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QuestionArrays in Hashtables Pin
Mazze.ger1-Jul-06 23:17
Mazze.ger1-Jul-06 23:17 
Hi guys!

A quick question from a c# newbie. Please take a look at the following two examples:

EXAMPLE 1:
using System;
using System.Collections;

class Tester
{
public static void Main()
{
Hashtable x = new Hashtable();
int[] y = { 1, 2, 3 };
x["1"] = y;
int[] z = { 4, 5, 6 };
x["2"] = z;
Console.WriteLine(((int[])x["1"])[1]);
Console.WriteLine(((int[])x["2"])[1]);
System.Threading.Thread.Sleep(25000);
}
}


EXAMPLE 2:
using System;
using System.Collections;

class Tester
{
public static void Main()
{
Hashtable x = new Hashtable();
int[] y = { 1, 2, 3 };
x["1"] = y;
y[0] = 4; y[1] = 5; y[2] = 6;
x["2"] = y;
Console.WriteLine(((int[])x["1"])[1]);
Console.WriteLine(((int[])x["2"])[1]);
System.Threading.Thread.Sleep(25000);
}
}

Example 1 produces the desired output 2 and 5 whereas Example 2 returns 5 and 5.
The only difference being that in Example 1 two variables were used (y and z) to write data to the hashtable whereas Example 2 uses only one variable (y). IMO both cases should produce the very same output, but they obviously don't. Could anyone explain to me why not? I don't understand the logic behind this. Do I always have to use different variables when writing to a hashtable? That would be very inconvinient, especially if the table were to consist of hundreds or even thousands of items!

Any help is greatly appreciated!
Thans for your efforts!!!
Mazze

AnswerRe: Arrays in Hashtables Pin
Guffa1-Jul-06 23:51
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Mazze.ger2-Jul-06 1:34
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