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Thanks ohart but I tried to search this at support.microsoft.com but did not find this.
Can you please provide me the link for this article?
Thanks
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support.microsoft.com/kb/301982 contains the article.
Other articles are 242243 and 822750 (altho this one is a little harder to understand and get going, at least if you are new to VB.NET like I am).
OH
ohart
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hi...
how can i insert data to sql database...
plz, advice me...
thz a lot...
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if you want to be helped here you have to be specific.
you want to use an application front end to do that or you want to run a an insert statement into the database. be specific.
Vuyiswa Maseko
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Can we use non-english characters as listview column heading at run-time?
I mean when I add the columns for the listview at run time
listview1.columns.add("<b>I want to write Urdu word as heading</b>",100,Center)
Thanks In advance
Ejaz
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Yes U can certainly do that , i hav done that
dim lst as new listviewitem
Me.ListView1.BeginUpdate()
lst = ListView1.Items.Add("0")
lst.subitems.add("1")
lst.subitems.add("2")
lst.subitems(2).font = New Font(" U R Urudu Font", 16, FontStyle.Bold)
Me.ListView1.EndUpdate()
This code will Show The 2nd Column of u r listview in Urudu Language
Reply, How It Helped.
Prabumj
Prabumj@gmail.com
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Howdy folks  
This is my first time posting, very new to the whole Microsoft Development Paradigm, Primarily come from a Web Marketing, PHP, and MySQL background .
I'm pretty much learning trial by fire, and am looking at some classic Visual Basic 2003 code for a web admin. I'm used to full color coding, and it appears that Visual Studio 2003 does not differentiate between user defined functions and language functions. Both appear to be in black text.
I'm used to seeing something more along these lines
Where language centric (in this case PHP) functions are colored as bold green text and user defined functions are regular case and purple
Is there anyway of replicating this behavior inside of visual studio 2003 and visual studio 2005?
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Michaeljd wrote: Is there anyway of replicating this behavior inside of visual studio 2003 and visual studio 2005?
Nope. There's no way of telling them apart.
The are no "language-defined" functions in VB.NET. They're now done as Shared methods of various classes in the Microsoft.VisualBasic namespace. So, in essence, everything is a user-defined class/method now. There's no way to tell the difference between a predefined class in the .NET Framework and one that you can write yourself.
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thank you for your quick reply
That's strange, I would think because the language is strongly typed, and microsoft pretty much knows what classes they've written that it would be able to create some sort of addon that replicates this. Not so important to veteran users, but nifty for newbies.
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How I can add textboxes at run time?
I am using this method to add the control
Dim txtbox1 As New TextBox
Me.Controls.Add(txtbox1)
this works fine but I want to create controls through loop
like
For i = 1 to mnumber 'mnumber can be different - sometimes it can be 4 or 5 or 10
I want to add textboxes like
txtbox1,txtbox2,txtbox3,txtbo4 and so on
next
How this can be solve.
Thanks In advance
Ejaz
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No problem, you should keep the references of the new TextBoxes in some kind of collection;
it could be an array, an ArrayList, a generic List, whatever. You can not have individual
identifiers ("variable names") for each of your TextBoxes when you create them in a loop;
if that is what you want (why should you?) then you need to use explicit statements
without a loop.
Dim myTBList as New ArrayList ' or some other list...
for i=1 to 10
Dim txtbox1 As New TextBox
Me.Controls.Add(txtbox1)
myTBList.Add(txtbox1)
next
Luc Pattyn [Forum Guidelines] [My Articles]
this weeks tips:
- make Visual display line numbers: Tools/Options/TextEditor/...
- show exceptions with ToString() to see all information
- before you ask a question here, search CodeProject, then Google
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You're kidding, right? You've already written all the code in your own post.
For i As Integer = 1 to 10
Dim newTB As New TextBox()
With newTB
' Setup your textbox position, size, ...
' and any other properties you want.
End With
Me.Controls.Add(newTB)
Next
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I have one combo box for months and one for weeks from (1 to 4).
If user select month March from the months combo box and then select week 3 from the weeks combo then I want application to provide the dates for the selected period.
Thanks In advance.
Ejaz
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First you have to decide what rule to use to determine which month a week belongs to. There is a rule to decide this for weeks in the year, are you going to apply the same rule on months that the current culture is using, or are you going to use a specific rule regardless of the current culture?
Then you have to decide how to handle the fifth week that occurs in some months.
---
single minded; short sighted; long gone;
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Thanks Guffa for ur reply
There are 2 combo boxes one for month and other for weeks
month combo has list for months like
January
Feburary
March
April
May
June
July
August
September
October
November
December
And week combo has list for weeks like
1
2
3
4
Now when user will select the week march and week 2 then I need the dates for that week of the period.
