C / C++ / MFC

Stephen Hewitt wrote:

which function is called depends on the type the expression is assigned to.

Stephen Hewitt wrote:

You can use this with templates too

// VanillaConsole.cpp : Defines the entry point for the console application.
//
 
#include "stdafx.h"
#include <iostream>
using namespace std;
 
struct Magic
{
	template <typename T>
	operator T() const
	{
		return 0.1234012340123401234;
	}
};
 
int main()
{
	Magic m;
 
	int i = m;
	float f = m;
	double d = m;
 
	cout << "i=" << i << ", f=" << f << ", d=" << d << endl;
 
	return 0;
}

// VanillaConsole.cpp : Defines the entry point for the console application.
//
 
#include "stdafx.h"
#include <iostream>
#include <typeinfo>
using namespace std;
 
struct Magic
{
	template <typename T>
	operator T() const
	{
		cout << typeid(T).name() << endl;
		return T();
	}
};
 
int main()
{
	Magic m;
 
	int i = m;
	float f = m;
	double d = m;
 
	return 0;
}

George_George wrote:

I am confused if T is int, what is T()?

toxcct wrote:

it's not a static function, nor a singleton.

"You better pass to managed code."

Dieghito wrote:

Yes, but both methods use data member ...

class ABC
{
public:
  int m_i;
  int m_i2;
  void MyFunc() { cout<<"hello atl";}
};

void main()
{
  ABC *c= NULL;
  int * p = &(c->m_i); 
  int * p2 = &(c->m_i2); 		
}