C / C++ / MFC

CPP911 wrote:

Another question, the posting says BYTE b=50; but if we have a stream of binary digits in a file, is there an easy command to input every 32 (or k bits in general) into a variable for further processing or will i have to use a pointer and keep track of the number of bits already inputed and convert it step by step to a decimal integer (by adding 2^m each time...)?

CPP911 wrote:

I found in some postings the data types "BYTE" and "DWORD". Can someone tell me in what library they can be found if any?

"Let us be thankful for the fools. But for them the rest of us could not succeed." - Mark Twain

"There is no death, only a change of worlds." - Native American Proverb

int i=3;
double d=(double)i;

An RK value is an encoded integer or floating-point value. 
RK values have a size of 4 bytes and are used to decrease file size for floating-point values. 
If bit 1 is cleared, the encoded value represents the 30 most significant bits of an IEEE 754 
floating-pointvalue (64-bit double precision). The 34 least significant bits must be set 
to zero. If bit 1 is set, the encoded valuerepresents a signed 30-bit integervalue. To get 
the correct integer,the encoded value has to beshifted right arithmeticaly by 2 bits. If bit0 
is set, the decoded value(both integer and floating-point)must be divided by 100 to get thefinal 
result.

int code; //Set this to your 32 bit code
__int64 temp=(code & 0xFFFFFFFD); //Mask the lowest two bits of the code
temp << 32; // Shift the code 32 bits to the left
double* pFloat = (double *)temp; 
double ans = *pFloat;
if (code & 1) ans /= 100.0;

rk <<= 2;
__int64 *buf = new __int64;
*buf = rk;
*buf <<= 32;
double* dub = (double *)buf;
val = *dub;

int i=3;
double d = i;

Michael Dunn wrote:

FYI this belongs in the C# forum[^]