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This would be a great solution...but how I can do this?
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The tricky part is customizing the >> operator. Have a look, for instance, at this article http://www.codeproject.com/cpp/Encoder.asp[^].
If the Lord God Almighty had consulted me before embarking upon the Creation, I would have recommended something simpler.
-- Alfonso the Wise, 13th Century King of Castile.
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Thank you...I will check this..
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If you're using this for logging purposes, why don't use CString::FormatV()?
Like this:
void <YourClassName>::Log( LPTSTR pText, ... )
{
CString LogText;
va_list args;
va_start( args, pText );
LogText.FormatV( pText, args );
}This would make the function call similar to printf().
"It's supposed to be hard, otherwise anybody could do it!" - selfquote
"High speed never compensates for wrong direction!" - unknown
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I think this is in the MFC library and I don't can use it...
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hansipet wrote: I think this is in the MFC library and I don't can use it...
Ok, then use vsprintf(). See here[^].
It works the same as the CString alternative, but in this case you have to provide the output buffer.
"It's supposed to be hard, otherwise anybody could do it!" - selfquote
"High speed never compensates for wrong direction!" - unknown
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Problem : my hook procedure is not working when the main window losts focus or minimized...
description:
i have written a global hook procedure to track the keystrokes. the hook procedure resides in a dll and i am calling it from the main window. from the dll i am displaying the keycode using a messagebox. it is working globally... then problem is when i tried to write the keypress to a file it is working but when the main window losts focus the keystrokes are not written to the file but it displayed... i tried to pass the value to the main window using WM_COPYDATA but neither of the options helped... i was able to reveice the WM_COPYDATA message in the main window only when the window is active and when my window goes inactive it dosent work... how to solve this... i am using dev C++ ide... i am using C style and not c++ or MFC...what should be done to make the main window always receive messages from the hook procedure???
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Hi to All,
How to manage Bitrate through Programming?
In my application during runtime, I am generating some data & transfering it to (any type of) Output (like IP Output, any type of Output Card, or writting a File). I have done it, but I want to transfer data at particular Bitrate to the Output.
Consider that I am sending generated data to IP, so how I can achieve it's transfer at particular bitrate?
When I was trying to transfer data at 2Mbps OR 3Mbps using MachineCycles & Sleep(1) at getting output bitrate as 749 Kbps with 1% Processing. But when I remove Sleep(1) I am getting out bitrate as 1.9Mbps OR 2.9 Mbps (respectively), with 61% of Procssing.
What is the solution to achieve bitrate transfer with low Processing?
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In my program I've got a base class (all member methods are pure virtual) which a number of classes are derived from. In a seperate class I want to have an array which contains pointers to these classes, i.e. it doesn't create the objects just has a pointer to them. My code loks like this so far:
<br />
class BaseClass<br />
{<br />
public:<br />
BaseClass( ) ;<br />
<br />
virtual<br />
~BaseClass( ) ;<br />
<br />
virtual void<br />
EveryClassNeedsThis ( ) = 0 ;<br />
<br />
private:<br />
BaseClass( const BaseClass &source ) ;<br />
<br />
BaseClass& <br />
BaseClass::operator= ( const BaseClass &rhs ) ;<br />
<br />
} ;<br />
<br />
class DerivedClassA : public BaseClass<br />
{<br />
public:<br />
DerivedClassA ( ) ;<br />
<br />
virtual<br />
~DerivedClassA ( ) ;<br />
<br />
void<br />
EveryClassNeedsThis ( ) ;<br />
<br />
private:<br />
DerivedClassA ( const DerivedClassA &source ) ;<br />
<br />
DerivedClassA & <br />
DerivedClassA ::operator= ( const DerivedClassA &rhs ) ;<br />
} ;<br />
<br />
class ArrayClass<br />
{<br />
public:<br />
ArrayClass ( ) ;<br />
<br />
virtual<br />
~ArrayClass ( ) ;<br />
<br />
void<br />
AddToArray ( BaseClass *obj )<br />
<br />
private:<br />
ArrayClass( const ArrayClass &source ) ;<br />
<br />
ArrayClass& <br />
ArrayClass::operator= ( const ArrayClass &rhs ) ;<br />
<br />
BaseClass *m_DerivedObjects ;<br />
} ;<br />
In the implementation for AddToArray I have
<br />
{<br />
m_DerivedObjects = obj ;<br />
}<br />
but i get an access violation on this, so can anyone spot what I'm doing wrong? 
TIA,
Andy
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morning blues even worse than I thought!
