|
I have been trying to access frames with webBrowser document.
I always get the system telling me I don't have access. I read up on the net and it is a known issue due to security.
Has anyone ever achieved this?
HTMLDocument doc = (HTMLDocument) i_webBrowser.Document;
object aRef = frameNumber;
object anObj = doc.frames.item(ref aRef);
HTMLWindow2 aWindow = (HTMLWindow2) anObj;
HTMLDocument aDoc;
// the line below will cause the security exception
aDoc = (HTMLDocument) aWindow.document;
test
|
|
|
|
|
Hi All!
i am trying to use the ContextMenu control, and i do know how handle a click on it, i mean if you go the Form you can only handle popup event.
i tried to add to one menu item a click hasndler but it does not go in to the function that i created, can some one tell me how can i tell if the MenuItem in the ContextMenu was clicked and how can i handle it.
Thanks 
|
|
|
|
|
ytubis wrote: i tried to add to one menu item a click hasndler but it does not go in to the function that i created,
Proper steps are:
1) Click on one menu item
2) Go to the event tab on the property panel
3) Double click on the click event; an event and handler shall be added
4) Find the handler function and fill in the function body with your logic
Best,
Jun
|
|
|
|
|
That is exectlly the problem, i see there only the popup event and not click event or select event and i do not know why??????
|
|
|
|
|
That sounds weired. I use Linux stations at work and only can check it out for you tonight. Hopefully you've found the answer by then.
Best,
Jun
|
|
|
|
|
In VS2003, when you select a menu item and click on the event tab, you should see the following events:
Click
DrawItem
MeasureItem
Popup
Select
Best,
Jun
|
|
|
|
|
Pls can any help me figure out if there is any error in this web sevcice client. I have included Username and Password for testing. When
http://dedicated134.eapps.com/pencomweb2/PENCOM_WebService.asmx is registered
classes exposed are:
PencomServer2.PENCOM_WebService c1 = new PencomServer2.PENCOM_WebService();
PencomServer2.RSANO_Response c2 = new PencomServer2.RSANO_Response();
PencomServer2.EmployeeRecord[] record=new PencomServer2.EmployeeRecord[2];
but of tesing purposes
(string r = c1.TestPenComService();)
can be used.
Sample code is:
required namespace are:
using Microsoft.Web.Services3;
using Microsoft.Web.Services3.Design;// formerly Microsoft.Web.Services3.Policy
using System.Security.Permissions;
using Microsoft.Web.Services3.Security;
using Microsoft.Web.Services3.Security.Tokens;
public void ReadData()
{
//Secure Service
//http://dedicated134.eapps.com/pencomweb2/PENCOM_WebService.asmx
// Create an instance of the Web service proxy
PencomServer2.PENCOM_WebService c1 = new PencomServer2.PENCOM_WebService();
PencomServer2.RSANO_Response c2 = new PencomServer2.RSANO_Response();
PencomServer2.EmployeeRecord[] record=new PencomServer2.EmployeeRecord[2];
// This is the username security token which is used by the service proxy
UsernameToken token = null;
Username = "PENSUREPFA";
Password = "NS946343PE";
byte[] passwordBytes = System.Text.Encoding.UTF8.GetBytes(Password);
string passwordEquivalent = Convert.ToBase64String(passwordBytes);
token = new UsernameToken(Username, passwordEquivalent, PasswordOption.SendHashed);
//PolicyEnforcementSecurityTokenCache.GlobalCache.Add(token); //wse3.0
//Get the SoapContext for the SOAP request that is being made to the Web service.
Microsoft.Web.Services3.SoapContext requestContext = c1.RequestSoapContext;
//Add the UsernameToken to the WS-Security SOAP header.
requestContext.Security.Tokens.Add(token);
//Encrypt the UsernameToken in the WS-Security SOAP header.
