Re: Why doesen't my window show when using CreateDialog()? - C / C++ / MFC Discussion Boards

Re: Why doesen't my window show when using CreateDialog()?

30-Apr-02 8:51

Cool it works now. But i can't move the window now... any ideas?

Thanks

Re: Why doesen't my window show when using CreateDialog()?

Ravi Bhavnani30-Apr-02 9:02

Ravi Bhavnani

30-Apr-02 9:02

Ensure that the dialog has a caption bar and your dialog proc is handles standard messages by calling the default handler. Any reason why you're using the Win32 API instead of MFC?

/ravi

"There is always one more bug..."
http://www.ravib.com
ravib@ravib.com

Re: Why doesen't my window show when using CreateDialog()?

30-Apr-02 9:11

yes, this is the procedure, i've placed brakepoints in it to make sure it enters it and it does:

BOOL CALLBACK WndProc(HWND hWnd, UINT uMsg, WPARAM wParam, LPARAM lParam)
{
switch (uMsg)
{
case WM_COMMAND:
switch (wParam)
{
case ID_FILE_EXIT:
PostQuitMessage (0);
break;
}
break;
case WM_DESTROY:
PostQuitMessage (0);
break;
default:
return DefWindowProc (hWnd, uMsg, wParam, lParam);
}

return (0L);
}

and the reason why i use it is because i think i have more control over my program, i don't like those embedded things, hope you understand me Smile | :)

Re: Why doesen't my window show when using CreateDialog()?

Ravi Bhavnani30-Apr-02 9:22

Ravi Bhavnani

30-Apr-02 9:22

Anonymous wrote:
and the reason why i use it is because i think i have more control over my program,

Imho, it's much easier to build GUIs using MFC. You get a lot of support from the framework.

/ravi

"There is always one more bug..."
http://www.ravib.com
ravib@ravib.com

Re: Why doesen't my window show when using CreateDialog()?

30-Apr-02 9:34

I agree, but when you can use the Dialog designer with a non-MFC program i think it's better.

Re: Why doesen't my window show when using CreateDialog()?

C^hris L^osinger30-Apr-02 10:47

C^hris L^osinger

30-Apr-02 10:47

Anonymous wrote:
i think it's better

i've never heard someone using MFC ask why they can't move their dialog...

but, to each his own.

-c

<font size=-2>//The Mandelbrot set
o(int O){putchar(O);}main(){float l[8],O,I=.05;char _;for(l[6]=15;l[6]<':';o
(10),l[5]=-'$'*I+l[6]++*I)for(l[7]=-5;l[7]<'@';l[4]=-'('*I+l[7]++*I,o(_?'?':':'))for
(*l=O=0,_=1;++_&&((l[2]=*l**l)+(l[3]=O*O)<4);O=*l*O+l[5]+O**l,*l=l[2]-l[3]+l[4]);}</font>

Smaller Animals Software

Re: Why doesen't my window show when using CreateDialog()?

Philippe Mori30-Apr-02 12:51

Philippe Mori

30-Apr-02 12:51

My guess is that the move command does not reach the call to DefWindowProc.

If fact, if the command is not handled by your code (ID_FILE_EXIT in this case), then DefWindowProc should be called.

Thus you should add a default in the internal switch that will call DefWindowProc.

But according to MSDN, systems command like SC_MOVE are send as a WM_SYSCOMMAND message so it may be something else...

Philippe Mori

Re: Why doesen't my window show when using CreateDialog()?

1-May-02 2:20

I already have a default case in my switch statement...:

BOOL CALLBACK WndProc(HWND hWnd, UINT uMsg, WPARAM wParam, LPARAM lParam)
{
switch (uMsg)
{
case WM_COMMAND:
switch (wParam)
{
case IDC_OPENFILE:
OnOpenFile(hWnd);
break;

case ID_FILE_EXIT:
PostQuitMessage (0);
break;
}
break;

case WM_INITDIALOG:
OnInitApp(hWnd);
break;

case WM_DESTROY:
RegSave(hWnd);
PostQuitMessage (0);
break;
default:
return DefWindowProc (hWnd, uMsg, wParam, lParam);
}

return (0L);
}

i have also made breakpoints so see if the satement is executed, and it is..

Class Destruct

Peter Liddle30-Apr-02 8:18

Peter Liddle

30-Apr-02 8:18

Hey Guys

If i use an instance of a class in a funtion then deallocate it is it deallocated again when the function drops out. I only ask cos i keep getting a close handle again on my file access class at the end of my function even though i have already destructed the instance and haven't created another.

Peter

Re: Class Destruct

C^hris L^osinger30-Apr-02 8:28

C^hris L^osinger

30-Apr-02 8:28

if you "new" an object, then the destructor is only called when you "delete" it.

if you allocate the object on the stack, the destructor is called when the object goes out of scope.

one or the other (or you can explicitly call the destructor, but that's something you can't really do without knowing you're doing it)

-c

<font size=-2>//The Mandelbrot set
o(int O){putchar(O);}main(){float l[8],O,I=.05;char _;for(l[6]=15;l[6]<':';o
(10),l[5]=-'$'*I+l[6]++*I)for(l[7]=-5;l[7]<'@';l[4]=-'('*I+l[7]++*I,o(_?'?':':'))for
(*l=O=0,_=1;++_&&((l[2]=*l**l)+(l[3]=O*O)<4);O=*l*O+l[5]+O**l,*l=l[2]-l[3]+l[4]);}</font>

Smaller Animals Software

Re: Class Destruct

Ravi Bhavnani30-Apr-02 8:42

Ravi Bhavnani

30-Apr-02 8:42

If you store a pointer to class A as member variable in class B, and class B is designed to delete the A object in its own destructor, you should reset the pointer to NULL when you manually delete object A. This will make it clear:

B:: ~B()
{
  // Free A
  if (m_ptrA != NULL) {
     delete m_ptrA;
  }
}
 
B::someFunction()
{
  m_ptrA = new A();
  ...;
  delete m_ptrA;
  m_ptrA = NULL;      // <--- Reset pointer after deleting object
}

/ravi

"There is always one more bug..."
http://www.ravib.com
ravib@ravib.com

Re: Class Destruct

Mike Nordell1-May-02 8:44

Mike Nordell

1-May-02 8:44

No. But if you haven't created your own copy c'tor and assignment operator a HANDLE wrapper class might use the compiler generated versions and then two object might try to release the same resoucrce when they are destructed.

