How to block the View Source - ASP.NET Discussion Boards

how to open a modal dialog from clicking on a datagrid linkButton item

JuJAngel4-Jul-06 4:47

4-Jul-06 4:47

I have a datagrid with a link button column.
By clicking on this link button, i want a modal dialog to be opened
hoooowwwww? Sniff | :^)

Re: how to open a modal dialog from clicking on a datagrid linkButton item

minhpc_bk4-Jul-06 15:47

minhpc_bk

4-Jul-06 15:47

You may need to do the following steps:
+ Create an event handler for the ItemDataBound event of the datagrid control.
+ Get reference to the link button.
+ Add the handler for the client event onclick of the linkbutton using the Attributes collection with the Add method, in the handler you'd call to show up the modal dialog box.

You can find the sample code from the site datagridgirl[^].

Need Help : insert Row into ...

elpens4-Jul-06 4:43

elpens

4-Jul-06 4:43

Hi all,

I'm currently trying to add (with a button) rows into tables (html table, asp table or gridView) .

I've tried : (asp:Table)

Private Sub AddRow()
Dim count As Integer = procTable.Rows.Count //never increment !!!
Dim myRow As New TableRow
Dim myCell As New TableCell
myCell.Text = "myCell"
myRow.Cells.Add(myCell)

'this is the asp:Table
procTable.Rows.AddAt(count, myRow)
End Sub

Had anyone an idea???

Thanks a lot

ElpenS

-- modified at 10:26 Tuesday 4th July, 2006

ElpenS

Re: Need Help : insert Row into ...

Sushant Duggal4-Jul-06 18:48

Sushant Duggal

4-Jul-06 18:48

Hi ElpenS,

I work in C#, so i can give u an idea , what i think about the problem.
In C# when we create a new row , we create a new row for the table.
i.e.

TableRow tr = procTable.newRow();

And then at last we add the row to the table.

procTable.Rows.Add(tr);

I hope it works,
Thanks

Sushant Duggal.

Re: Need Help : insert Row into ...

elpens4-Jul-06 20:01

elpens

4-Jul-06 20:01

Thanks to you for your reply,

Unfortunatly, it doesn't works in VB.net.

procTable.newRow is not defined.

Will wait on further messages... D'Oh! | :doh:

Have a nice day

ElpenS

Dynamic control issue driving me nuts

andyk19674-Jul-06 4:21

andyk1967

4-Jul-06 4:21

I can't take it any longer... Can someone pleaseeeee help me. I have included my code below. I have searched everything and read many articles but I still don't get it. So please no reaction in the sense; you must create your controls in page_load, you must recreate your controls in the onpageinit, preserve viewstate, etc. because I have seen all those matters, many many times. My guess is that I just miss a tiny bit...

On a webform I have a placeholder and in codebehind this placeholder is filled with 2 dropdownlists and two buttons. The two lists are filled with data from a dbase. When a user clicks one button an item is transfered from one list to the other, vice versa. What happens in code below is that I have to click a button twice to have an item move. Actually the first time when I click the button the item is transfered but the list wont refresh, while I regenerate the listboxes in my on page init (i tried the on postback as well). When I do a response.redirect to the same page it works fine but that shouldn't be the way to go.

Imports System.Data.SqlClient
Imports System.Data
Partial Class Beheer_viewstate
Inherits System.Web.UI.Page
Dim bID As Integer
Sub Page_Init(ByVal s As Object, ByVal e As EventArgs) Handles MyBase.Init
Session("boekingID") = 105
bID = 105
dynamiccontent()
End Sub
Sub dynamiccontent()
Dim conn As New SqlConnection(System.Configuration.ConfigurationManager.AppSettings("MyProvider"))
conn.Open()
'ongeboekte extras per reiziger
Dim get_boeker_ongeboekte_extras As New SqlCommand("get_boeker_ongeboekte_extras", conn)
get_boeker_ongeboekte_extras.CommandType = CommandType.StoredProcedure
get_boeker_ongeboekte_extras.Parameters.AddWithValue("@boekerID", bID)
get_boeker_ongeboekte_extras.Parameters.AddWithValue("@boekingID", Session("boekingID"))
Dim rdr_get_boeker_ongeboekte_extras As SqlDataReader = get_boeker_ongeboekte_extras.ExecuteReader()

Dim extras As New ListBox
extras.ID = "lbx_extras" & bID
extras.DataSource = rdr_get_boeker_ongeboekte_extras
extras.DataValueField = "extraID"
extras.DataTextField = "naam"
extras.EnableViewState = "true"
extras.DataBind()
rdr_get_boeker_ongeboekte_extras.Close()

