C / C++ / MFC

int total16 = (bit14 & 0xFFF) + ((bit4 & 0xF) << 12);

int value = 151; //in binary = 10010111
//the mask we will be using will be 0xaa (170 dec) wich is 10101010 in binary
int value2 = value & 0xAA;
// this will do the mask
// value    10010111
// 0xAA     10101010 
// =        10000010
// so your answer is 10000010 wich is 130 in dec.
// so value2 == 130

// the shift operator << and >> shifts bits in an direction
// we are now going to shift the value of value2 right with one bit
value2 = value2 >> 1;
//this will do the shift as following
// value2   10000010
// >>  1
// answer   01000001 (65 in dec)

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ShaluMalu wrote:

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...OnLButtonDown(...)
{
       .....
       if(m_rcArea2.PtInRect(&pt))
            OnArea2();
}