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How i can get position of mouse when hold tap and the contextmenu show? Thanks
Nothing
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hi pmasknguyen!
honestly, i'm confused with your question... but if you mean to get the mouse position,
you can use the MousePosition property of the control. but this is in screen coordinates.
if you want to convert it to control coordinate, use PointToClient method and pass the MousePosition value as a parameter.
and also you can override OnMouseDown method if you are inheritng a control and if not, you can use MouseDown event instead.
hope that's what you want.
microsoc 
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I have used OnMouseDown but it's just update mouse position when tap on the screent. But when hold-tap the contextmenu will show out and the Event will not occur. How to catch this and get position.
Nothing
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so you mean, you want to get the Mouse position when the contextmenu shows?
if that's what you want, you can use the Popup event of the contextmenu. then on your event handler, you can now use the MousePosition property.
hope that solves your problem. 
microsoc 
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Hello,
I need to change the index of the currentrow so i can select the next record in the datagridview.
gtz stijn
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hi
How to add console in win app in vs 2005?
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Set the project type to "console application" in the project properties dialog
modified 12-Sep-18 21:01pm.
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Hi!
What do you mean with "how to add console"?
You want a windows application and an additional shell window (often referred to as 'console')?
Then call Process.Start("cmd.exe"); (although I can't see what this is good for right now).
Or do you mean a console like you get in some FPS games where you can type in commands for your application?
In this case you'll have to implement it for yourself. For example, create a dialog with a TextBox and every time <Return> is pressed, evaluate the string in the TextBox and act accordingly.
Regards,
mav
--
Black holes are the places where god divided by 0...
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hi guys,
how can i prevent a messagebox from reappearing? i have this timer that if the client is not connected to the server, a messagebox would appear informing the user that he is not connected to the server. i want the messagebox to show only once, until he is connected to the server. tnx in advance..
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How long a message box is displayed is controlled by the user. If you want to remove the messagebox by code, you can't use a messagebox. Use a small form instead.
---
b { font-weight: normal; }
-- modified at 8:25 Monday 27th February, 2006
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thanks for the reply..
ok, i thnk ill use a form as you suggested. how can automatically close the form? will i use a timer?
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Couldnt you just use a bool value to indicate whether or not its shown (might have to create it as an object for this) and use an if statement to act accordingly ?
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uhhh how is dat possible autekre? is that for the messagebox or the form?
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public partial class Form1 : Form<br />
{<br />
private Boolean lShowedOnce = false;<br />
<br />
public Form1()<br />
{<br />
InitializeComponent();<br />
}<br />
<br />
private void Timer1_Tick(object Sender, EventArgs e)<br />
{<br />
if (this.Tag != "Connected")<br />
{<br />
if (!lShowedOnce)<br />
{<br />
lShowedOnce = true;<br />
MessageBox.Show("You are not connected to the server....");<br />
}<br />
if (ConnectToServer())<br />
this.Tag = "Connected";<br />
}<br />
}<br />
<br />
private Boolean ConnectToServer()<br />
{<br />
Boolean lConnected = false;<br />
return (lConnected);<br />
}<br />
<br />
}<br />
----------
There go my people. I must find out where they are going so I can lead them.
- Alexander Ledru-Rollin
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hey thanks man!
i'll try this code immediately..
i really appreciate it..
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hai iam using wiaeasy image for capturing image,its working fine when i use web cam, while using video camera its giving error message like No wia device found. pls give me the code or what i have use to get the image of video camera.
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Hi!
Then why don't you ask the makers of wiaeasy image why it doesn't recognize your video camera?
Regards,
mav
--
Black holes are the places where god divided by 0...
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Hi
I would like to use the C# Datagrid that was submitted by one of your authors,Linjie, but i keep getting the following error:
"Failed to create component: Collate", when I attempt to drop it on my form.
Please assist
Thanks
Christopher
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Chances to receive a reply are much higher if you ask in the comments section of the article itself. The general C# forum isn't the correct place.
Regards,
mav
--
Black holes are the places where god divided by 0...
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i just wants when i click column header all the column "with its data " are selected
i've sent this question with another email plz replay on this message not on the other
regards,
dalia ali
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You need a DataGrid instead of the ListView.
In a ListView you can only select lines.
_________________________________
Please inform me about my English mistakes, as I'm still trying to learn your language!
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1. I'm writing a process manager and by the sounds EnterDebugMode is what I want to set, but how do I go about setting MY program to it as the method doesnt seem to be available to Process objects, is it really just as simple as Process.EnterDebugMode()/Process.LeaveDebugMode() without any associated object ?
2. I've got an 'oncolumnclick' sorting method that works fine but when I refresh my listview the sorting disappears, presumably theres an easy way to keep it (my refresh method involves clearing the whole thing and repopulating it) is there a way of figuring out which column was the last to be clicked and then sending a message to programatically 'reclick' it on refresh ?
TIA.
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i fill listview with items from a file
i want, when i select the column header, i want all the items in this column SELECTED... i tried to change the backcolor of this column and no use of it
if u can help me solving this problem plz
Dalia
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I have almost completed my application. I have created another form called DXSettings what I want (C# 2003) is code for the form DXSettings button btnwall to change a image in a PctWall in MainMenu Form. (Main menu will be open first) I used a Open File dialog. How would you do this?
In the end we're all just the same
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Hi
I am not sure what exactly u r trying to do. But to change an image in another form it is so simple
Diclare the picture box or the component whose image you nee to change as public
create the opject of that form in your form
Then go for the below code
xx.Image = Image.FromFile("c:\\abcd\\xyz.jpg");
Hope this helps you.
Neo
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