'geboekte extras
Dim get_boeker_geboekte_extras As New SqlCommand("get_boeker_geboekte_extras", conn)
get_boeker_geboekte_extras.CommandType = CommandType.StoredProcedure
get_boeker_geboekte_extras.Parameters.AddWithValue("@boekingID", Session("boekingID"))
get_boeker_geboekte_extras.Parameters.AddWithValue("@boekerID", bID)
Dim rdr_get_boeker_geboekte_extras As SqlDataReader = get_boeker_geboekte_extras.ExecuteReader()

Dim gekozenextras As New ListBox
gekozenextras.ID = "lbx_gekozenextras" & bID
gekozenextras.DataSource = rdr_get_boeker_geboekte_extras
gekozenextras.DataValueField = "extraID"
gekozenextras.DataTextField = "naam"
gekozenextras.EnableViewState = "true"
gekozenextras.DataBind()
rdr_get_boeker_geboekte_extras.Close()

'knopje voor toevoegen
Dim extrastoevoegen As New Button
extrastoevoegen.CssClass = "btn"
extrastoevoegen.Text = "-->"
extrastoevoegen.EnableViewState = "true"
extrastoevoegen.CommandName = "myId"
extrastoevoegen.CommandArgument = bID
AddHandler extrastoevoegen.Command, AddressOf extrastoevoegen_Click

'knopje voor verwijderen
Dim extrasverwijderen As New Button
extrasverwijderen.CssClass = "btn"
extrasverwijderen.Text = "<--"
extrasverwijderen.EnableViewState = "true"
extrasverwijderen.CommandName = "myId"
extrasverwijderen.CommandArgument = bID
AddHandler extrasverwijderen.Command, AddressOf extrasverwijderen_Click

plh_reizigers.Controls.Add(extras)
plh_reizigers.Controls.Add(extrastoevoegen)
plh_reizigers.Controls.Add(extrasverwijderen)
plh_reizigers.Controls.Add(gekozenextras)

End Sub
Sub extrastoevoegen_Click(ByVal Sender As Object, ByVal e As CommandEventArgs)
Dim extrastoevoegen As Button = CType(Sender, Button)
Dim myId As String = extrastoevoegen.CommandArgument
Dim lbx As ListBox = FindControl("lbx_extras" & myId)
Dim conn As New SqlConnection(System.Configuration.ConfigurationManager.AppSettings("MyProvider"))
conn.Open()
Dim set_boeker_extra As New SqlCommand("set_boeker_extra", conn)
set_boeker_extra.CommandType = CommandType.StoredProcedure
set_boeker_extra.Parameters.AddWithValue("@boekingID", Session("boekingID"))
set_boeker_extra.Parameters.AddWithValue("@extraID", lbx.SelectedValue)
set_boeker_extra.Parameters.AddWithValue("@boekerID", myId)
set_boeker_extra.ExecuteNonQuery()
conn.Close()
lbx.SelectedIndex = -1
End Sub
Sub extrasverwijderen_Click(ByVal Sender As Object, ByVal e As CommandEventArgs)
Dim extrasverwijderen As Button = CType(Sender, Button)
Dim myId As String = extrasverwijderen.CommandArgument
Dim lbx As ListBox = FindControl("lbx_gekozenextras" & myId)
Dim conn As New SqlConnection(System.Configuration.ConfigurationManager.AppSettings("MyProvider"))
conn.Open()
Dim del_boeker_extra As New SqlCommand("del_boeker_extra", conn)
del_boeker_extra.CommandType = CommandType.StoredProcedure
del_boeker_extra.Parameters.AddWithValue("@boekingID", Session("boekingID"))
del_boeker_extra.Parameters.AddWithValue("@extraID", lbx.SelectedValue)
del_boeker_extra.Parameters.AddWithValue("@boekerID", myId)
del_boeker_extra.ExecuteNonQuery()
conn.Close()
lbx.SelectedIndex = -1
End Sub
End Class

Re: Dynamic control issue driving me nuts

minhpc_bk4-Jul-06 5:11

minhpc_bk

4-Jul-06 5:11

andyk1967 wrote:
My guess is that I just miss a tiny bit...

What you miss is the control life cycle, or more exactly the order of the events. You bind the datasource to the ListBox in the Page_Load event, and update the data base in the button Click event, and basically the Page_Load happens before the postback event such as the button's Click event. So the list does not reflect the updated data until you click the button again or call redirect in order for the data binding code to re-run. Here, in the buton click event handler, after you update database you simply run the code to bind the datasource to the LixtBox again to refresh the control.

