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The C# code is the eqivelant of using the Windows API CreateProcess() to launch Explorer.exe
and have it open with the specified file highlighted:
STARTUPINFO StartupInfo;
memset(&StartupInfo, 0, sizeof(STARTUPINFO));
StartupInfo.cb = sizeof(STARTUPINFO);
StartupInfo.dwX = 100;
StartupInfo.dwY = 100;
StartupInfo.dwXSize = 400;
StartupInfo.dwYSize = 400;
PROCESS_INFORMATION ProcessInfo;
TCHAR szCommandLine[260];
_tcscpy(szCommandLine, _T("explorer.exe /select,"));
_tcscat(szCommandLine, _T("C:\\AUTOEXEC.BAT"));
if (::CreateProcess(NULL,
szCommandLine,
NULL,
NULL,
FALSE,
NORMAL_PRIORITY_CLASS,
0,
NULL,
&StartupInfo,
&ProcessInfo))
{
::CloseHandle(ProcessInfo.hProcess);
::CloseHandle(ProcessInfo.hThread);
}
else
{
DWORD err = ::GetLastError();
}
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On an "Install program I want to give the User the choice of installing the 1) Data Folder on their computer (without installing a Desktop Icon(shortcut)), 2) Install all the Data Folders (with a Desktop Icon), 3) Install a Desktop Icon(shortcut) only for drive "d:\", or 4) view the files from Windows Exployer.
I must be able to have Windows Exployer begin running with the selected file being loaded up if the User selects the 4th option.
Will the code you sent do option 4 as is?
A C++ programming language novice, but striving to learn
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Larry Mills Sr wrote: Will the code you sent do option 4 as is?
This line needs to be changed
_tcscat(szCommandLine, _T("C:\\AUTOEXEC.BAT"));
I've hardwired it to highlight C:\AUTOEXEC.BAT since it was a file that probably exists on your
system so if you tried the code it would work.
You'll want to copy the actual pathname of the file/folder you wish to be highlighted when explorer
starts.
Mark
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Please remember my last email.
I will only use Exployer IF the User selects it. I wouldn't want Exployer to run at any other time.
How do I make sure this happens!
Please excuse my ignorance.
A C++ programming language novice, but striving to learn
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Let me make sure I've got this right - this is an install program you are writing with C/C++
correct?
The user will be presented with 4 options as outlined in the above post.
If option 4 is chosen then the user can choose a location to store the files?
Or is it the location for a folder?
What do you want explorer to default to? The files to install or where the files should go?
How you give the user the 4 choices will determine which processing gets done. You'd only
call/use the explorer code if the user chooses option 4, based on their selection.
Mark
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I'm using VC6 and have no idea what is causing this problem. Normally if you compile a blank windows app you get a lot of imports from kernel32. I believe that this is because the CRT uses them to initialize.
The problem is as soon as I use ANY api from kernel32 all these are lost and I end up with the 1 API I use. Causing the app to crash in the CRT (before WinMain)!
Has anyone seen this happen before, know a solution/workaround or have any idea what is causing it? If I don't use any imports form kernel32 the ones used by the CRT are there and the app runs. 
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In my program, I need a structure which looks like:
<br />
struct stru_A{<br />
char Name[MAX_LEN];<br />
float score;<br />
}<br />
Moreover, I declare a vector variable of type stru_A to hold Name_Score pairs. My problem arises with the member variable 'Name'.
<br />
vector 'struct stru_A' Name_Score_Collection;<br />
<br />
In the above declaration of stru_A, the size of Name, MAX_LEN, is predefined to be 30(#define MAX_LEN 30, to hold the longest name in my database). However, in the database many peoples' name are much less than 30 letters. Hence, much valuable memory space are wasted. I wonder what's the way to solve this problem.
I have tried with a string variable. It is true it can solve this problem. However, in the later part of my program I need to write each struture in vector Name_Score_Collection into a file on my hard disk. I used CFile::write() to accompolish this. CFile::write() worked fine with 'char Name[MAX_LEN]', but not with 'std::string Name'. I think this is because function write() need to know the exact size for each structure to be write out. The size of a string variable is not fixed.
-- modified at 9:29 Saturday 16th December, 2006
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Use a CString/std::string instead?
Or use a map of names/scores:
std::map<std::string, float> aMap
aMap["cy163"] = 100.00;
Or even a std::vector of std::pair:
std::vector<std::pair<std::string, float> > myVec;
myVec.push_back(std::make_pair("cy163", 100.00));
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Much better answer than mine. It's what I get for working in an MFC house.
Software Zen: delete this;
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I have tried with a string variable. It is true it can solve this problem. However, in the later part of my program I need to write each struture in vector Name_Score_Collection into a file on my hard disk. I used CFile::write() to accompolish this. CFile::write() worked fine with 'char Name[MAX_LEN]', but not with 'std::string Name'. I think this is because function write() need to know the exact size for each structure to be write out. The size of a string variable is not fixed. But, I am not sure about this.
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You will need to store the size of each string, the string data, and then the float. More complicated than simply writing an entire structure to disk but a worthwhile exercise nonetheless. 
