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ive done that thanks, but i still get error like
error C2143: syntax error : missing ';' before ','
error C2143: syntax error : missing ';' before '{'
ive set my array up as ---
char array[12][12]={
{'L','A','Y','Z','E','I','T','H','S','J','H','R'},
{'B','C','Q','Q','U','K','H','L','J','D','A','T'},
..
..
};
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Anonymous wrote:
ive set my array up as ---
char array[12][12]={
{'L','A','Y','Z','E','I','T','H','S','J','H','R'},
{'B','C','Q','Q','U','K','H','L','J','D','A','T'},
..
You've set it up wrong
e.g.
char array[3][3]=
{
{'A', 'B', 'C'},
{'a', 'b' , 'c'},
{'D', 'E' , 'F'}
}
shoudl work.
 (-_-)
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or like this if you want
char array[5][3] = {"brian","niamh","marky"};
(-_-)
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Psst! Hey, over here.
<stealthly>
did you mean?
char array[3][6] = {"brian","niamh","marky"};
</stealthly>
Jeremy L. Falcon
"Tickle me Elmo -- please!"
<nobr>
Homepage : Sonork = 100.16311
Maybe my mangling might misguide malicious miscreants momentarily?
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Hey
What you need to do is just define the inputs in one big list no need for {} after every 12 the compiler automatically assigns the first 12 to teh first array of 12 then the next 12 to the next and so on.
Peter
Do it like this char array[12][12]={'L','A','Y','Z','E','I','T','H','S','J','H','R','B','C','Q','Q','U','K','H','L','J','D','A','T'};
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Reveal thyself ye swine or thus not an answer from me you will receive!
Even the best of the best ask questions -- that's how they become the best.
Jeremy L. Falcon
"If you eat the cookie..."
<nobr>
Homepage : Sonork = 100.16311
I care to not care about the care of not caring for the caring of a caring one's country.
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its a miss-tari!!!
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char array[4][7] =
{
{"zero\0"}, {"one\0"}, {"two\0"}, {"three\0"}
};
puts(array[2]);
Jeremy L. Falcon
"Tickle me Elmo -- please!"
<nobr>
Homepage : Sonork = 100.16311
Maybe my mangling might misguide malicious miscreants momentarily?
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hi, sorry to bother you again, but it still comes up with the same errors 
damsel in distress
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It's giving you a syntax error? Could you post the code (if it's not millions of lines that is) so I could have a run-through?
Jeremy L. Falcon
"Tickle me Elmo -- please!"
<nobr>
Homepage : Sonork = 100.16311
Maybe my mangling might misguide malicious miscreants momentarily?
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Jeremy Falcon wrote:
Reveal thyself ye swine or thus not an answer from me you will receive!
Sounds as if a Shakespearian plea for the anonymous to become a user
Nick Parker
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Inside a DLL, Can I find which process is calling the dll ? Thanks
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How about a bit more info:
If you want the process name use GetModuleFileName()
If you want the PID use GetCurrentProcessId()
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GetModuleFileName() worked. Thank You!
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Can you use a string object.
Ex. CString str;
str.Format("%d", nNumbers);
str.GetLength();
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How about capture keystrokes ?
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or you can use this approach:
char buff[6];
int i = 2632;
int len;
sprintf(buff, "%i", i);
len = strlen(i);
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or you can use a simpler aproach:
int len
if (i < 10)
len = 1;
if (i < 100 and i > 9)
len = 2;
if (i < 1000 and i > 99)
len = 3;
if (i < 10000 and i > 999)
len = 4;
if (i < 100000 and i > 9999)
len = 5;
very simple, but since you can't use conversions, i'd use that one.
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Try this -
int get_NumDigits(int x)
{
return (int) (1+log10(abs(x)));
}
Vivek
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Thats a nice solution except of course what if x is 0?
Log10(0) = error!
if (x != 0)
return (int)(1 + log10(abs(x))) ;
else
return 1 ;
}
Roger Allen
Sonork 100.10016
If I had a quote, it would be a very good one.
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Yes,
thats a good safe check. the code wont crash but will report num digits in zero to be zero.
Roger Allen wrote:
return 1 ; // 0 is 1 digit wide
Maybe from a printing point of view, but I think from a math viewpoint, num digits in zero = zero. (if you define num digits of an integer to be the number of times you have to divide the integer by 10 to get a value to zero)
I better get back to work ..
Vivek
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