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Take a look at PInvoke and see what it can do for you. You are going to have to create a struct on the C# side to map across.
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If you are going to move the class into a dll anyway, consider reimplementing it a s a COM object with an interface. That can be wrapped in a Com Callable wrapper to give .Net access to the class.
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Hi,
how to save a file in local system without dialog message.
here i pass the file path propgramatically.not use the upload controls.
plz help me to solve the problem asap.
regards
venkat.
venkat
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Use the System.IO.File APIs. If that's not what you're looking for, you'll need to provide more information.
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Hi ,
string strBaglanti = "Provider=Microsoft.Jet.OLEDB.4.0; Data Source=ftakip.mdb";
// Baglanti nesnemiz:
OleDbConnection conBaglanti = new OleDbConnection(strBaglanti);
OleDbCommand komut = new OleDbCommand();
komut.CommandType = CommandType.Text;
komut.CommandText = "SELECT sum(F_TUTAR) as toplam FROM F_KAYIT where DURUM='BIZDE'";
komut.Connection = conBaglanti;
conBaglanti.Open();
lblToplam.Text = Convert.ToString(komut.ExecuteScalar());
F_TUTAR COLOUMN IS DECIMAL i wanna show it in lblToplam.Text .. but its show it like 1397 but it must be 1.397,00 Currency.
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You are going to have to use one of the string formatters.
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I am using a DataGridView and had to override the ProcessCmdkey and ProcessDialogKey to treat a enter like a tab. Reason being is with this application the user only uses the 10 key. My problem is that I need to validate a cell before moving on and if the validation fails, I need to put the focus back on that cell. I have tried to use the cell validating and several other methods to put the validation code and then used the following code to set the focus. It seems like it sets the focus but then process the tab.
dgvDetails.CurrentCell.Selected = false;
dgvDetails.Rows[e.RowIndex].Cells[e.ColumnIndex].Selected = true;
dgvDetails.CurrentCell = dgvDetails.SelectedCells[0];
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Did you try to set the cancel property of the Validation-event-args?
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That worked except instead of using the .value of the cell, I had to use the EditedFormattedValue. I am guessing this is due to a lifecycle issue. Thanks for your help
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I have a class with a static constructor. First time I access the class the static constructor gets executed and there an exception occurs. After that if I try to access any of the methods of the class I am getting the same exception that was occured in the constructor.
public class Test1
{
static Test1()
{
//some exception here - ExceptionTest
}
public static void LoadData()
{
//if I access this method then I am getting ExceptionTest everytime I call this method.
//The type initializer for 'X.Test1' threw an exception.
}
}
How do I get rid of this?
Thanks
Shubho
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Static constructor is used to initialize static data members as soon as the class is referenced first time
Go Through this link !!. It will help you
Static Constructor in C#[^]
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What is the exception? Copy the exception type, the exception message, and the line of code associated with that exception so we can help. I can say, that the reason you are getting an exception later on is solely due to the problem that is created within your static constructor. Any object that throws an exception while being constructed cannot be used anywhere in the code.
-Jeff
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Hi
I would like to know how would i display a messageBox in a web form. I know in Windows forms you would use something like
MessageBox.Show("Hello");
How could i show this kind of dialog box (or equivalent)on a web form, if a user clicks a button??
Cheers 
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if you want to use message box in your web page use Jvascript for that !!!
<code>
<script langauge="javascript" runat="Server">
void MessagBox(string s)
{
alert(s);
}
</script>
</code>
and on button Click call that function!!!
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Thanks for that
now i'd just like to know, if i had a hyperlink on my page and when the user clicked on that link a messageBox should appear.
How could i acheive this?? similar procedure using client side scripts??
Cheers
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Yes, You can use on link button and call that method onclick of that link !!!
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Hey ya'll,
Over the years ;
a) I've forgotten my geometry
b) Never really had a good handle on it
c) In class was flirtin with the girl in front of me
d) all of the above
Anyway having said that, my problem;
I'm working on a graphics application and am adding a line tool.
