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For me the immediate work around is to replace the ( with something else and try to make a patter with that !!! And then use the Regex.Matches()!!!
Regards,
Jaiprakash M Bankolli
jaiprakash.bankolli@gmail.com
http://jaiprakash.blog.com/
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You need to use the escape character '\'. For example: "PaperIndex \(India\) Private".
"We make a living by what we get, we make a life by what we give." --Winston Churchill
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How to integrate digital cameras with .net?
The input from a camera should be sent to a .net application
Please specify the tool which does this.
Thanks.
din
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Typically it depends on the methods exposed by the camera software !! If there are methods exposed then you can very well use the drivers and access the images from camera if not then find out from provider itself
Regards,
Jaiprakash M Bankolli
jaiprakash.bankolli@gmail.com
http://jaiprakash.blog.com/
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would like to know any tool that supports integration of web applications with digitalcameras,webcam e.t.c
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My feeling is the provider needs to be asked, as it is some times proprietary information !!!
-- modified at 9:58 Saturday 14th April, 2007
Regards,
Jaiprakash M Bankolli
jaiprakash.bankolli@gmail.com
http://jaiprakash.blog.com/
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do a gogoogle search for Windows image Acquisition. There is a library by Microsoft that u can use to acquire images from Digital camera, scanner e.t.c
t.aransiola
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Hia to all,
Here i have a problem that,I am using 3 txtboxes and,in these 3, 1 textbox is readonly(getting value from ddlist),and 1 textbox is editable.And now my requirement is,
i have to get the values from txt1 and txt2 into txt3.That i have to get only on when txt3_gotfocus.Means when i click for editing in the txt3 ,it shd give the values of txt1 and tx2.(assume both numeric and charcters in txt1 and txt2.)
Can anyone give me some idea
I know javascript when both txt's are editable.but how to write one is editable and one is readonly.
Thanks in advance.
kissy
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Hi,
AFAIK, there is no OnFocus event in the ASP.NET textbox. If txt2 is the editable one, and you want to have txt3 updated when txt2 is changed, you could do:
Protected Sub txt2_TextChanged(ByVal sender As Object, ByVal e As System.EventArgs) Handles txt2.TextChanged
If Txt1 <> "" And Txt2 <> "" Then
Txt3.Text = txt1.Text & txt2.Text
Else
'Error handling code
End If
End Sub
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hai lucjon,
THanks for ur response.But it is giving any value in txt3.
if i try edit,it shd give the txt1 & txt2 values in txt3.
Give me some othet idea.
plz i have tried as u told,but not working.
kissy
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Hello,
I am developing Web Application in that I am storing HTTPPostedFile in Datatable.But after that I am not able to fetch that File in HTTPPostedFile object.
I had written code as,
HttpPostedFile obj_Posted;
sobj_Posted =((HttpPostedFile)dt.Rows[0]["HttpPostedFile"]).FileName;
But here error comes as invalid type cast
swapnil Bhavsar
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Hi,
What is the datatype of the column of the table into which you are storing the file?
Thanks and Regards,
Chetan Ranpariya
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Hi,
I have a web application(ASP.net, C#) in which the user is be able to download a .cab file to the PC by clicking on a button after making a file selection. I tried many methods for accomplishing the download task.
The code i tried is given below.
Response.ContentType = "APPLICATION/OCTET-STREAM";
System.String disHeader = "Download; Filename=\"" + myfilename+ "\"";
Response.AppendHeader("Content-Disposition", disHeader);
System.IO.FileInfo fileToDownload = new System.IO.FileInfo(myfilepath);
Response.Flush();
Response.WriteFile(fileToDownload.FullName);
or
FileStream MyFileStream = new FileStream(myfilepath, FileMode.Open);
long FileSize;
FileSize = MyFileStream.Length;
byte[] Buffer = new byte[(int)FileSize];
MyFileStream.Read(Buffer, 0, (int)MyFileStream.Length);
MyFileStream.Close();
Response.ContentType = "application/octet-stream";
Response.AddHeader("content-disposition", "attachment; filename=" + myfilename);
Response.BinaryWrite(Buffer);
When i tried these two methods, i could download the files to the PC. The user has to copy the cab file to the Pocket PC device for installing it. The file downloaded through the web application may have some problem so that it cannot be installed on the Pocket PC.
When i tried to install the original file from the repository, it worked fine. It means that there occurs some problem with the cab file while it is being downloaded.
The original file is having the size 420 KB. But the file downloaded is having size 432 KB.
Could anybody guide me to solve the problem?
Thanks in advance.
Nicejith
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hi lucjon,
i tried that code.
still i'm getting the same problem..
there occurs some size variation when i'm trying to download file using all these methods..