How to block the View Source

venkatasivaramaprasad4-Jul-06 3:06

venkatasivaramaprasad

4-Jul-06 3:06

Hi all,

Can any body tell me how to restrict the user without seeing source code of the page by right clicking the mouse on the page and select view source or from view menu of the menu bar. Thanks in advance.

Thanks and Regards

Venkat

Re: How to block the View Source [modified]

RichardGrimmer4-Jul-06 3:14

RichardGrimmer

4-Jul-06 3:14

add some javascript:

<br />
page.onmenu = "javascript: return false;"<br />

(BTW - removed in the above replaced "onmenu" that I typed)

should prevent the cm functioning at all. As for disabling particular items, doubt it's possible - Guffa? Ista? Anyone hehe?

"Now I guess I'll sit back and watch people misinterpret what I just said......"
Christian Graus At The Soapbox

-- modified at 9:15 Tuesday 4th July, 2006

Re: How to block the View Source

venkatasivaramaprasad4-Jul-06 3:41

venkatasivaramaprasad

4-Jul-06 3:41

Thanks man. But can you explain me where i should this code Thanks in advance.

Thanks and Regards

Venkat

Re: How to block the View Source

Jesse Squire4-Jul-06 4:35

Jesse Squire

4-Jul-06 4:35

The short answer is: you can't.

Richard's trick is a good one, and will overwrite the default context menu that appears from a right-click on the page. However, the browser is considered to be owned exclusively by the user, not the page. As a result, no code on a page can interfere with the core functions of the browser. The "View-->Source" option of the browser's main menu bar will always be present. Also, a user can simply disable javascript (or use an add-on) to use the default context menu despite any scripting that you do to hide it.

At the end of the day, anything that you render to the browser can be viewed as source and there is nothing that you can do to prevent it. As a rule of thumb, I'd strongly recommend that you render nothing to the browser that you do not wish the general public to see.

--Jesse

"start the web server before proceding"

ravikiranreddydharmannagari4-Jul-06 2:17

ravikiranreddydharmannagari

4-Jul-06 2:17

"web server on this computer is not running"
iam getting error message while opening an webapp
plz let me know
plz let me know asap

with regards
d.ravi kiran reddy

Re: "start the web server before proceding"

Paddy Boyd4-Jul-06 2:18

Paddy Boyd

4-Jul-06 2:18

Have you tried starting the web server?

Smile | :)

Re: "start the web server before proceding"

Paddy Boyd4-Jul-06 2:19

Paddy Boyd

4-Jul-06 2:19

But seriously. Is there a web server installed on your machine?

To check if IIS is there, click start > run > type inetmgr and hit enter. This should open up IIS admin page if it exists.

Re: "start the web server before proceding"

ravikiranreddydharmannagari4-Jul-06 2:34

ravikiranreddydharmannagari

4-Jul-06 2:34

iam able to see the adminpage but iam not able to find the files which have been prevly there

with regards
d.ravi kiran reddy

Re: "start the web server before proceding"

ravikiranreddydharmannagari4-Jul-06 2:42

ravikiranreddydharmannagari

4-Jul-06 2:42

hai,

still iam getting the same error message

plz let me know asap

Re: "start the web server before proceding"

Paddy Boyd4-Jul-06 5:34

Paddy Boyd

4-Jul-06 5:34

Man, try adding a new virtual directory within IIS and pointing it at your website files, or possibly re-installing the app if you're still getting issues.

Message Box using Java Script

psmukil4-Jul-06 1:00

psmukil

4-Jul-06 1:00

Hi all,

Im using C# as my code behind, im having a code in the button click event where im checking whether a file is exists, if it exists then it show the confirmation message box like "file found, want to continue", but its happening if we register the script in the page load and its not checking the condition. By clciking the button itself its showing the message box.

i need that script should get pop up only after the condition get satisfied. Is it possible? Please help me out to solve this problem. Thanks a lot in advance.

The code is given below

private void Page_Load(object sender, System.EventArgs e)

{

i = "file Exists";

StringBuilder str = new StringBuilder();

str.Append("");

str.Append("function PopWindow()");

str.Append("{");

str.Append("alert('hello world')");

str.Append("}");

str.Append("");

if(!Page.IsClientScriptBlockRegistered("clientscript"))

{

Page.RegisterStartupScript("clientscript",str.ToString());

}

Button1.Attributes.Add("onclick","PopWindow();");

}

private void Button1_Click(object sender, System.EventArgs e)

{

if (i=="file Exists")

{

int x= 0;

int y =0;

x = x+ y;

Button1.Attributes.Add("onclick","PopWindow();");

int a = 2;

int z = 2;

z = z+ a;

Response.Write(z.ToString());

}

}

Regards

Mukilan.