I am only using 4 weeks for all the months.
Any idea how to solve this?
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You are just repeating yourself.
Read my previous post, and if you don't understand it, specify what it is that you don't understand.
---
single minded; short sighted; long gone;
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I am communication to a device via serial cable. I have to send data in a packet with a type of check sum on the end of it. When I calculate my check sum CRC-16 I get 14643 as a total. Great! What I don't understand is I need to change that into the a <high> <low> checksum instead of the number 14643. To do this manually, I have been figuring out the 16 bit binary equivalent. and then looking at each 4 bits to determine the hexadecimal equivalent and slitting the first two hex and the second to get my <high> <low> check sums. How do I do this in code?
ex:
14643 is
0011100100110011 in Binary 16 bits
0011 1001 0011 0011
3 9 3 3 in Hex
<high> <low>
39 33 Append at end of output.
Does anyone know an easy way to code this? I looked on line and there is nothing that converts the 14643 to only 16 bits. It converts each digit to its binary equivalent.
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Hi Cory,
indeed the number that reads 14643 in decimal, reads 3933 in hex.
in C# you do that with:
int n=14643;
string s=n.ToString("X4");
which generates a string of at least four hex digits (i.e. it prefixes zeroes when
the "X" format would generate fewer than four digits because of a low value of n)
I now have installed Visual Studio VB.NET Express Edition, so I can answer in your
language; here it is, my very first VB.NET program ever:
Sub Main()
Dim n As Integer = 14643
Dim s As String = n.ToString("X4")
Console.WriteLine(s)
' or all in one line:
Console.WriteLine(14643.ToString("X4"))
' Keep console window open:
Console.ReadLine()
End Sub
Luc Pattyn [Forum Guidelines] [My Articles]
this weeks tips:
- make Visual display line numbers: Tools/Options/TextEditor/...
- show exceptions with ToString() to see all information
- before you ask a question here, search CodeProject, then Google
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You are thinking in hexadecimal, which is your problem. Hexadecimal is just a textual representation of numbers, but you don't want to send text.
14643 is<br />
0011100100110011 in binary 16 bits<br />
00111001 00110011 as two 8 bit values<br />
57 51 in decimal
A 16 bit value can be represented in little-endian or big-endian format. Intel system uses little-endian format, so you send the least significant byte first.
So, first you send the byte value 51, then the byte value 57.
You can use the BitConverter class to split the 16 bit value into two bytes:
Dim checksum As Int16 = 14643<br />
Dim bytes As Byte() = BitConverter.GetBytes(checksum)
You now have an array that contains two bytes, 51 and 57.
---
single minded; short sighted; long gone;
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Hi Cory,
once more you confused me:
in an earlier post[^] you asked for converting a string into a byte array holding the ASCII
characters, indicating you want to send text (but you needed the byte array so you could
insert non-printable characters such as hex 01, 02 and 03 IIRC).
Now you get two completely different replies on your checksum question; mine is
generating a hex string (which would need to go through the string-to-bytearray process),
Guffa's is generating two bytes that are not ASCII characters at all (and at a specific
byte order you never specified as far as I can remember).
So I don't see how this all fits together.
If this still is about the thing that started as a CRC-16 question, you are taking a long
and scenic route through the binary/text and decimal/binary/hex worlds.
It might be a good idea for you to publish a couple of complete, valid messages (e.g.
using hex byte values) with indications what is what; doing so would help us understand
what your questions are about, and how they fit in the overall scheme of things.
It's just a thought.
Greetings
Luc Pattyn [Forum Guidelines] [My Articles]
this weeks tips:
- make Visual display line numbers: Tools/Options/TextEditor/...
- show exceptions with ToString() to see all information
- before you ask a question here, search CodeProject, then Google
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Hi,
Is there is any way to add a listview in datagrid like nested datagrid?
I want a main datagrid with +/- button to expand and collapse the item.Now I want to add a listview within the datagrid.
Thanks In Advanc
Ejaz
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I have done nested datagrids before. If you google it you should find several topics on it. However, I think most of the code is C#.
_____________________________________________
Flea Market! It's just like...it's just like...A MINI-MALL!
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Hi,
I have a confusion regarding storage of instances in VB.net . I am dynnamically creating pictureboxes in response to a user click at runtime. I am then adding them to 2 different ArrayLists (as i need to use them while maintaining 2 different orders). Now would this create 1 instance of the object in memory or waste resources by creating 3 different pictureboxes? If it will, then whats the way to store a reference as you can in C++ using the & operator?
Thanks,
Ahmad
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