Refresh ListBox

Anton A. Loukine30-Apr-02 8:13

Anton A. Loukine

30-Apr-02 8:13

Hi:

This may be a stupid question.
In a dialog box, a certain function is called when I press 'Add' button. This function adds data to the listbox and then goes through the loop which takes about 15 seconds. The listbox doesn't get repainted until this long procedure is over (in fact, the control disappears from the screen at all during that time).

Is there a way to refresh/repaint the control BEFORE this lengthy loop is called?

Thanks

Re: Refresh ListBox

Tom Archer30-Apr-02 8:33

Tom Archer

30-Apr-02 8:33

UpdateWindow will update the contents. Also, another function for you to be aware of is SetRedraw which allows you to disable drawing for situations where you're doing a lot to the control and don't want the flicker - but instead want a complete redrawing of the control only when finished.

Cheers,
Tom Archer
Author, Inside C#

A total abstainer is one who abstains from everything but abstention, and especially from inactivity in the affairs of others.

Re: Refresh ListBox

Ravi Bhavnani30-Apr-02 9:03

Ravi Bhavnani

30-Apr-02 9:03

In addition to Tom's suggestions, you shouldn't be repopulating the entire list box when you add an item. This is a common GUI mistake. Instead, keep the listbox in synch with your data store by simply adding/inserting a single element. This will make your GUI respond faster and appear more professional.

If you must repopulate the list box, show a busy cursor. Use AfxGetApp()->DoWaitCursor() to do this.

/ravi

"There is always one more bug..."
http://www.ravib.com
ravib@ravib.com

Re: Refresh ListBox

30-Apr-02 9:52

Ravi!
You are really taking the things out of context and causing utter confusion to the people who are looking for 'good' suggestions. Please look at a question twice or thrice before posting your suggestion.
Thanks
Frown | :(

Re: Refresh ListBox

Ravi Bhavnani30-Apr-02 9:56

Ravi Bhavnani

30-Apr-02 9:56

Yes, I'm well aware of the original question. What about my suggestion did you find not good or misleading?

/ravi

"There is always one more bug..."
http://www.ravib.com
ravib@ravib.com

My mistake

Ravi Bhavnani30-Apr-02 9:57

Ravi Bhavnani

30-Apr-02 9:57

I should've read the question the 4th. time. Blush | :O

Thanks!

/ravi

"There is always one more bug..."
http://www.ravib.com
ravib@ravib.com

Re: My mistake

1-May-02 8:07

I don't think you will listen the 'real' music even at the n'th time;P

MDIFrame

act_x30-Apr-02 6:53

act_x

30-Apr-02 6:53

I have a menu item to exit the application(MDI).
the title on the menu Item is "Exit".
what is the best(safest) way to terminate the application ?
Cry | :((

Re: MDIFrame

30-Apr-02 7:14

I use DestroyWindow()

Re: MDIFrame

Tom Archer30-Apr-02 7:33

Tom Archer

30-Apr-02 7:33

Use the CWinApp::OnAppExit function if you want to mimic exactly how the MFC exits the app

By the way, the best way to figure things like this out is to look at the menu in your default MDI app. You'll see that the Exit menu item has an ID of ID_APP_EXIT.

Then, taking that if you search through the MFC source code (using Find in Files) you'll find the following message map for the CWinApp class.

BEGIN_MESSAGE_MAP(CWinApp, CCmdTarget)
//{{AFX_MSG_MAP(CWinApp)
// Global File commands
ON_COMMAND(ID_APP_EXIT, OnAppExit)
// MRU - most recently used file menu
ON_UPDATE_COMMAND_UI(ID_FILE_MRU_FILE1, OnUpdateRecentFileMenu)
ON_COMMAND_EX_RANGE(ID_FILE_MRU_FILE1, ID_FILE_MRU_FILE16, OnOpenRecentFile)
//}}AFX_MSG_MAP
END_MESSAGE_MAP()

This type of peeking into the MFC code is the best way to learn the "correct" way to program your apps.

Cheers,
Tom Archer
Author, Inside C#

A total abstainer is one who abstains from everything but abstention, and especially from inactivity in the affairs of others.

How do i use a Resource for my main window?

30-Apr-02 6:36

I have made a resource file which defines what controls etc. are on my form, but how do i use that Resource on my main window? I know how to use it when creating a new dialog but not with the main window. And, i don't want to use MFC Smile | :)

thanks

is this wright?

30-Apr-02 6:31

hi,
i keep getting an error saying ": error C2196: case value '1' already used".
is there another way of having an or function in the middle

switch (get_textletter)
{
case 'a' || 'A':
get_textletter=0;
break;

case 'b'|| 'B':
get_textletter=1;
break;

case 'c'|| 'C':
get_textletter=2;
break;

Re: is this wright?

Tim Smith30-Apr-02 6:37

Tim Smith

30-Apr-02 6:37

'a' || 'A' is a logical or operation. Thus, the result is either 0 or 1.

try:

case 'A':
case 'a':

etc...

Tim Smith

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