REgards
Mukilan

Re: Message Box using Java Script

Mircea Grelus4-Jul-06 1:30

Mircea Grelus

4-Jul-06 1:30

Well the problem is that client side code always get executed before the page is sent to the server.
So if your button has a server-side event and also a client side one (Button1.Attributes.Add("onclick","PopWindow();"); ) the PopWindow() will get called when you press the button and after that the page will be send to the server.

What you need to do is register the client script to be shown after the page has been submitted. So do not add an onclick attribute to the button, but in the Button1_Click(object sender, System.EventArgs e) method after validating if you need to show a popup just use Page.RegisterClientScriptBlock("msg","PopWindow(););. This will cause the PopWindow javascript method to be called after the page loads on the clients side.

regards,
Mircea
Many people spend their life going to sleep when they’re not sleepy and waking up while they still are.

Re: Message Box using Java Script

psmukil4-Jul-06 2:07

psmukil

4-Jul-06 2:07

thank u very much for your suggestion

but if i register code after checking the condition, that message box is not getting pop upped, in the browser if we click button, the "popwindow()" string is getting displayed

Code is given below,

private void Button1_Click(object sender, System.EventArgs e)
{
if (i=="file Exists")
{
int x= 0;
int y =0;
x = x+ y;
StringBuilder str = new StringBuilder();
str.Append("");
str.Append("function PopWindow()");
str.Append("{");
str.Append("alert('hello world')");
str.Append("}");
str.Append(""); Page.RegisterClientScriptBlock("clientscript","PopWindow();");// Here is the problem

Another Way

Page.RegisterClientScriptBlock("clientscript",PopWindow()); // its giving build error as follows(without specified in the quotes)

c:\inetpub\wwwroot\WebApplication1\WebForm1.aspx.cs(79): The name 'PopWindow' does not exist in the class or namespace 'WebApplication1.WebForm1'

int a = 2;
int z = 2;
z = z+ a;
}
}

Mukil

Re: Message Box using Java Script

Paddy Boyd4-Jul-06 2:22

Paddy Boyd

4-Jul-06 2:22

Why are you dynamically creating the PopWindow function. Surely if it's static you can just include it in the head of the page?

Re: Message Box using Java Script [modified]

Guffa4-Jul-06 2:27

Guffa

4-Jul-06 2:27

psmukil wrote:
StringBuilder str = new StringBuilder();
str.Append("");
str.Append("function PopWindow()");
str.Append("{");
str.Append("alert('hello world')");
str.Append("}");
str.Append(""); Page.RegisterClientScriptBlock("clientscript","PopWindow();");// Here is the problem

You are only putting the code for the function in the StringBuilder, you don't use it for anything.

The StringBuilder doesn't automatically recognise that you have created a script, and that there is a web page where the script could go. Neither does the RegisterClientScriptBlock automatically recognise that you happen to have a StringBuilder that contains a script with a function that corresponds with the function call in the code that you do add to the page.

---
b { font-weight: normal; }

-- modified at 8:28 Tuesday 4th July, 2006

Re: Message Box using Java Script

Mircea Grelus4-Jul-06 2:34

Mircea Grelus

4-Jul-06 2:34

The problem is that you don't have any function called PopWindow() in your rendered page. Why? Because you didn't place it there. You have just defined the StringBuilder in you method, but didn't send it to the page.

1. Put the Javascript in a .js file and inlcude a link to it from HTML
or
2. Register the javascript in the page on page_load just as you do the function call.

regards,
Mircea
Many people spend their life going to sleep when they’re not sleepy and waking up while they still are.

GOOGLE

MHASSANF4-Jul-06 0:59

MHASSANF

4-Jul-06 0:59

google can't search my image in my web site
how can i solve it ?

With Thanks

MHF

Backcolor for separate rows DataRow in Datatable in C#

michaeil4-Jul-06 0:29

michaeil

4-Jul-06 0:29

I create DataTable in code C# as Add-method of DataRow. Then I do DataGrid.DataSource = DataTable and DataGrid.DataBind.
Can I set BackColor for DataRow at moment of work Add-method? It is impossible to set BackColor for object DataGridItem in DataGrid in my situation.

michailk2001

Use Ctrl+Left/Right to switch messages, Ctrl+Up/Down to switch threads, Ctrl+Shift+Left/Right to switch pages.