<br />
void<br />
AddToArray ( BaseClass *obj,<br />
int pos )<br />
<br />
BaseClass *m_DerivedObjects<br />
should be
<br />
BaseClass *m_DerivedObjects [10] ;<br />
and
<br />
m_DerivedObjects = obj ;<br />
should be:
<br />
m_DerivedObjects [pos] = obj ;<br />
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If you want to manipulate an array of objects (or pointers to objects if you want to use polymorphism), I highly suggest that you take a look at the container classes from the STL: vector, list, ...
Everything has been implemented and has been used by a lot of developers, so, chances of bugs are close to zero.
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Hi,
thanks for your reply, found out it wasn't the array causing the problem but that I was calling a non static method in a non-static manor (also the variables are not static either). 
cheers,
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My advice remains valid even if you found the bug  . Why reinvent the wheel when something free exist ?
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Hai i have some problem here.
1.
using namespace std;
int main()
{
char name[50];
char lastname[50];
char fullname[150];
char university[50];
char uni[100];
int age;
cout<<"Enter first name:";
cin.getline(name,50);
cout<<"Enter last name:";
cin.getline(lastname,50);
cout<<"Enter age:";
cin>>age;
cout<<"Enter University:";
cin.getline(university,20);
strcpy(fullname,name);
strcat(fullname, " ");
strcat(fullname,lastname);
cout<<"Your name:"<<fullname<<endl;
cout<<"your="" age:"<<age<<endl;
="" cout<<"study:"<<university<<endl;
}
2.
using="" namespace="" std;
int="" main()
{
="" char="" name[50];
="" lastname[50];
="" fullname[150];
="" university[50];
="" uni[100];
="" int="" age;
="" cout<<"enter="" first="" name:";
="" cin.getline(name,50);
="" last="" cin.getline(lastname,50);
="" university:";
="" cin.getline(university,20);=""
="" age:";
="" cin="">>age;
strcpy(fullname,name);
strcat(fullname, " ");
strcat(fullname,lastname);
cout<<"Your name:"<
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Try cin.ignore() or use fflush(stdin) to clear the buffer.
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thank you so much......now i have an idea...
thank you
mazeed
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thank you,
it is work..
i'm using cin.ignore()..
thank you so much...
mazeed
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Why are you using char[] variables with C++ when string variables would be way more efficient? Yeah, it's only a few hundred bytes, but that, coupled with not having to use strcxx(), is a good reason to switch.
"A good athlete is the result of a good and worthy opponent." - David Crow
"To have a respect for ourselves guides our morals; to have deference for others governs our manners." - Laurence Sterne
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Hi all:
I'm wondering how's the following code snippet could finish returning the final 'nn' to the caller, since I did not explicitly return 'nn' on each recursive call.
int ss(int n)<br />
{<br />
int nn;<br />
if (n)<br />
nn = (n + ss(n - 1));<br />
else<br />
return 0;<br />
}<br />
<br />
int n = ss(4);
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Actually it returns 0 on my system.
If the Lord God Almighty had consulted me before embarking upon the Creation, I would have recommended something simpler.
-- Alfonso the Wise, 13th Century King of Castile.
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LiYS wrote: I'm wondering how's the following code snippet could finish returning the final 'nn' to the caller, since I did not explicitly return 'nn' on each recursive call.
Compiler should issue warning about return path.
Prasad
MS MVP - VC++
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I guess accumulator register is used to store the return value,
Since the code donot execute the return statement except at the last,
the previous result in the accumulator n+ss(n-1) is taken as return value.
Thus we get the currect value. If you used return 1; instead of return 0;
you get 1 + the result;
Best Regards
Raj
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Yes, I guess you're right, add the following asm statement makes the program result logical to me. But what's the theory behind this?
int sum(int n)
{
int nn;
int dummy = 0;
if (n)
{
nn = (n + sum(n - 1));
__asm
{
mov eax, 0
}
}
else
return 0;
}
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There is nothing theoritical, It depends on the implementation of the compiler.
if _asm::call is the opcode for a function call, then it has to place its return value in some register/memory location;
I guessed it is some where on the return mechanism and verified in code dissassembly.
int n = ss(4); will be something like
push 4
call ss
mov dword ptr [n],eax
After a call, we need the return value, called subroutine places its return value in eax.
Iam not sure, the theory of VC++ compiler is available open, but i believe this depends on the compiler implementation, for instance gcc compiler may not behave the same, hence most compiler flashes warning some thing like "not all code path returns value"
Best Regards
Raj
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simply add some accumulator register involving operation next to nn = (n + ss(n - 1));
like another addition. It won't work as you expected.
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