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Is ASP.NET Ajax v1.0 is free of cost for commercial use? Plz reply with proof that supports your answer. I need this urgent.......... plz help
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Hi, PC Plus Magazine (recent issue, Code it section) states that ASP.NET Ajax (Atlas) 1.0 uses the Microsoft Permissive license. I'm not very good at legal stuff, but from what I read here, I think it can be used commercially.
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I had a problem in sending email from asp.net 2.0.
The code which i have used for sending email follows..
First i have imported some namespaces
<br />
using System.Net;<br />
using System.Net.Mail;<br />
after, in a button click event i have written like this
<br />
string toaddr;<br />
toaddr = "stxvechoor@rediffmail.com";<br />
MailMessage message = new MailMessage();<br />
message.From = new MailAddress("sebastian@atenindia.com");<br />
message.To.Add(new MailAddress(toaddr));<br />
message.CC.Add(new MailAddress("stxvechoor@rediffmail.com"));<br />
message.Priority = MailPriority.High;<br />
message.Subject = "hai";<br />
message.Body = "Test Mail";<br />
SmtpClient client = new SmtpClient();<br />
client.Port = 2095;<br />
client.Host = "mail.ateninc.com";<br />
client.Send(message);<br />
But it showed some error..
Can anyone help me.....
I will be thankful to you...
Sebastian
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Hi,
Which error message you get?
Thanks and Regards,
Chetan Ranpariya
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First i got the error below
SMTP exception was unhandled by user code..
when i added try..catch... it showed some error like this..
mail sending failed
I couldn't understand these..
will you help me?
thanks
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Hi all,
how to insert one data grid into another datagrid.
ex: if i select one item in one column than it will display new datagrid that should shows the related item details.
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<br />
asp:datagrid id="dgAddresses" runat="server" CssClass="grid" AutoGenerateColumns="False" GridLines="None"<br />
Width="680"><br />
SelectedItemStyle Font-Bold="True" CssClass="grid_itemSelected"></SelectedItemStyle><br />
EditItemStyle CssClass="grid_itemEdit"></EditItemStyle><br />
AlternatingItemStyle CssClass="grid_itemAlternating"></AlternatingItemStyle><br />
ItemStyle CssClass="grid_item"></ItemStyle><br />
HeaderStyle Font-Bold="True" CssClass="grid_header"></HeaderStyle><br />
FooterStyle CssClass="grid_footer"></FooterStyle><br />
Columns><br />
asp:TemplateColumn ItemStyle-HorizontalAlign="Center" ItemStyle-VerticalAlign="Top"><br />
ItemTemplate><br />
asp:ImageButton ID="ibtnViewUsers" runat="server" CommandArgument='<%#DataBinder.Eval(Container.DataItem, "lngAddressID").ToString()%>' Visible='<%#DataBinder.Eval(Container.DataItem, "CountDP").ToString() == "0" && DataBinder.Eval(Container.DataItem, "CountUsers").ToString() != "0"%>' ImageUrl="../../../../../../images/bo_icons/arrow_yellow_right_12x12.gif" AlternateText="$Click_to_view_users_conected_to_this_address$"><br />
/asp:ImageButton> <br />
/ItemTemplate><br />
/asp:TemplateColumn><br />
<br />
asp:TemplateColumn HeaderText="$Addresses$" ItemStyle-VerticalAlign="Top"><br />
ItemTemplate><br />
asp:DataGrid id="dgUsersConections" runat="server" CssClass="grid" Visible="False" AutoGenerateColumns="False"<br />
GridLines="None"><br />
SelectedItemStyle Font-Bold="True" CssClass="grid_itemSelected"></SelectedItemStyle><br />
EditItemStyle CssClass="grid_itemEdit"></EditItemStyle><br />
AlternatingItemStyle CssClass="grid_itemAlternating"></AlternatingItemStyle><br />
ItemStyle CssClass="grid_item"></ItemStyle><br />
HeaderStyle Font-Bold="True" CssClass="grid_header"></HeaderStyle><br />
FooterStyle CssClass="grid_footer"></FooterStyle><br />
Columns><br />
asp:TemplateColumn HeaderText="$Users$"><br />
ItemTemplate><br />
asp:Label id="lblUsers" runat="server"><br />
<%#DataBinder.Eval(Container.DataItem, "strName").ToString()%><br />
/asp:Label><br><br />
/ItemTemplate><br />
/asp:TemplateColumn><br />
/Columns><br />
/asp:DataGrid><br />
/ItemTemplate><br />
/asp:TemplateColumn><br />
/Columns><br />
/asp:datagrid><br />
Then you have to add an ItemCreated on the outer datagrid (dgAddresses):
<br />
#region Web Form Designer generated code<br />
override protected void OnInit(EventArgs e)<br />
