ASP.NET

Sandeep Akhare23-Apr-07 0:23

23-Apr-07 0:23

PLease Don't put urjent in your post.

Thanks and Regards
Sandeep

If you want something you never had,
do something you have never done!

_AK_23-Apr-07 0:26

23-Apr-07 0:26

You changed your user name? Smile | :)

Any specific reasons for choosing "Warnings-Errors". Smile | :)

Best Regards,
Apurva Kaushal

Sandeep Akhare23-Apr-07 0:37

23-Apr-07 0:37

Apurva Kaushal wrote:
ny specific reasons for choosing "Warnings-Errors".

Yes i need to play with it daily and in forums also i face this word maximum time Smile | :)

Just kidding

Thanks and Regards
Sandeep

If you want something you never had,
do something you have never done!

_AK_23-Apr-07 0:53

23-Apr-07 0:53

Warnings-Errors wrote:
Yes i need to play with it daily

Part of life for almost all the developers. Smile | :)

Best Regards,
Apurva Kaushal

Sandeep Akhare23-Apr-07 0:48

23-Apr-07 0:48

Hi Apurva

Apurva Kaushal wrote:
You changed your user name?

Earlier it was Sandeep Akhare

Are you still in Hyderabad ?

Thanks and Regards
Sandeep

If you want something you never had,
do something you have never done!

_AK_23-Apr-07 0:51

How to get value in next pages

23-Apr-07 0:51

Yep man.. still there at same place. Smile | :)

Best Regards,
Apurva Kaushal

siddisagar22-Apr-07 23:52

siddisagar

22-Apr-07 23:52

Hi,

I have 10 pages in my project.In that webform1.aspx contains Empno textbox.I need this value in webform4.aspx.Pls tell me how to get First page textbox value in fourth page.I am navigating pages in 1,2,3,4 etc

Don't tell session .Tell me Other than session .Pls tell me different ways ?

Thanks.

Sandeep Akhare23-Apr-07 0:20

23-Apr-07 0:20

HI
There are many ways to do it Querystring and viewState is one of them ,
But i think you should store all those values which you need in the future
try this
Add in class file and create static string variables that will store your values

<br />
public class datacontainer<br />
{<br />
	public datacontainer()<br />
	{<br />
		//<br />
		// TODO: Add constructor logic here<br />
		//<br />
	}<br />
    static string _PersonId;<br />
<br />
    public static string PersonId<br />
    {<br />
        get {return _PersonId;}<br />
        set { _PersonId = value; }<br />
    <br />
    }<br />
}<br />

now set the values
as datacontainer.PersonId = TextBox1.Text;
and get by datacontainer.PersonId

Thanks and Regards
Sandeep

If you want something you never had,
do something you have never done!

siddisagar23-Apr-07 0:26

siddisagar

23-Apr-07 0:26

Can You Tell me how to do using HiddenFields.

Thanks for replying.

Sandeep Akhare23-Apr-07 0:41

Re: How to get value in next pages [modified]

23-Apr-07 0:41

Hi Sagar
How much data you want to store in hidden field ?
i have given the good solution in last post i think that is better option

Thanks and Regards
Sandeep

If you want something you never had,
do something you have never done!

siddisagar23-Apr-07 1:11

siddisagar

23-Apr-07 1:11

Just I need to send name of the user to next page .Here my requirement is use hiddenField.Pls tell me u r valuable solution .

Thanks.

-- modified at 7:52 Monday 23rd April, 2007

Sandeep Akhare23-Apr-07 1:51

23-Apr-07 1:51

Hi Sagar this is your solution
Add Hidden feild control to your aspx page
set the value of it in button click event
Now you can get in any page
set the value

<br />
<asp:HiddenField ID="PeronName" runat="server"  /><br />
in button click event <br />
PeronName.Value = TextBox1.Text;<br />

Now you can get this value ib your 2,3,4,5 pages just by
Request.Params["PeronName"]; returns your Paerson name

Now enjoy And please first try to search on Google if failed to get any solution then only post on forums Keep learnig my friend Google is your best friend not Forums

Thanks and Regards
Sandeep

If you want something you never had,
do something you have never done!

