Re: Application.Exit() - How do I return an exit code. - C# Discussion Boards

Ed.Poore3-Apr-06 7:47

3-Apr-06 7:47

1) Is this the correct forum, is it a C# program?
2) Has your disk been defragged recently?
3) Do you have lots of services / background apps running?

Ed

Re: why is the program running so slow

Agyeman3-Apr-06 8:15

Agyeman

3-Apr-06 8:15

It is a C# project i am working. I do not have lots of back apps running. This is because I am running below the physical memory. Yes it has been fragmented . Thank you.

Nana

Re: why is the program running so slow

Guffa3-Apr-06 7:55

Guffa

3-Apr-06 7:55

Well, there could be thousands of reasons...

What kind of program is it? What does it do? Who made it? How slow is "really slow" really?

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b { font-weight: normal; }

Application.Exit() - How do I return an exit code.

Mark42623-Apr-06 6:36

Mark4262

3-Apr-06 6:36

I am new to C#, and I have compiled a simple exe (a WindowsFormsApp, not a console app) to perform an operation, and want to notify the calling application when it has completed and return a status code.

ApplicationExit();

Just seems to exit, and even if I try to set a return code with:

System.Environment.ExitCode = #;

I don't seem to get anything either.

Can anyone help??

Thanks,
Mark

Re: Application.Exit() - How do I return an exit code.

Braulio Dez3-Apr-06 6:58

Braulio Dez

3-Apr-06 6:58

Hello,

Try the following

[STAThread]
static void Main()
{
Application.Run(new Login());
return 999;
}

In the retun, you get the exit code

/// -----------------------
Braulio Díez

http://www.bdiez.com
/// -----------------------

Re: Application.Exit() - How do I return an exit code.

Ravi Bhavnani3-Apr-06 7:08

Ravi Bhavnani

3-Apr-06 7:08

Isn't Main() a void method?

/ravi

My new year's resolution: 2048 x 1536
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Re: Application.Exit() - How do I return an exit code.

Ed.Poore3-Apr-06 7:49

Ed.Poore

3-Apr-06 7:49

Doesn't have to be, valid types are void and int according to the C# spec I seem to remember, same as in ANSI C

Ed

Re: Application.Exit() - How do I return an exit code.

Ravi Bhavnani3-Apr-06 9:01

Ravi Bhavnani

3-Apr-06 9:01

Ah.

/ravi

My new year's resolution: 2048 x 1536
Home | Music | Articles | Freeware | Trips
ravib(at)ravib(dot)com

Re: Application.Exit() - How do I return an exit code.

vineas3-Apr-06 7:53

vineas

3-Apr-06 7:53

Ravi Bhavnani wrote:
Isn't Main() a void method?

Main() can be either void or int:

[STAThread]
static int Main(string[] args)
{
  // do stuff
  if (error)
    return 1;
  else
    return 0;
}

-----
In the land of the blind, the one eyed man is king.

Re: Application.Exit() - How do I return an exit code.

Mark42623-Apr-06 8:24

Mark4262

3-Apr-06 8:24

Ravi,

Yes, your code works perfectly. Thanks!

This code works also:

Application.Exit();
Environment.Exit(2445);

Thanks,
Mark

Re: Application.Exit() - How do I return an exit code.

Ravi Bhavnani3-Apr-06 9:01

Ravi Bhavnani

3-Apr-06 9:01

Thanks, but I think you meant to thank Braulio. Smile | :)

/ravi

My new year's resolution: 2048 x 1536
Home | Music | Articles | Freeware | Trips
ravib(at)ravib(dot)com

Re: Application.Exit() - How do I return an exit code.

Ravi Bhavnani3-Apr-06 9:02

Ravi Bhavnani

3-Apr-06 9:02

Ah.

/ravi

My new year's resolution: 2048 x 1536
Home | Music | Articles | Freeware | Trips
ravib(at)ravib(dot)com

Detecting an already running application

royk1233-Apr-06 5:44

royk123

3-Apr-06 5:44

Hi,

When loading a program how do i check if an instance of the same program is already runing, and if so maximizing it from the system tray instead of opening a new instance?

tnx

Roy

Re: Detecting an already running application

Stefan Troschuetz3-Apr-06 5:56

Stefan Troschuetz

3-Apr-06 5:56

Search the articles here on Code Project. There are many that cover this topic.

www.troschuetz.de

crash on Win32 call

sreejnarayan3-Apr-06 5:04

sreejnarayan

3-Apr-06 5:04

Hi, I get a window crash on executing the following code. Problem tracked on sending the message RB_SIZETORECT. Please let me know if there is any solution for this and anybody faced same problem. Thanks ..

