C / C++ / MFC

Re: CListCtrl problem: How to set the item state to selected state?

29-Oct-07 0:09

Have a look at SetItemState method.
Smile | :)

If the Lord God Almighty had consulted me before embarking upon the Creation, I would have recommended something simpler.
-- Alfonso the Wise, 13th Century King of Castile.

Nishad S29-Oct-07 0:12

Nishad S

29-Oct-07 0:12

Use SetItemState( -1, LVIS_SELECTED, LVIS_SELECTED );

- NS -

Re: CListCtrl problem: How to set the item state to selected state?

fantasy121529-Oct-07 1:04

fantasy1215

29-Oct-07 1:04

thx very much,
Actually I'm not sure about SetItemState, now I have your example.

CRectTracker

kk.tvm28-Oct-07 23:24

kk.tvm

28-Oct-07 23:24

Hi
In my program CRectTracker class is used to resize a window. How to control rectangle ( shadow rectangle draws while dragging mouse) while resizing the window. I use TrackRubberBand function.

thanks in advance

-RisKhan-

about time and time_t

George_George28-Oct-07 22:18

Re: about time and time_t

28-Oct-07 22:18

Hello everyone,

In MSDN for time function,

time_t time(
time_t *timer
);

http://msdn2.microsoft.com/en-us/library/1f4c8f33(VS.80).aspx

the return value of time is time_t, but in the Return Value section, it mentioned,

Return the time as seconds elapsed since midnight, January 1, 1970. There is no error return.

So, I am wondering whether time_t could be represented as elapsed number of seconds correctly and safely -- no data lost if we convert return value to unsigned long?

Like,

unsigned long second = time (NULL);

thanks in advance,
George

Roger Broomfield28-Oct-07 23:08

Roger Broomfield

28-Oct-07 23:08

In time.h

typedef long time_t;

Re: about time and time_t

George_George28-Oct-07 23:39

28-Oct-07 23:39

Thanks Roger,

Your answer is helpful!

regards,
George

DllRegisterServer

George_George28-Oct-07 21:57

28-Oct-07 21:57

Hello everyone,

I am wondering when function DllRegisterServer will be invoked? I am using Visual Studio 2005 to develop an in-process native (unmanaged) C++ COM. I am wondering when it will be invoked?

1. During the build process or during the DLL initialization process?
2. I find this function only works for debug mode, not release mode. Is that correct?

In MSDN,

http://msdn2.microsoft.com/en-us/library/ms682162.aspx

there are not too much information about when this method will be invoked and whether it works for both debug mode code and release mode code.

thanks in advance,
George

CPallini29-Oct-07 0:59

29-Oct-07 0:59

DllRegisterServer it's typically called when you need to register the COM component (for instance, by regsvr32). Note: usually Visual Studio registers the component as (if I remember well) a post build step.

George_George wrote:
2. I find this function only works for debug mode, not release mode. Is that correct?

No. The function must work also in release mode, otherwise you cannot deploy (the release mode) component.

Hope that helps.

Smile | :)

If the Lord God Almighty had consulted me before embarking upon the Creation, I would have recommended something simpler.
-- Alfonso the Wise, 13th Century King of Castile.

George_George29-Oct-07 2:10

29-Oct-07 2:10

Thanks CPallini,

I do not explicitly call regsvr32 in build process. For the build process, I
simply use Visual Studio 2005 IDE to build. Smile | :)

I suspect regsvr32 invokes DllRegisterServer since I set the following
option to yes in debug configuration,

Linker --> General --> Register Output to yes

But I am not sure. Any comments?

regards,
George

Paresh Chitte29-Oct-07 2:42

Paresh Chitte

29-Oct-07 2:42

George_George wrote:
I do not explicitly call regsvr32 in build process. For the build process, I
simply use Visual Studio 2005 IDE to build.

I suspect regsvr32 invokes DllRegisterServer since I set the following
option to yes in debug configuration,

Linker --> General --> Register Output to yes

Custom build step is at

Project | Properties | Custom Build Step | Command Line.

Here you will find something like

regsvr32  /s/c "$(TargetPath)"<br />
echo regsvr32 exec. time > "$(OutDir)\regsvr32.trg"

Regards,
Paresh.

That was VS6!

CPallini29-Oct-07 3:39

29-Oct-07 3:39

The OP was VS 2005 (quite similar indeed).
Smile | :)

If the Lord God Almighty had consulted me before embarking upon the Creation, I would have recommended something simpler.
-- Alfonso the Wise, 13th Century King of Castile.

Re: That was VS6!

George_George29-Oct-07 4:05

29-Oct-07 4:05

Yes, CPallini! I should be somewhere else as you pointed out.

regards,
George

George_George29-Oct-07 4:01

29-Oct-07 4:01

Thanks Paresh,

But there is nothing in Project | Properties | Custom Build Step | Command Line in my Visual Studio 2005. So I think there should be something else which runs regsvr32 to register the values in Windows Registry.

regards,
George

CPallini29-Oct-07 3:36

29-Oct-07 3:36

Your guess is exact, as Visual Studio documentation states:

Register Output
Run regsvr32.exe /s $(TargetPath), which is valid only on .dll projects. For .exe projects, this property is ignored. If you want to register an .exe output, set a postbuild event on the configuration to do the custom registration that is always required for registered .exe files.

Smile | :)

If the Lord God Almighty had consulted me before embarking upon the Creation, I would have recommended something simpler.
-- Alfonso the Wise, 13th Century King of Castile.

George_George29-Oct-07 4:03