//X509SecurityToken serverToken = GetSecurityToken();
//requestContext.Security.Elements.Add(new EncryptedData(serverToken, "#" + token.Id));
//Create a new instance of the MessageSignature class by using
//the UsernameToken just added to the WS-Security SOAP header.
MessageSignature sig = new MessageSignature(token);
//Add the digital signature to the WS-Security SOAP header.
requestContext.Security.Elements.Add(sig);
//Specify the time-to-live (TTL) for the
//SOAP message to diminish the chance of someone
//intercepting the message and replaying it.
requestContext.Security.Timestamp.TtlInSeconds = 120;
//Call the Web service.
//c1.UploadEmployeesRecordToGetRSANos(record, 0023);
try
{
string r = c1.TestPenComService(); //test version
}
catch (Exception g)
{
MessageBox.Show(g.Message);
}
}
On trying to connect to a test method, the respose I get back is:
Microsoft.Web.Services2.Security.SecurityFault: The security token could not be authenticated or authorized ---> System.Exception: WSE563:
The computed password digest doesn't match that of the incoming username token.
at Microsoft.Web.Services2.Security.Tokens.UsernameTokenManager.VerifyHashedPassword(UsernameToken token, String authenticatedPassword)
at Microsoft.Web.Services2.Security.Tokens.UsernameTokenManager.VerifyPassword(UsernameToken token, String authenticatedPassword)
at Microsoft.Web.Services2.Security.Tokens.UsernameTokenManager.VerifyToken(SecurityToken securityToken)
at Microsoft.Web.Services2.Security.Tokens.SecurityTokenManager.LoadXmlSecurityToken(XmlElement element)
--- End of inner exception stack trace ---
at Microsoft.Web.Services2.Security.Tokens.SecurityTokenManager.LoadXmlSecurityToken(XmlElement element)
at Microsoft.Web.Services2.Security.Tokens.SecurityTokenManager.GetTokenFromXml(XmlElement element)
at Microsoft.Web.Services2.Security.Security.LoadToken(XmlElement element, SecurityConfiguration configuration, Int32& tokenCount)
at Microsoft.Web.Services2.Security.Security.LoadXml(XmlElement element)
at Microsoft.Web.Services2.Security.SecurityInputFilter.ProcessMessage(SoapEnvelope envelope)
at Microsoft.Web.Services2.Pipeline.ProcessInputMessage(SoapEnvelope envelope)
at Microsoft.Web.Services2.WebServicesExtension.BeforeDeserializeServer(SoapServerMessage message)
Magic has often been thought of us the art of making dreams come true; the art of realizing visions. Yet before we can bring birth to the vision we have to see it.
|
|
|
|
|
I have two DataGridViews side by side with the same number of rows and columns. They connect to untyped DataSets. When I select a specific sell in the left DataGridView, I want the same cell to be selected in the right DataGridView. How do I go about doing that?
Thanks!
|
|
|
|
|
Hi,
I have doubt by using Shadowcopying. Please anyone give samples and explanation how shadow copy is working in .net windows forms using c#.
Thanks,
kokila.
|
|
|
|
|
|
Hi i was just wondoring if anyone knows how to create a trafic program with the 3 lights and cars going from left to right, right to left, up down and down up in c#
i did it in java it is easy but how can we do it in c#
thx
/\|-||\/|/\|)
|
|
|
|
|
It also the same. You can take your java source code and a little bit changes then you can compile it using C#. The language is almost the same.
|
|
|
|
|
stancrm wrote: It also the same
I know it is very similar but the thing is there are functions in java that i used that are not present in c# also i am not an expert in c# so for example i don't know how to represent the car as a moving object on the screen...
thx
/\|-||\/|/\|)
|
|
|
|
|
Halawlaws wrote: for example i don't know how to represent the car as a moving object on the screen...
How did you represent a moving car on the screen in Java?
Best,
Jun
|
|
|
|
|
Jun Du wrote: How did you represent a moving car on the screen in Java?