Win32Wrapper.RECT rbWindowRect = new Win32Wrapper.RECT();

Win32Wrapper.GetWindowRect(m_ReBarWindowHandle, out rbWindowRect);

int height = Win32Wrapper.SendMessage(
m_ReBarWindowHandle, Win32Wrapper.RB_GETROWHEIGHT, 0, 0);

Win32Wrapper.RECT insetRect = new Win32Wrapper.RECT();

insetRect.Left = rbWindowRect.Left;
insetRect.Top = rbWindowRect.Top;
insetRect.Right = rbWindowRect.Right;
insetRect.Bottom = (rbWindowRect.Top + height);

Win32Wrapper.SendMessage(
m_ReBarWindowHandle,
Win32Wrapper.RB_SIZETORECT,
0,
ref insetRect);

test test

Dynamically displaying class properties

IAmChris3-Apr-06 4:54

IAmChris

3-Apr-06 4:54

Hello,

When you build a custom control and place it on the toolbar in the VS IDE, then add it to a form, the public properties are dynamically loaded for that control/class in the properties window, right? I want to replicate that functionality in a test application.

Basically I'm building a class library that serializes/deserializes classes into/from XML documents on a network stream (through a socket.) As the serialized objects come down the wire and are deserialized into objects, they are sent to the (Windows) UI through events. I want to store them into something like a ListView (using a derived class from ListViewItem that holds a reference to the object) then when I click on an item in the ListView, a properties window is displayed showing all the public properties of that object along with the values. Then I can make sure that the objects are being serialized/deserialized correctly.

Any ideas how would I do this?

Thanks

Re: Dynamically displaying class properties

Stefan Troschuetz3-Apr-06 5:09

Stefan Troschuetz

3-Apr-06 5:09

You can achieve this by using reflection. The following lines of code should point you in the right direction.

PropertyInfo[] propertyInfos = obj.GetType().GetProperties();
for (int index = 0; index < propertyInfos.Length; index++)
{
  propertyInfos[index].Name; // Gives the name
  propertyInfos[index].GetValue(obj); // Gives the value
}

www.troschuetz.de

Re: Dynamically displaying class properties

IAmChris3-Apr-06 5:40

IAmChris

3-Apr-06 5:40

That't great! Thank you very much

Re: Dynamically displaying class properties

darkelv4-Apr-06 2:33

darkelv

4-Apr-06 2:33

You can use a propertygrid to display the properties of the class.

You can make changes to the object through the propertygrid though.

help on Smart device Application

DotNet novice3-Apr-06 4:53

DotNet novice

3-Apr-06 4:53

I have an alarm application for a Pocket PC (DELL Axim x51). When the alarm ring I play a beep sound using soundplayer class's PlayLooping method. But the sound stops on touch of any part of screen. I should play the sound until the user hits the STOP/SNOOZE menu buttons(which I have in my application). I display a messagebox when it starts playing. please suggest me how to keep the sound playing until the user hits my menu buttons. I do stop it in menu's event handler but before that when the user clicks on the screen it stops. I need to prevent this from happening and should make the sound stop only on click of my menu items.

--Shobha

-- modified at 10:56 Monday 3rd April, 2006
I have forgot to mention that I'm using OPENNETCF's Soundplayer class and my project is on Visual Studio.NET 2003.

Convert .png to .gif

realmontanakid3-Apr-06 4:18

realmontanakid

3-Apr-06 4:18

Hi

I got an .png Image and want to convert it in an .gif file. When i try to show the .png file in an img tag the backround color of the image is grey. I heard Inetrnet Explorer can't show transparent .png files.

So i want to convert it in an .gif file. But after that the background of my .gif file is black..

<br />
String gifFilePath2 = System.IO.Path.Combine(path, fileName + "_scaled.png");<br />
String gifFilePath3 = System.IO.Path.Combine(path, fileName + "_scaled.gif");<br />
<br />
System.Drawing.Image imgGIF = System.Drawing.Image.FromFile(gifFilePath2);<br />
            Bitmap bmpGIF = new Bitmap(imgGIF, size);<br />
            bmpGIF.Save(gifFilePath3, System.Drawing.Imaging.ImageFormat.Gif);<br />

How to get: selected or not selected?

Dima Filipiuk3-Apr-06 3:54

Dima Filipiuk

3-Apr-06 3:54

How to get: selected or not selected some text or images on page of axWebBrowser? It is for work with clipboard.

Re: How to get: selected or not selected?

albCode3-Apr-06 4:28

albCode

3-Apr-06 4:28

Can you make your question more structured please....

_____________________

Proud to be Albanian
_____________________

Re: How to get: selected or not selected?

Dima Filipiuk3-Apr-06 9:28

Dima Filipiuk

3-Apr-06 9:28

It is for different popup menu. If text selected i show popup_memu_1. If text not selected i show popup_menu_2.

-- modified at 15:29 Monday 3rd April, 2006

CheckBox.Enabled = False without grey?

livez3-Apr-06 3:19

livez

3-Apr-06 3:19

Hello

I have a checkbox I set to Enabled =False from time to time. However, I don't appreciate the grey tone both text and box gets when this is done. Is there some way to work around this? So far I've done an inherited checkbox control which actually consists of two, one of which is always disabled. I move this to front when control.Enabled = false. This doesnt solve the problem with the actual box being grey'ed down as well. How should I go about doing this?

/regards

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