C / C++ / MFC

17-Dec-07 0:48

What is your date variable type?

If the Lord God Almighty had consulted me before embarking upon the Creation, I would have recommended something simpler.
-- Alfonso the Wise, 13th Century King of Castile.

Re: add int to date

Maximilien17-Dec-07 0:59

Maximilien

17-Dec-07 0:59

what about CTime and CTimeSpan ?

Maximilien Lincourt
Your Head A Splode - Strong Bad

Re: add int to date

Try17-Dec-07 1:09

Try

17-Dec-07 1:09

Thank you, i got the soln
I am using COleDateTime and COleDateTimeSpan.
COleDateTime d;
COleDateTimeSpan s(2,0,0,0);
d::GetCurrentTime();
d = d + s;

Http Parser Library

ktm TechMan17-Dec-07 0:15

ktm TechMan

17-Dec-07 0:15

Can anybody suggest a light weight HTTP parser library(DLL) preferably open source?

Count words in a string

CodingLover16-Dec-07 23:33

16-Dec-07 23:33

Hi all,

I want to find the number of words in a string. That string only contain whitespace, tab space and the new line character. So I code it as follows.

int numberOfWords = 1;
string st(pBuffer);

for(int i = 0;i <= st.length(); i++)
{
    // Whitespace and tab space
    if(pBuffer[i] == ' ')
    {
        numberOfWords ++;
    }
            if(pBuffer[i] == '\t')
            {
                    numberOfWords ++;
            }

    // Newline
    if(pBuffer[i] == '\n')
    {
        numberOfWords ++;
    }

}

cout << "\n" << numberOfWords;

But this code is odd. I mean say there is a whitespace and a tab space are occur with each other. Then the result is wrong. How can I avoid such odd points there.

I appreciate your help all the time...
Eranga Smile | :)

Nelek16-Dec-07 23:58

Nelek

16-Dec-07 23:58

Eranga Thennakoon wrote:
I mean say there is a whitespace and a tab space are occur with each other

Take a look if the character at i-1 and i+1 are valid before increasing the counter.

Eranga Thennakoon wrote:
int numberOfWords = 1;

BTW... if you are asking about 2 spaces or 2 tabs together... then you should take care on empty buffer, so start in numberOfWords = 0 :P

Greetings.
--------
M.D.V. Wink | ;)

If something has a solution... Why do we have to worry about?. If it has no solution... For what reason do we have to worry about?
Help me to understand what I'm saying, and I'll explain it better to you
“The First Rule of Program Optimization: Don't do it. The Second Rule of Program Optimization (for experts only!): Don't do it yet.” - Michael A. Jackson

CodingLover17-Dec-07 0:12

17-Dec-07 0:12

Nelek wrote:
Take a look if the character at i-1 and i+1 are valid before increasing the counter.

Or should I check i and i+1. I'll use it and failed.

Nelek wrote:
if you are asking about 2 spaces or 2 tabs together

I've change my code as this.

bool isLastCharBlank = true;
int iWordCount = 0;

char * szTemp = szInputString;

while(*szTemp)
{
    // Whitespase, tab and newline
    if ((*szTemp == ' ') || (*szTemp == '\n'))
    {
        isLastCharBlank = true;
    }

    else if (isLastCharBlank)
    {
        iWordCount++;
        isLastCharBlank = false;
    }
    szTemp++;
}
cout << iWordCount;

Since I've use a pointer to the string I can avoid such instances (I mean 2 spaces, 2 tabs, a tab and a space etc)

But now my question is how to avoid multiple new line characters at the end.

I appreciate your help all the time...
Eranga Smile | :)

CPallini16-Dec-07 23:58

16-Dec-07 23:58

What about:

int count=0;
int len = strlen(pBuffer);
int i =0;
for ( ; ; )
{
  while (pBuffer[i]==' ' || pBuffer[i] == '\t' || pBuffer[i] == '\n' && i < len)
  {
    i++;
  }
  if (i ==len ) break;
  count++;
  while (!( pBuffer[i]==' ' || pBuffer[i] == '\t' || pBuffer[i] == '\n') && i < len)
  {
    i++;
  } 
  if (i == len) break;
}

It is odd, but has a chance to work
Smile | :)

If the Lord God Almighty had consulted me before embarking upon the Creation, I would have recommended something simpler.
-- Alfonso the Wise, 13th Century King of Castile.

CodingLover17-Dec-07 0:35

17-Dec-07 0:35

Yes, it's work. But how can I avoid the multiple newline characters at the end.

Say my string is "One Two Three", and I've enter two times the enter key. So the the result is not 3, that is because of the additional new line characters. How can I avoid it. When I take the length it gives the length more than the original length.

I appreciate your help all the time...
Eranga Smile | :)

CPallini17-Dec-07 0:43

17-Dec-07 0:43

Do you mean CR-LF pair? I f the answer is yes, then you have to handle the carriage return '\r' character too, for instance

...
while(pBuffer[i]==' ' || pBuffer[i] == '\t' ||
      pBuffer[i] == '\n' || pBuffer[i] == '\r' && i < len)
...

and so on

If the Lord God Almighty had consulted me before embarking upon the Creation, I would have recommended something simpler.
-- Alfonso the Wise, 13th Century King of Castile.

CodingLover17-Dec-07 0:59

17-Dec-07 0:59

Oki, I got your point. But now I'm really confusing, if I've not take the definition in wrong way. That is, carriage return can be occur within a string? My initial code detect only the final newline characters, not within the string.

Can you explain it little more. Smile | :)

I appreciate your help all the time...
Eranga Smile | :)

CPallini17-Dec-07 1:01

17-Dec-07 1:01

Eranga Thennakoon wrote:
That is, carriage return can be occur within a string?

In fact, any caratter can.

Smile | :)

If the Lord God Almighty had consulted me before embarking upon the Creation, I would have recommended something simpler.
-- Alfonso the Wise, 13th Century King of Castile.

CodingLover17-Dec-07 1:07

17-Dec-07 1:07

That is interesting, and I found that another thing also. When I use your code line that multiple newline at the end avoided.

Ok, say I type a word then any number of spaces, tabs the answer is right. If I add a newline after all those things, the answer is added one more. Only one and it is happened within the string. That mean carriage return can't avoid within the string???? or...??

I appreciate your help all the time...
Eranga Smile | :)

CPallini17-Dec-07 2:11

17-Dec-07 2:11

AS I suggested you can augment my code to intercept and discard carriage returns ('\r') as well as any other character.
Smile | :)

If the Lord God Almighty had consulted me before embarking upon the Creation, I would have recommended something simpler.
-- Alfonso the Wise, 13th Century King of Castile.

CodingLover17-Dec-07 16:28

17-Dec-07 16:28

Yep, I think so. It is the easiest way to do it. I'll work it out and if I got any issue back to here.. Big Grin | :-D

I appreciate your help all the time...
Eranga Smile | :)

toxcct17-Dec-07 1:28

toxcct

17-Dec-07 1:28

you could use a string tokenizer[^], and then just count the occurences (that mean, is the example above, count the vector size)...

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CodingLover17-Dec-07 16:33

17-Dec-07 16:33

Ok, I've read that page. But little bit difficult to me, because vectors and stuff in C++ are new topics for me. Anyway thanks for the link again, I'll try it after doing some works with vectors. Wink | ;)

I appreciate your help all the time...
Eranga Smile | :)