Urgent Javascript

jayarajmrj22-Apr-07 23:28

jayarajmrj

22-Apr-07 23:28

I have a form lot of server controls are there like textboxes , labels, dropdownlist etc., I want to clear all the textboxes in one javascript function,Instead of passing of all the textboxes id's.

_mubashir22-Apr-07 23:37

_mubashir

22-Apr-07 23:37

Your statement makes no sence to me infact you havnt asked for anything. The only answer i can give yout is to go ahead and do what you want. Try and be clear of what exactly you need.

Mubashir
Software Architect
Storan Technologies Inc, USA
Every job is a self portrait of the person who did it.

_AK_23-Apr-07 0:16

23-Apr-07 0:16

What you need to do is to loop through all the controls in the form and then if it is a textbox you clear it.
you can use document.Form1.elements.length to get the complete number of controls available and here Form1 is the form name.

Best Regards,
Apurva Kaushal

Datagrid question??

Nada Adel22-Apr-07 23:27

22-Apr-07 23:27

Hi,
I created a datagrid that is bound at runtime with a database. This datagrid also has a template column, but this template column is displayed at the beginning of the datagrid (at the far left), I want this template column to be on the far right...How can I do that? The problem is that the other columns in the datagrid are bound at runtime so at design time this template column is the first column to be displayed??..is there anyway to fix this??

thnx in advance

_AK_22-Apr-07 23:31

22-Apr-07 23:31

If you are creating all the columns of the datagrid at runtime then create the template column also at runtime.
Alternatively are you specifying the bound column at design time then put the template column part at the last(after the bound columns) and it will be displayed at the last only.

Best Regards,
Apurva Kaushal

Nada Adel23-Apr-07 0:04

23-Apr-07 0:04

thnx but how can I do that, I wrote something like that but I can't seem to link it with the datagrid.

TemplateColumn tc = new TemplateColumn();
tc.HeaderText = "Display on Map";
LinkButton LinkButton2 = new LinkButton();
LinkButton2.CommandName = "btnShow2";

I don't know the exact code for it, coz I've always use the wizard from the design.

_AK_23-Apr-07 0:23

23-Apr-07 0:23

First you need to create the template column and then in the itemdatabound event create the control which you want to be there in the template column. Also put templatecreation code after the bound column creation code.

Best Regards,
Apurva Kaushal

Nada Adel23-Apr-07 1:04

23-Apr-07 1:04

Do u have any Link for an example that I can use as a reference??

_AK_23-Apr-07 1:38

23-Apr-07 1:38

I don't know about the link but you can search through google.
BTW here is the code to create bound column and template column dynamically:

BoundColumn bCol = new BoundColumn();<br />
bCol.DataField = DC.ColumnName;<br />
bCol.HeaderText = DC.ColumnName;

here DC is the datacolumn.

TemplateColumn tColStatus = new TemplateColumn();
tColStatus.HeaderText = "Status";

only thing is after creating these columns you need to add them to the datagrid and once it is done in the itemdatabound event you can place the following code to add the control to the template column.

<br />
Label lblStatus = new Label();<br />
lblStatus.EnableViewState = true;<br />
lblStatus.ID = "lblStatus";<br />
lblStatus.Text = "Pending";<br />
e.Item.Cells[index of the template column].Controls.Add(lblStatus);

Best Regards,
Apurva Kaushal

Nada Adel23-Apr-07 3:15

23-Apr-07 3:15

thnx for the code, really helpful but there's still one problem, when I insert the linkButton using this code:

e.Item.Cells[1].Controls.Add(LinkButton2);

The header of the template column becomes the control itself, I mean the header becomes a LinkButton too, so why does that happen..and how can I resolve this issue??

thnx in advance for all ur help

_AK_23-Apr-07 5:10

23-Apr-07 5:10

That is OK what you need to do is to put the code of itemdatabound event inside this "if" loop:
if(e.Item.ItemType == ListItemType.Item || e.Item.ItemType == ListItemType.AlternatingItem)

Best Regards,
Apurva Kaushal

Nada Adel23-Apr-07 9:41