I want to define an area around the tool which I can use for hit testing.
My thoughts were to define a rectangle 5 pixels either side of the line and the length of the line but I just cannot get a handle on it??
The line can be at any angle and be of any length.
------------------------ Upper boundry (??)
------------------------ The line
------------------------ Lower boundry (??)
Thanks ya'll,
Mike
Life is not measured by the number of breaths we take, but by the
moments that take our breath away. "George Carlin"
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You mean 5px above, and 5px below? Or 2.5px above and below?
Either way, you need to calculate the angle of the line, which basically is:
int lenX = startX-endX;
int lenY = startY-endY;
float length = sqrt(lenX^2 + lenY^2);
float angle = inverse cos(length/lenX)
Check up on google, there's lots of maths there.
My current favourite word is: Bauble!
-SK Genius
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Thanks for the help, will give it a try. Something so simple, guess I was over engineering it!
Mike
Life is not measured by the number of breaths we take, but by the
moments that take our breath away. "George Carlin"
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Hi Mike,
what you need is algebra, not geometry.
a straight line can be represented by a*x + b*y + c = 0
having two points (x1,y1) and (x2,y2) you can find a,b,c (except for an
arbitrary scale factor).
The orthogonal distance of an arbitrary point (x,y) to that same line is given
by a*x + b*y + c which is obviously zero for all points on the line.
So for hit testing I would:
- calculate a,b,c once
- checking a*x + b*y + c is sufficiently small
- for a finite line segment: also checking x is in an acceptable range
smallest of x1 and x2 minus some, largest of them plus some; same for y.
BTW: officially you should normalize the scale factor such that e.g.
a*a+b*b+c*c=1; in reality you can skip that and replace the distance check by:
(a*x + b*y + c)^2 small with respect to a*a+b*b+c*c
FYI: there is a completely different way to do all this:
create a memory-based bitmap where you draw the same line with a much thicker pen,
of a selected color; now just sample the color at (x,y) to see whether it is
part of the thick line. This also works for more complex shapes and drawings
provided you use different colors for different pickables (a problem will arise
where they overlap though).
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Luc,
Thanks thats exactly what I needed. Had the slope, deltaX and deltaY and from that calculated the angle but got stuck there. I guess what I thought would be easiest would be to find the 4 points perpendicular to the line and just do a rectangle.contains(point).
Thanks,
Mike
Life is not measured by the number of breaths we take, but by the
moments that take our breath away. "George Carlin"
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No, the sides of a rectangle are always parallel to the axis - but you can do something similiar with Path/Region - structures.
Let's say you've got the endpoints (x,y) and (x',y') of your line, then the vector perpendicular to this will be
(- y'+ y,x' - x). Normalize this with the reziprocal of the length: l = sqrt((x'-x)^2 + (y'-y)^2) and you get an
vektor (vx,vy) (vx = -(y'+y)/l, vy = (x'-x)/l),
now you add (d = desired width) d/2*n and -d/2*n to the endpoints to get 4 new points that define the outline of your shape (use a path with this 4 points to create a region).
Now you only have to add two circles with radius d/2 and centers of your original endpoints of the line to the region and you have a region describing the desired neighbourhood - and you can do Hittesting in it
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CKnig,
Thanks, appreciate the help!
Mike
Life is not measured by the number of breaths we take, but by the
moments that take our breath away. "George Carlin"
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Hi,
I have this formula -
Double i_decel_rate = ((Convert.ToInt32(textbox1.Text) * 10000) / Convert.ToInt32(textbox2.Text));
But for some reason the double doesn't display as double - like a value 7.98 is shown as 7 - it is not showing the decimals - but does display the integer value. I am using a text box to display this value - is there a way in webforms to print a value? Like the windows forms has messagebox.show()?
is anything off with the syntax?
thanks.
modified on Monday, December 10, 2007 8:41:47 AM
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