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N(1) = 2519
N(2) = 2519 + 2520 = 5039
N(3) = 2519 + 2520 + 2520 = 7559
N(4) = 2519 + 2520 + 2520 + 2520 = 10079
...
N(n) = 2519 + (n - 1)*(2520)
No idea what the heck it means, though. Care to enlighten us mathematically-challenged folks?
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Jon Sagara wrote: N(n) = 2519 + (n - 1)*(2520)
N(n) = (n * 2520) - 1
= 2520n - 1
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Some other interesting and useless observations:
1*2*3*4*5*6*7*8*9 is divisible by 2520 = 144
2520 is divisible by 2 * 3 * 5 * 7 = 12 (product of prime 1 - 9)
4 * 6 * 8 * 9 is divisible by 144 = 12 (product of 'non' prime 1 - 9) 
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its the LCM of all the numbers (2520) - 1
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10! - 1 = 3628799. Its 1 less than a multiple of 1, 2, 3 ... 10.
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((3628799 + 1) / 10) / (2 * 3 * 4 * 6) + (9 - 7 + 8 - 10) + 1 = 2519. 
------------------------------
PROST Roleplaying Game
War doesn't determine who's right. War determines who's left.
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x = (i - 1) (mod i), 2 ≤ i ≤ 10.
Thus, x = LCM(2, 3, 4, 5, 6, 7, 8, 9, 10) * k + LCM(2, 3, 4, 5, 6, 7, 8, 9, 10) - 1
LCM(2, 3, 4, 5, 6, 7, 8, 9, 10) = LCM(5, 7, 8, 9) = 23.32.5.7 = 2520.
Thus, x = 2520k + 2519. min(x) = 2519.
I had to redo it since I did it backwards.
"People who want to share their religious views with you almost never want you to share yours with them." - Anonymous
Web - Blog - RSS - Math - LinkedIn
Last modified: Thursday, July 27, 2006 12:08:26 PM --
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I know I'm a little late (and a valid solution has already been given), but no real explanation has been made. You first need to find a number that is a multiple of all these multiples (10 * 9, 9 * 8, etc), then one less than that will give the proper remainders. So, to find the least common multiple, first break these into primes:
10 * 9 = 2 * 3 * 3 * 5, 9 * 8 = 2 * 2 * 2 * 3 * 3, 8 * 7 = 2 * 2 * 2 * 7, etc.
Take out what is unique for each to get 2 * 2 * 2 * 3 * 3 * 5 * 7 = 2520. So, one answer (though you already know) to the original problem is 2519.
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How many Americans does it take to change a lightbulb ?
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0
these kinds of work are normally handled by mexicans non - americans in america
-- modified at 19:18 Wednesday 26th July, 2006
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Quartz... wrote: these kinds of work are normally handled by mexicans in america
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sorry that was a joke on lazy americans like us
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change it? it was perfect when we invented it!
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Yes[^], but then they "tweaked" it.
"I know which side I want to win regardless of how many wrongs they have to commit to achieve it." - Stan Shannon
Web - Blog - RSS - Math - LinkedIn
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10...
one to handle the bulb, the 9 others to turn the house...;P
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 I figured the first post here should be made by a math major. 
225 years ago, we set an example for the rest of the world by creating a country where everyone could vote...
Well, except for women and black people, but we fixed that!
-Adam Duritz, of Counting Crows
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I was going to make a lame first post but I figured someone else deserved the honor :p
CS is like a math major; only harder. Plus we don't get the girl.
A man said to the universe:
"Sir I exist!"
"However," replied the Universe, "The fact has not created in me A sense of obligation."
-- Stephen Crane
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Ennis Ray Lynch, Jr. wrote: CS is like a math major; only harder. Plus we don't get the girl.
Heh. I'm actually an Applied Math/Computer Science major...so I'm screwed in both respects. 
225 years ago, we set an example for the rest of the world by creating a country where everyone could vote...
Well, except for women and black people, but we fixed that!
-Adam Duritz, of Counting Crows
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You Java:Swing both ways?
"I know which side I want to win regardless of how many wrongs they have to commit to achieve it." - Stan Shannon
Web - Blog - RSS - Math - LinkedIn
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Or not screwed as the case may be
A man said to the universe:
"Sir I exist!"
"However," replied the Universe, "The fact has not created in me A sense of obligation."
-- Stephen Crane
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Sweeeeeet, a math forum
I'd like to help but I am too lazy to Google it for you.
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No idea why anyone voted you a 1, maybe they don't like humour, anways to add to the list of pointless posts I'll inform you that I corrected that humourless "mistake".
As of how to accomplish this I wouldn't have a clue at the moment and I'm too lazy to google it
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Ed.Poore wrote: I corrected that humourless "mistake".
Same here
I'd like to help but I am too lazy to Google it for you.
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Yes, but I only just heard about it.
"I know which side I want to win regardless of how many wrongs they have to commit to achieve it." - Stan Shannon
Web - Blog - RSS - Math - LinkedIn
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