With frames do i have frames in c#?
thx
/\|-||\/|/\|)
|
|
|
|
|
Windows Form in C# appears to be equivalent to Frame in Java.
Best,
Jun
|
|
|
|
|
If you create a new Windows Form, then use the event Paint.
private void Form1_Paint(object sender, PaintEventArgs e)
{
...
}
Then write your code in this method. For example :
private void Form1_Paint(object sender, PaintEventArgs e)
{
e.Graphics.DrawLine(new Pen(Brushes.Black, 1), 0, 0, 50, 50);
}
That code will draw a black line with width = 1, from (0,0) to (50,50)
|
|
|
|
|
I am working on a project
i have created 3 tiers:
presentation layer
datalinklayer
business logiclayer
i have a dropdownlist named Category_List resides in my login screen.I want to dynamically add the items to it .so i created a table called type which has a single field called Category.
now i want to bind my backend sql server with my application.
i am able to do it staight away in my asp.net application but what i want is that the connection string should be in a class file ,while the page loads the method that contains the connection string should be called and the items must get filled in my Dropdownlist.
iam unable to do it inthe class file,pl help me in doing so with helpof an example.
thank u
arun
|
|
|
|
|
What problem do you have in writing a class file? Would you please elaborate this?
Just add one class file in your web application, and define all data access functions in it.
Also you can define a function in the class that will dynamically fill the dropdown list by passing it as a parameter by reference.
Regards,
Ketan
|
|
|
|
|
[edit]I'm using .NET 1.1[/edit]
I have a date in the form of a string, in the American format, MM/DD/YYYY. How can I create a DateTime object from this string, irrespective of the current culture?
In other words, even if the current culture is French, the incoming string 11/03/2005 should be interpreted as Nov 03, 2005. I want to do this without changing the current culture.
I tried doing
DateTime suspDt = Convert.ToDateTime(strDate, new CultureInfo("en-US")); but that didn't work. 
Thanks in advance! 
Cheers,
Vikram.
"I am not Jesus and will never be. The fact is I was a piece of cr*p till I found Him." - Paul Selormey.
-- modified at 9:09 Tuesday 4th July, 2006
|
|
|
|
|
DateTime mydatetime = DateTime.Parse("11/03/2005");
|
|
|
|
|
Hi,
Try something like:
DateTime myDateTime = new DateTime(year,month,day);
The year,month and day can be substracted from the string if you know their exact position, using Substring and IndexOf. It helped me a lot sometimes. Hope it helps you. 
Do your best to be the best
|
|
|
|
|
I was hoping there's a cleaner solution, but hey, your suggestion works.
Thanks a ton!
š
Cheers,
Vikram.
"I am not Jesus and will never be. The fact is I was a piece of cr*p till I found Him." - Paul Selormey.
|
|
|
|
|
Using .NET 1.1 and the following code:
string theDate = "11/03/2005";<br />
DateTime dt = Convert.ToDateTime(theDate, new System.Globalization.CultureInfo("en-US"));<br />
MessageBox.Show(dt.ToLongDateString());
Shows Nov 3 2005.
If I remove the culture info, and allow my local machine (UK) to decide, it gives March 11th. So basically that is exactly the desired behaviour!
What did you mean by:
Vikram A Punathambekar wrote: but that didn't work
It appears to work perfectly!
Current blacklist
svmilky - Extremely rude | FeRtoll - Rude personal emails | ironstrike1 - Rude & Obnoxious behaviour
|
|
|
|
|
J4amieC wrote: It appears to work perfectly!
I use the European format on my machine too, but it didn't work. 
However, since then, I replaced the code with the DateTime(year, month, date) suggestion above and it works perfectly.
Thanks anyway! 
š
Cheers,
Vikram.
"I am not Jesus and will never be. The fact is I was a piece of cr*p till I found Him." - Paul Selormey.
|
|
|
|
General 
News 
Suggestion 
Question 
Bug 
Answer 
Joke 
Praise 
Rant 
Admin 
Submit an article or tip
