create public functions that wanted as argument a vector, so like char* = getFileNames(const vector<cfileinfo> files)</cfileinfo>
I didn't know what the best solution was, even because I haven't a very complete plan of my project, at the moment.
I chose the first one.
Now, if I think about the idea proposed by DadivCrow, the use of a class like in 1) would be the best, 'cuz I can overload functions. If I use main functions, I couldn't overload them like
getFileName(const vector<cfileinfo> &myFiles, char* myList) ;<br />
getFileName(const vector<cfileinfo> &myFiles, vector<string> myList) ;</string></cfileinfo></cfileinfo>
So, I think I'll use solution #1) with DavidCrow suggestion.
What do you think?
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I'm still not satisfied.
I think that writing such a code
cout << "\n This is myList Content:" << "\n" << myList.getCharFileNames() ;
is more effective than this one
<br />
char *buff ;<br />
myList.getFilename(buff) ;<br />
cout << "\n This is myList Content:" << "\n" << buff ;
And so, I think DaveCrow's philosophy doesn't suit to me.
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Capitanevs wrote: And so, I think DaveCrow's philosophy doesn't suit to me.
I was simply addressing your question, "As I can't overload functions with different return types (that's right?), I need to name them in different way. Do you have suggestions?" The rest is up to you.
"Normal is getting dressed in clothes that you buy for work and driving through traffic in a car that you are still paying for, in order to get to the job you need to pay for the clothes and the car and the house you leave vacant all day so you can afford to live in it." - Ellen Goodman
"To have a respect for ourselves guides our morals; to have deference for others governs our manners." - Laurence Sterne
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you can still use DavidCrows comment, if the function returns the same "char *" which is taking in.
char * FILELIST::getFilename(char *buff)
{
.....
return buff;
}
....
char *buff ;
...
cout << "\n This is myList Content:" << "\n" << myList.getFilename(buff) ;
or giving an operator overloading.
class FILELIST
{
public:
operator const char *()
{
return m_szListString;
}
private:
char m_szListString[MAX_LIST_STRING];
};
then (const char *)myList will give the string and you can directly use in cout as,
cout << "\n This is myList Content:" << "\n" << myList;
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That could be a good solution, great!
I'll turn to more substantial problems now.
Tnx u all
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I have this small snippet where 'a' is of short datatype.I am sending the address of short to one of the function ,another function returns the void pointer ,i want to typecast this void pointer to long but am not getting the right answer as 10 but it is giving garbage value.But if i type cast to short it gives proper value 10.For reference i am adding the code.
Plz reply me back as soon as possible.
#include<stdio.h>
void *temp;
void
call_func(void*);
void* ret_val();
int
main()
{
int a;
long b=0;
short* c;
a=10;
call_func(&a);
b=*((long*)ret_val()); ///if *((short*)ret_val)) gives proper value
c=ret_val();
printf("%ld\n",b);
printf("%d\n",*c);
return 0;
}
void
call_func(void* arg)
{
temp=arg;
}
void* ret_val()
{
return temp;
}
Thanks in Advance.
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Of course you can't cast from void* to short*; maybe, if you use an explicit cast, you could.
But, I question & wonder myself, why do you have to manage a void* returning function?
Did you build it by yourself or was it somewhere?
bye
M
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First thing, please read the posting guidelines at the top of the forum: format the code with the <pre> tags, it is quite difficult to read right now.
Member 4478833 wrote: I have this small snippet where 'a' is of short datatype.
That's not what you have in your code: there it is an integer, not a short. Anyway, if it is a short then your code cannot work: basically what you are doing is converting from a pointer to short to a pointer to long. A short is 2 bytes and a long is 4 bytes. So, guess what happens ? The pointer to long will 'see' two bytes more that were not initialized by the short and those of course contains garbage.
Anyway, why are you doing stuff like that ? Playing with void pointers is something that you probably want to avoid (unless you are doing plain C progrmming).
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hello,
I am obliged by your reply.I am aware of the situation you have mentioned ,but the problem is i have to implement the thing in the project i am working ,where the address i am sending to the void* can be of long ,char* or integer data type(so used void*),I before hand know its datatype ,if datatype is integer i typecast to long ,but i cant typecast for short.The predefined datatype mentioned in my code is either Long,Float,char*,Now i am facing problem if the address sending to the void* is short Variable ,with other datatypes i have not faced this problem...So i thought may b there is some solution for this which i am not aware of.
It will be of great help if you give any alternative you have for this.
Thanks in advance.
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Member 4478833 wrote: c=ret_val();
Assuming you fix this syntax error, both printf() statements print 10. 
"Normal is getting dressed in clothes that you buy for work and driving through traffic in a car that you are still paying for, in order to get to the job you need to pay for the clothes and the car and the house you leave vacant all day so you can afford to live in it." - Ellen Goodman
"To have a respect for ourselves guides our morals; to have deference for others governs our manners." - Laurence Sterne
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