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I have two bitmaps (loaded from resources).
I want to combine thse two bitmaps side-by-side into a 3rd bitmap.
I want to put the 3rd (combined) bitmap into an image list.
I tried using the BitmapDC class from the GDI articles section, but I'm missing something (obviously, otherwise I wouldn't be here).
Here's the code I'm using now:
CBitmap bmp1;
CBitmap bmp2;
bmp1.LoadBitmap(nImgConsult);
bmp2.LoadBitmap(nImgLabs);
CBitmapDC bmpDC(34, 21, GetDC(), RGB(255,255,255));
DrawBitmap(&bmp1, &bmpDC, CPoint(0, 0));
DrawBitmap(&bmp2, &bmpDC, CPoint(17, 0));
CBitmap* pBMP = bmpDC.Close();
if (!m_ResultsImages.Replace(0, pBMP, NULL))
{
TRACE("ImageList.Replace failed\n");
}
delete pBMP;
Any hints, clues, or alternative code?
-- modified at 11:36 Wednesday 26th July, 2006
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Why not just use the GetBitmapBits/SetBitmapBits (and CGdiObject::GetObject) to get the bits from images 1 and 2, create a byte array that is the size of the sum of both those arrays (which should be double the size of either one if the bitmaps are the same size), copy the bytes from image 1 to the first part of the new array, and image 2 to the last part of the new array and then use SetBitmapBits on a newly created CBitmap object?
If you decide to become a software engineer, you are signing up to have a 1/2" piece of silicon tell you exactly how stupid you really are for 8 hours a day, 5 days a week
Zac
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another approach is create a bitmap sized to fit both source bitmaps. arrange the bitmaps via bitblt()
Kuphryn
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Hi
Can we have two CDocument derived classes in an MDI application??
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Thus the name MDI = Multiple Document
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hey can anyone help me sort this? the weird thing is my program ran at first but now if i try and run i get this debug error!
*********************************************************************************************
*": warning C4267: 'argument' : conversion from 'size_t' to 'DWORD', possible loss of data"
*********************************************************************************************
If i'm not dead enough for life, am i alive enough for death?
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Smells like an stl issue.
You will get this type of message if you do something like this:
<br />
std::vector<long> vecLong;<br />
int n = vecLong.size();<br />
A lot of the stl classes returns a size_t numeric data type (instead of say, int, long etc).
Its not an error, but you should be aware of any overflow issues. If you are sure that your DWORD variable has enough range to accomodate the stl's size_t number, then just do a simple type cast.
<br />
std::vector<long> vecLong;<br />
int n = static_cast<int>(vecLong.size());<br />
I Dream of Absolute Zero
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The compiler is telling you exactly what is wrong. Show the line of code in question.
"Money talks. When my money starts to talk, I get a bill to shut it up." - Frank
"Judge not by the eye but by the heart." - Native American Proverb
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this is not an error. it is just a warning.
the compiler warns you about the fact that you copy some value of a particuliar type into a smaller type, hence the "possible loss of data".
what you can do to avoid this is :
- make the two types identical
- explicitely cast while assigning the value
- disable temporarily/totally the warning using the #pragma warning(disable:4267) statment...
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toxcct wrote: - disable temporarily/totally the warning using the #pragma comment(disable:4267) statment...
I believe you meant #pragma warning(disable:4267).
If you decide to become a software engineer, you are signing up to have a 1/2" piece of silicon tell you exactly how stupid you really are for 8 hours a day, 5 days a week
Zac
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Zac Howland wrote: believe you meant #pragma warning(disable:4267).
yup, typo 
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Are you compiling as 64-bit by chance? I believe size_t is a 64-bit integer on 64-bit platforms whereas DWORD (which is just an unsigned long) is always 32-bits. Thus, if you try to implicitly cast a size_t to a DWORD, it will give you that warning. To get around it, either ignore it, use bitshift operations to get the lower 32-bits, or use static_cast to explicitly cast it to a DWORD.
If you decide to become a software engineer, you are signing up to have a 1/2" piece of silicon tell you exactly how stupid you really are for 8 hours a day, 5 days a week
Zac
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hi
i have funtion named change(long lngNo,unsigned char* pData);
where some times i send intger data,float data ,BOOL data as second parameter.How do i convert integer ,float ,BOOL to unsigned char*.
thanks in before
james
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RockyJames wrote: How do i convert integer ,float ,BOOL to unsigned char*.
Use the address-of operator (&). For example:
int x;
change(5L, &x);
"Money talks. When my money starts to talk, I get a bill to shut it up." - Frank
"Judge not by the eye but by the heart." - Native American Proverb
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error C2664: : cannot convert parameter 2 from 'int *__w64 ' to 'unsigned char *'
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You'll need to cast it, since change() is expecting an unsigned char *.
Why are you trying to make a one-size-fits-all function?
"Money talks. When my money starts to talk, I get a bill to shut it up." - Frank
"Judge not by the eye but by the heart." - Native American Proverb
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can't you write several overloads of the function, which every func receive the right type ?
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RockyJames wrote: i have funtion named change(long lngNo,unsigned char* pData);
where some times i send intger data,float data ,BOOL data as second parameter.How do i convert integer ,float ,BOOL to unsigned char*.
It is very bad practice to write a one-size-fits-all function. If you are trying to do something with the bytes (i.e. send them across a network using sockets), that is one thing, but if you are trying to decrease the number of methods you need to write for a given operation that doesn't involve direct byte transmissions, then this is the wrong approach.
A cleaner way of doing it would be to:
typedef unsigned long ulong;
typedef unsigned char byte;
void change(ulong size, byte* data)
{
}
template<class T> void change(const T& data)
{
change(sizeof(T), (byte*)&data);
}
If you decide to become a software engineer, you are signing up to have a 1/2" piece of silicon tell you exactly how stupid you really are for 8 hours a day, 5 days a week
Zac
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The function is not written by me,it is one of the function in control.that`s the problem..so how can i send integer ,float ,BOOL in BYTE or unsinged char format.....?
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If you have the ability to refactor the function, you should.
That said, if you are just looking to get something working with it, you can cast anything in memory to a char* (or anything else for that matter) by taking the address of it (note that it is not necessarily safe to do, but is possible):
struct MyStruct
{
};
MyStruct data;
change((char*)&data, sizeof(MyStruct));
If you decide to become a software engineer, you are signing up to have a 1/2" piece of silicon tell you exactly how stupid you really are for 8 hours a day, 5 days a week
Zac
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In C++, how get the value and key in the IDictionary
Thanks.
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Are you referring to the Keys and Values properties?
"Money talks. When my money starts to talk, I get a bill to shut it up." - Frank
"Judge not by the eye but by the heart." - Native American Proverb
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Hi I would like to start a powerpoint slideshow from C++ the way it is done by the shell. I think this is possible by using OLE automation but I could not find a good example to help me on the way. I prefere to use slideshow viewer only if this is possible. (don't use powerpoint) I am not using MFC.
Thanks: cool:
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Remco Hoogenboezem wrote: Hi I would like to start a powerpoint slideshow from C++ the way it is done by the shell.
Then use ShellExecute().
"Money talks. When my money starts to talk, I get a bill to shut it up." - Frank
"Judge not by the eye but by the heart." - Native American Proverb
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