{<br />
InitializeComponent();<br />
base.OnInit(e);<br />
}<br />
<br />
private void InitializeComponent()<br />
{<br />
<br />
this.dgAddresses.ItemCreated += new System.Web.UI.WebControls.DataGridItemEventHandler(this.dgAddresses_ItemCreated);<br />
this.Load += new System.EventHandler(this.Page_Load);<br />
<br />
}<br />
<br />
#endregion
This method shoud look something like this:
private void dgAddresses_ItemCreated(object sender, System.Web.UI.WebControls.DataGridItemEventArgs e)<br />
{<br />
try <br />
{<br />
if (e.Item.ItemType == ListItemType.Item || e.Item.ItemType == ListItemType.AlternatingItem) <br />
{<br />
DataRowView drv = (DataRowView) e.Item.DataItem;<br />
<br />
System.Web.UI.WebControls.ImageButton ibtn = (System.Web.UI.WebControls.ImageButton)e.Item.Cells[0].Controls[1];<br />
ibtn.Click += new System.Web.UI.ImageClickEventHandler(this.ibtnViewConections_Click); <br />
} <br />
} <br />
catch (Exception err) <br />
{<br />
}<br />
}<br />
the ibtnViewConections_Click:
<br />
private void ibtnViewConections_Click(object sender, System.Web.UI.ImageClickEventArgs e)<br />
{<br />
System.Web.UI.WebControls.ImageButton ibtn = (System.Web.UI.WebControls.ImageButton)sender; <br />
DataGridItem dgiRow = (DataGridItem)ibtn.Parent.Parent;<br />
<br />
if(ibtn.CommandName == "")<br />
{<br />
ibtn.ImageUrl = "../../../../../../images/bo_icons/arrow_yellow_down_12x12.gif";<br />
if(dgiRow.ItemType == ListItemType.Item)<br />
{<br />
ibtn.CommandName = "grid_item";<br />
}<br />
else<br />
{<br />
ibtn.CommandName = "grid_itemAlternating";<br />
}<br />
createConnectionsView(ibtn); <br />
}<br />
else<br />
{<br />
dgiRow.CssClass = ibtn.CommandName;<br />
ibtn.ImageUrl = "../../../../../../images/bo_icons/arrow_yellow_right_12x12.gif";<br />
ibtn.CommandName = "";<br />
removeConnectionsView(ibtn); <br />
} <br />
}
The code that adds the inner datagrid:
<br />
private void createConnectionsView(System.Web.UI.WebControls.ImageButton ibtn)<br />
{<br />
DataGridItem dgiRow = (DataGridItem)ibtn.Parent.Parent;<br />
dgiRow.CssClass = "grid_itemSelected";<br />
int lngAddressID = int.Parse(ibtn.CommandArgument);<br />
<br />
My.BusinessLogicObjects.Address bloAddress = null;<br />
try <br />
{<br />
DataView dvUsersToAddress = null;<br />
bloAddress = new My.BusinessLogicObjects.Address();<br />
dvUsersToAddress = bloAddress.GetUsersToAddress(lngAddressID); <br />
<br />
if(dvUsersToAddress.Count != 0)<br />
{ <br />
DataGrid _dgUserConections = (DataGrid)dgiRow.FindControl("dgUsersConections");<br />
_dgUserConections.Width = System.Web.UI.WebControls.Unit.Percentage(100);<br />
_dgUserConections.DataSource = dvUsersToAddress;<br />
_dgUserConections.DataBind();<br />
_dgUserConections.Visible = true;<br />
} <br />
<br />
}<br />
catch (Exception err) <br />
{ <br />
throw new Exception(Error loading result$") + " " + err.Message, err);<br />
} <br />
finally <br />
{<br />
if (bloAddress != null) bloAddress.Dispose(); <br />
bloAddress = null; <br />
}<br />
}
Then to hide the inner datagrid:
private void removeConnectionsView(System.Web.UI.WebControls.ImageButton ibtn)<br />
{<br />
DataGridItem dgiRow = (DataGridItem)ibtn.Parent.Parent; <br />
<br />
DataGrid _dgUsersConections = (DataGrid)dgiRow.FindControl("dgUsersConections"); <br />
_dgUsersConections.Visible = false;<br />
<br />
}
Hope it helps
Thomas
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Hi to all,
I am using .NET2003, while run the Project it displaying this kind of Errors.
A project with an Output Type of Class Library cannot be started directily.
In order to debug this project, go to the Debugging tab under configuration Settings in Project Properties, and set the Start Action to start External Program or Start URL. Alternatively, You can add a non-library project to this solutions that uses a reference to this project and set it as the startup Project.
I tried with above Paragraph but I am getting same Problems.
Mohan Balal
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Hi, how are you..?
you are trying to run a class library project which has no forms, so you will not be able to run it and you will get this type of error.
you should create one simple form application and link your class library with it and then, try to run that form application ...you will be able to debug your class library project through this path....
Bye.
Chirag Patel
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