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The problem is that ms create all this table for you automaticly with lot of code and i want to use that code.If i change db after i must change code in all application and believe that is lot of work  i think something is not right with my db but what ?Even that thank you for your answare
when i want to read something good just seat and type it
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I need to find the HTML comment using regular expression. I tried this expression (? . but this is not suitable to find multiline comment (that is newline).
Please help anyone to find this HTML comment using regex.
Thanks in Advance.
Regards
R.Arockiapathinathan
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try this:
it will find all HTML comments within the source.
greetings
walter
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Fantastic and million thanks to you.
It works fine.
Regards
R.Arockiapathinathan
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Hi All,
Can anyone tell me how do I create tab control in ASP.NET 2.0.I cant see tab control directly in toolbox.I am using VB as code behind language.
Please help me at the earliest.
Thanks in advance...
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Thanks for the reply.
I got this link but I need the text instead of Image and also I cant see the tab control as show in that page.
Finally on click event the text fields changes to another field.I mean when I click any of the field name then it changes.
Please help me...
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I have a gridview in which in every row i have a button .When i click that
button i want to perform some task.This button is in third column the second column has the name of the file . i want that name of that file which is there in that row. Actually i want to know what is the event and how to capture it .
thanks
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U can capture Row Command event for the same.
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can you help me out with the code.
thanks 
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Tyr this:
Protected Sub grdCommunicationDetailsView_RowCommand(ByVal sender As Object, ByVal e As System.Web.UI.WebControls.GridViewCommandEventArgs) Handles grdCommunicationDetailsView.RowCommand
Try
gridROW = CType(CType(e.CommandSource, Control).NamingContainer, GridViewRow)
ml_lngCommunicationID = CInt(grdCommunicationDetailsView.DataKeys(gridROW.RowIndex).Value)
htxtCommunicationID.Value = ml_lngCommunicationID
Select Case e.CommandName
Case "DeleteTrans"
objTAXCommunicationDetails = New CTAXCommunicationDetails
With objTAXCommunicationDetails
.FormId = msForm_TYPE.msForm_TAXCOMMUNICATIONDETAILS
.CommunicationID = ml_lngCommunicationID
.UserId = Session("UserId")
.Delete()
End With
strMessage = "Record Deleted Successfully...!"
RefreshGridView()
End Select
Catch ex As Exception
End Try
End Sub
<asp:GridView>
<Columns>
<asp:TemplateField HeaderStyle-CssClass="heading" HeaderText="Delete">
<ItemStyle HorizontalAlign="Center" VerticalAlign="Top" />
<ItemTemplate>
<asp:ImageButton ID="Delete" runat="server" CommandName="DeleteTrans" ImageUrl="../Images/delete.gif" CssClass="cursor"
ToolTip="Delete" />
</ItemTemplate>
<HeaderStyle Width="60px" />
</asp:TemplateField>
</Columns>
</asp:GridView>
Any problem let me know.
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hi ritu
try this code:-
Set commandname and CommandArgument property of Button
<asp:Button ID="BT" runat="server" Text="Button" CommandName="Botton" CommandArgument='<%# Eval("fileid") %>'/>
protected void GV_items_RowCommand(object sender, GridViewCommandEventArgs e)
{
string fileid = Convert.ToString(e.CommandArgument);
//By this code u will get ur fileid
}
pathan
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we cannot take button in gridview in this way. IT gives error .
Error 1 System.Web.UI.WebControls.DataControlFieldCollection must have items of type 'System.Web.UI.WebControls.DataControlField'.'asp:Button' is of type 'System.Web.UI.WebControls.Button'.
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Try the code which I gave as I am doing this only and its working in my Project. The only difference is that I am using image button and u r using button.
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Hi ritu
u can take server bottun between <ItemTemplate> tag.
i give u whole code how to take a button
now try this code
<asp:GridView ID="GV_cart" runat="server" AutoGenerateColumns="False"
OnRowCommand="GV_cart_RowCommand" CellPadding="4" ForeColor="#333333">
<Columns>
<asp:BoundField DataField="fileid" HeaderText="File Id" />
<asp:BoundField DataField="Filename" HeaderText="File Name" />
<asp:TemplateField>
<HeaderTemplate>File id</HeaderTemplate>
<ItemTemplate>
<asp:Button ID="BT" runat="server" CommandName="button" CommandArgument='<%#Eval("fileid") %>' Text="Button" Width="75px" />
</ItemTemplate>
</asp:TemplateField>
</Columns>
</asp:GridView>
After this write code on Row_command event
if (e.CommandName == "button")
{
string fileid= e.CommandArgument.ToString();
}
if u use more than one button than this code may be useful for checking which button evet fires by commandname condition.
Pathan
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thanks . had worked .thanks to varsha mane too.
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How to call webservice without adding webreference in solution
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Web Method from Web Service can be invoked by using HTTP POST. so, you can submit the Form with POST to a particular web method..
The way we are using in our project. we generate a proxy class by using wsdl. and just add this proxy class to web project. then, we can invoke to the webmethod via this proxy class..
here is also another way to invoke a web service without web reference.
http://www.codeproject.com/cs/webservices/CallWebServicesDynamic.asp
Hope it would help.
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hi I am reading xls file in that there are 5 column of date in dd/mm/yyyy format but while i am reading from code few of date column format is change.
i.e mm/dd/yyyy how to fix this problem
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Dear All,
I have made web application using Asp.net C#(Visual Studio2005). And I used Publish Web site option. Now I want to make web setup. I select New -> project -> SetUp and Deployement ->
There I given name of the setup and location of project file.When I click Ok. File System Web setup open. Now when i goes for add project output from web application project. I do not get any option
I even tried location of project to published web site location but it did not work out
Please help..
thanks
regards
imran khan
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i am using xml to import data to my web page. Information is displaying but xsl style sheet is not applying please tell me, whats the problem .... Please my code is :
Dim xmlPath As String = Server.MapPath("XMLFile.xml")
Dim xslPath As String = Server.MapPath("XSLTFile.xsl")
Dim fs As FileStream = New FileStream(xmlPath, FileMode.Open,FileAccess.Read)
Dim reader As StreamReader = New StreamReader(fs, Encoding.UTF8)
Dim xmlReader As XmlTextReader = New XmlTextReader(reader)
'Instantiate the XPathDocument Class
Dim doc As XPathDocument = New XPathDocument(xmlReader)
'//Instantiate the XslTransform Class
Dim xslDoc As XslCompiledTransform = New XslCompiledTransform()
xslDoc.Load(xslPath)
Dim sw As StringWriter = New StringWriter()
xslDoc.Transform(doc, Nothing, sw)
' //Close Readers
reader.Close()
xmlReader.Close()
Response.Write(sw.ToString())
Please help me... 
Feroze
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Hi Feroze!
Why aren't you using the XML-Control (found in the Toolbox)?
With this you just need to apply the XML-Source and the transformation file.
e.g:
Dim xmlDoc As New XmlDocument()
xmlDoc.Load("your path to the xml-data goes here")
With yourXmlControl
.Document = xmlDoc
.TransformSource = "your path to the xsl-file goes here"
End with
This is all what needs to be done.
- walter
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