ASP.NET

using System.ComponentModel;<br />
using System.Windows.Forms.Design;<br />
using System.Design;<br />
using System.Drawing.Design;

[Editor(typeof(FileNameEditor), typeof(UITypeEditor))]
public string PostbackURL
{
    get
    {
        return ImageButton.PostBackUrl;
    }
    set
    {
        ImageButton.PostBackUrl = value;
    }
}

thomas_joyee wrote:

What about window.print()?

Request.UserHostAddress

function checkKeyStroke(e) {<br />
  var characterCode;<br />
<br />
  if ( e && e.which ) {<br />
    e = e;<br />
    characterCode = e.which;<br />
  }<br />
  else {<br />
    e = event;<br />
    characterCode = e.keyCode;<br />
  }<br />
<br />
  if ( characterCode == 13 ) { // 13 is the ASCII character code for the enter key<br />
    // Add logic here to handle the key stroke<br />
 }<br />
}