|
I Never Look Behind wrote: how will i achieve this?
1 - Create a class which contains all these fields required. Assign value to the class fields and store class object in session which can be access in all these three pages. Remove the session after insertion to the database in final page.
2 - Create a temporary table and store the details over there. After insertion remove these values.
3 - If your information is not sensitive, pass it through querystring.
|
|
|
|
|
i hvae already done this using session but i want ot do this using some other different thing.
|
|
|
|
|
I Never Look Behind wrote: already done this using session but i want ot do this using some other different thing.
What about the 2nd and 3rd suggestion give by me ? Is that the different method you need. Why you need to try different method if session's are working as expected ?
|
|
|
|
|
Actuall it is a 7-step registering process 7 each step have large amount of data.
|
|
|
|
|
I Never Look Behind wrote: Actuall it is a 7-step registering process 7 each step have large amount of data.
Then you could put all the controls required in one single page and hide/show it using javascript. Since all the controls are in single page, you will be able to access all of them and update accordingly.
|
|
|
|
|
But all the steps are compulsory & if we put all control in a single page then it will become very complicated.
|
|
|
|
|
I Never Look Behind wrote: But all the steps are compulsory & if we put all control in a single page then it will become very complicated.
 This is ridiculous, You don't want to use all the 3 methods which is specified in the first post, you don't want to use all controls in single page and separate using JS. So how you are planning to do ? And I am not getting why you don't want to use all these.
|
|
|
|
|
The most optimized solution to this requirement is property.
Create a class with all these properties Name,Address,email etc.. and assign value to these properties and either pass it to another page or put it in session...
You can directly also put all these values in session...
|
|
|
|
|
Use Wizard control. you have no need to use multiple page.
bEst Regard
pAthan
please don't forget to vote on the post that helped you.
|
|
|
|
|
|
1. You can use Server.Transfer Method and Cross Page Post Feature which will allow you a normal post back but to a different page in the application. In the New page you access the values of the Previous Page using the PreviousPage property.
[or]
2. You can Use Wizard Control which will help you to create a multi-step form entry process in a web page.
- Regards -
JON
Life is not measured by the amount of breaths we take, but by the moments that take our breath away.
|
|
|
|
|
|
Hi,
I am new in .net. I am making an application using datagrid which is showing details about employees. So I want to make my data grid searchable. So i am using a textbox where user can enter some data into it and the matching result with all the columns will be displayed in the datagrid. If anyone knows how to do it or anyone hav a code for it. Please reply me
Rocki Star
|
|
|
|
|
You can try the following methods
1- When user enters search criteria, goto database and fetch the records and rebind the DataGrid.
2- When datagrid is initially binded, keep datasource in a session or viewstate, and do search on that datasource. If you are using DataTable to bind the grid, you can use Select() method to search the records.
|
|
|
|
|
Actually I am planning for that it will search for the criteria in all the column in datagrid. Search criteria is not restricted to only one column. So is there any method or event in datagrid which can help me.
http://www.preterra.com/flexsamples/gridsearch/gridsearch.html[^]
This is how one guy has achieved it using datagrid but he hasn't uploaded his code
Is it possible for me to do it in this style.
Thank You N a v a n e e t h
Rock Star
|
|
|
|
|
Rock Star. wrote: I am planning for that it will search for the criteria in all the column in datagrid.
Yes you can do as I specified in the first post. Assume your DataGrid is binded with a DataTable object. DataTable comes with a select(DataTableObject.Select()) method where you can write queries. So form a query which looks for the matches in all the columns when user clicks search, pass it to the select method on the DataTable object.
You can keep the DataTable object in Session/ViewState.
|
|
|
|
|
Search for the same in your dataset or datatable and display particular row...
For doing the same you can loop through all the rows present in ur datasource(dataset or wotever u r using)
|
|
|
|
|
hi
if you are binding a dataset to the grid then it is very easy....
filter the dataset with the value entered in the text box
dataset.select(
|
|
|
|
|
joemonvarghese wrote: if you are binding a dataset to the grid then it is very easy....
filter the dataset with the value entered in the text box
dataset.select(
WRONG. Dataset don't have Select() method.
|
|
|
|
|
how i can down a file named say abc.tif from server ..for time being the server and the clinet machine are the same.
|
|
|
|
|
Saving file can be done by different methods now it depends how u r getting the file like user is browsing a file or you are getting file in stream.... etc.
some methods are
File.Create(string path);
and
File.WriteAllBytes("../",Buff[]);
Specify what you doing and what you want exactly..
|
|
|
|
|
Prateek G wrote: File.WriteAllBytes("../",Buff[]);
This can't save a file from server to client. ASP.NET won't be having permission on the client machine to do anything.
|
|
|
|
|
 Sorry, you are right these permissions are machine specific...
Then Response.BinaryWrite(Byte[]);
Response.End()
Will give a popup which will allow user to save file...
|
|
|
|
|
hi sir ,actually i am having a abc.tif in the server.when clinet click a down load button this file has to download ..and when client again click sava then a save as pop diolog has to come to specify where to save this server file in the clinet machine ..will u give excat code...
|
|
|
|
|
Try something like this...
<br />
string sourceFile = "abc.tif";
<br />
<br />
FileInputStream filIpStrm = null;<br />
MemoryStream ms = new MemoryStream();<br />
filIpStrm = new FileInputStream(sourceFile);<br />
sbyte[] buffer = new sbyte[1024];<br />
int len = 0;<br />
while ((len = filIpStrm.read(buffer)) >= 0)<br />
{<br />
byte[] bbuffer = new byte[1024];<br />
System.Buffer.BlockCopy(buffer,0,bbuffer,0,1024);<br />
<br />
ms.Write(bbuffer,0,1024);<br />
}<br />
Response.OutputStream.Write(ms.ToArray(), 0, Convert.ToInt32(ms.Length));<br />
<br />
filIpStrm.close(); <br />
Response.ClearContent();<br />
Response.ClearHeaders();<br />
Response.ContentType = "application/octet-stream";<br />
Response.AppendHeader("Content-Disposition", "attachment; filename=AAA.tif");<br />
Response.Flush();<br />
Just check how can you access the file like I have written directly Source file name, just check how can you get your file in byte[]....
|
|
|
|
General 
News 
Suggestion 
Question 
Bug 
Answer 
Joke 
Praise 
Rant 
Admin 
Submit an article or tip