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Not to steal your thunder Rob... The following works under VC6.0 also (and stays within the standard C++ library). See std::string widen() and std::wstring narrow()[^]
Jeff
std::string StringNarrow( const std::wstring& wide ) {
typedef std::ctype<wchar_t> CT;
std::string narrow;
narrow.resize( wide.length() );
CT const& ct = std::_USE(std::locale(), CT);
ct.narrow( &wide[0], &wide[0] + wide.length(), '_', &narrow[0] );
return narrow;
}
std::wstring StringWiden( const std::string& narrow ) {
typedef std::ctype<wchar_t> CT;
std::wstring wide;
wide.resize( narrow.length() );
CT const& ct = std::_USE(std::locale(), CT);
ct.widen(&narrow[0], &narrow[0] + narrow.length(), &wide[0]);
return wide;
}
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Very useful. All my string widening/narrowing is done using MS specifics likes WideCharToMultiByte.
Not sure how it helps the OP though! 
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Since you're already using the STL vector class, why not use it's string class?
Software Zen: delete this;
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I have tried with a string variable. It is true it can solve this problem. However, in the later part of my program I need to write each struture in vector Name_Score_Collection into a file on my hard disk. I used CFile::write() to accompolish this. CFile::write() worked fine with 'char Name[MAX_LEN]', but not with 'std::string Name'. I think this is because function write() need to know the exact size for each structure to be write out. The size of a string variable is not fixed.
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Maybe is worth that you give a look to Serialization Topics in MSDN.
If the Lord God Almighty had consulted me before embarking upon the Creation, I would have recommended something simpler.
-- Alfonso the Wise, 13th Century King of Castile.
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I dont think you will get a problem there. Because, when you are going to write a structure variable into a file, you will just be saying sizeof(stObj), so what's the problem in "not knowing" the the size of the string variable. Or if you want to trim something out within a limited lenght you can always check for stdMyString.size() and do it.
:Gong: 歡迎光臨 吐 西批 :Gong:
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Hi Cy163,
> char Name[MAX_LEN], but not with std::string Name...
How so?
std::string Name
Name.c_str();
...
or
std::wstring Name
Name.c_str();
...
The following works under VC6.0 also (and stays within the standard C++ library). See std::string widen() and std::wstring narrow()[^]
Jeff
std::string StringNarrow( const std::wstring& wide ) {
typedef std::ctype<wchar_t> CT;
std::string narrow;
narrow.resize( wide.length() );
CT const& ct = std::_USE(std::locale(), CT);
ct.narrow( &wide[0], &wide[0] + wide.length(), '_', &narrow[0] );
return narrow;
}
std::wstring StringWiden( const std::string& narrow ) {
typedef std::ctype<wchar_t> CT;
std::wstring wide;
wide.resize( narrow.length() );
CT const& ct = std::_USE(std::locale(), CT);
ct.widen(&narrow[0], &narrow[0] + narrow.length(), &wide[0]);
return wide;
}
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store only a pointer, inside the structure, such as
struct stru_B {
char * lpszName;
float score;
};
then, of course, you need to deal with memory allocation/deallocation.
Alternatively include STL string or MFC CString into the struct.
If the Lord God Almighty had consulted me before embarking upon the Creation, I would have recommended something simpler.
-- Alfonso the Wise, 13th Century King of Castile.
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this method is problematic with CFile.read(), since sizeof(struct_B) is not fixed.
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cy163@hotmail.com wrote: this method is problematic with CFile.read(), since sizeof(struct_B) is not fixed.
That's is inevitable because you want to save variable-lenght chunks of data. You have to store the true struct lenght too (and before storing actual struct). There are several ways to do that. Again, maybe better to give a look at Serialization of MSDN.
If the Lord God Almighty had consulted me before embarking upon the Creation, I would have recommended something simpler.
-- Alfonso the Wise, 13th Century King of Castile.
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Call string::size() to get the length of the string.
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I just have a simple function to get the bounding rectangle. green color is without using the pen, red is with the pen. Why is the red rectangle so much bigger? even the green is not exactly correct.
http://img246.imageshack.us/my.php?image=testqq1.jpg[^]
void Test::DrawPreview(HDC hdc)
{
Graphics graphics(hdc);
Pen blackPen(Color(255, 0, 0, 0), 1);
Pen yellowPen(Color(255, 255, 255, 0), 20);
Pen redPen(Color(255, 255, 0, 0), 1);
Pen greenPen(Color(255, 0, 255, 0), 1);
Point pts[] = {Point(120,120),
Point(200,130),
Point(150,200),
Point(130,180)};
// Create a path that has one curve and one ellipse.
GraphicsPath path;
path.AddClosedCurve(pts, 4);
path.AddEllipse(120, 220, 100, 40);
// Draw the path with a thick yellow pen and a thin black pen.
graphics.DrawPath(&yellowPen, &path);
graphics.DrawPath(&blackPen, &path);
// Get the path's bounding rectangle.
RectF rect;
RectF rect2;
path.GetBounds(&rect, NULL, &yellowPen);
path.GetBounds(&rect2);
graphics.DrawRectangle(&redPen, rect);
graphics.DrawRectangle(&greenPen, rect2);
}
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How much larger is the red rect?
I didn't test your code, but with the yellow pen's width at 20 the red rect should be a little
bigger.
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I tried your code. Looks like they allow PLENTY of room for the thicker pen!
*Edit* Looks like a bug to me
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