Managed C++/CLI

Re: MC++ Graphics HELP !!!

9-Feb-06 15:18

I think you can get the e-book from Apress for about half the price of the paperback. You can also download the C++/CLI Language specification which is very helpful.

hbjs9-Feb-06 16:10

hbjs

9-Feb-06 16:10

Yeh you can D/L the soucre code from the examples in the book. The Appress.com site like u mentioned. Ill gotta keep searchin throught the site, it seems pretty helpful.

cheers

makaveli

nooB question: Can mix MFC and .NET extensions in single app/class ?

Mike the Red8-Feb-06 2:25

Mike the Red

8-Feb-06 2:25

I just started moving to C++ a couple weeks ago, and have run into an issue I've not been able to Google an answer to.

From within VS, it seems I have to use .NET extensions to create a windows service, but some of the functionality I want to implement requires MFC (or, at least, the only way I've found to do it requires MFC).

Will the VS compiler allow me to use both .NET extensions and MFC ? And if so, are there steps I have to be able to use both ?

Thanks in advance for your help,

Mike the Red (a.k.a. The nooB) :->

Re: nooB question: Can mix MFC and .NET extensions in single app/class ?

George L. Jackson8-Feb-06 9:23

8-Feb-06 9:23

You can mix MFC with Managed C++ or the new C++/CLI. However, since MFC is native code, you have to marshall any data exchanges with managed code. CString, for example, is very easy to use with managed code.

null value check

madhusri7-Feb-06 21:37

madhusri

7-Feb-06 21:37

Hi all,

I need to check if an object created for a class is NULL or not....
How can this be done?

The code segment i had used is shown below:
public ref class Class1
{
private: static Class1 ^instance;
private: Class1();
public: static Class1^ Instance()
{
if(instance == NULL)
{
instance = gcnew Class1();
}
return instance;
}
};

This returns the following error:
error C2065: 'NULL' : undeclared identifier

Anyboby please help me out in this

Thanks in advance

Thanks and Regards
Madhu

-- modified at 4:49 Wednesday 8th February, 2006

Re: null value check

Cedric Moonen7-Feb-06 22:10

Cedric Moonen

7-Feb-06 22:10

Errrr

You mean this:

if (MyObject == NULL)<br />
{<br />
  // Do some stuff<br />
}

Re: null value check

toxcct7-Feb-06 22:49

Error using a Visual Basic DLL in c++

7-Feb-06 22:49

i think he's more asking for the C++/CLI way...
not sure, but it might be something like this :

if (MyObject.IsNull()) {
    //...
}

TOXCCT >>> GEII power
[toxcct][VisualCalc 2.20][VCalc 3.0 soon...]

Re: null value check

Red Stateler8-Feb-06 3:06

Red Stateler

8-Feb-06 3:06

Use nullptr in lieu of NULL for managed objects.

pipe problem

allenmpcx7-Feb-06 17:26

allenmpcx

7-Feb-06 17:26

Hello, I obtained the following code from MSDN under _pipe():

<code>
// crt_pipe.c
/* This program uses the _pipe function to pass streams of
* text to spawned processes.
*/

#include <stdlib.h>
#include <stdio.h>
#include <io.h>
#include <fcntl.h>
#include <process.h>
#include <math.h>

enum PIPES { READ, WRITE }; /* Constants 0 and 1 for READ and WRITE */
#define NUMPROBLEM 2

int main( int argc, char *argv[] )
{
int fdpipe[2];
char hstr[20];
int pid, problem, c;
int termstat;

/* If no arguments, this is the spawning process */
if( argc == 1 )
{
setvbuf( stdout, NULL, _IONBF, 0 );

/* Open a set of pipes */
if( _pipe( fdpipe, 256, O_BINARY ) == -1 )
exit( 1 );

/* Convert pipe read descriptor to string and pass as argument
* to spawned program. Program spawns itself (argv[0]).
*/
itoa( fdpipe[READ], hstr, 10 );
if( ( pid = spawnl( P_NOWAIT, argv[0], argv[0], hstr, NULL ) ) == -1 )
printf( "Spawn failed" );

/* Put problem in write pipe. Since spawned program is
* running simultaneously, first solutions may be done
* before last problem is given.
*/
for( problem = 1000; problem <= NUMPROBLEM * 1000; problem += 1000)
{
printf( "Son, what is the square root of %d?\n", problem );
write( fdpipe[WRITE], (char *)&problem, sizeof( int ) );
}

/* Wait until spawned program is done processing. */
_cwait( &termstat, pid, WAIT_CHILD );
if( termstat & 0x0 )
printf( "Child failed\n" );

close( fdpipe[READ] );
close( fdpipe[WRITE] );
}

/* If there is an argument, this must be the spawned process. */
else
{
std::cout << "\nGOT HERE\n" << std::endl;
/* Convert passed string descriptor to integer descriptor. */
fdpipe[READ] = atoi( argv[1] );

/* Read problem from pipe and calculate solution. */
for( c = 0; c < NUMPROBLEM; c++ )
{
read( fdpipe[READ], (char *)&problem, sizeof( int ) );
printf( "Dad, the square root of %d is %3.2f.\n", problem, sqrt( ( double )problem ) );
}
}
}
</code>

The problem is, the code will display the parent message and then the program stops. I also know that the child process will jump in while the parent process is inside the for loop (I did a simple printf("GOT HERE") inside of the child process). Is there something wrong with this code, or something I am missing?? Frown | :(

Mike - I love to program!

-- modified at 23:26 Tuesday 7th February, 2006

Re: pipe problem

kakan9-Feb-06 0:01

kakan

9-Feb-06 0:01

Where do you open and close the pipes in the spawned process?

The Hidden Message

Peter Charlesworth7-Feb-06 9:54

Peter Charlesworth

7-Feb-06 9:54

Good morning, fellow homo sapiens sapiens and other species

I am a novice c++ programmer who mainly does it for fun.

I am currently working on a small program which displays messages after a certain amount of time
and for a certain amount of time. It's purpose is primarily helping me study and maybe it might
one day function as an alert-messenger.

I basically does this: the user selects the messages that need to be displayed and sets the timer and
the delay between messages. Then the program randomly selects a message and displays that message
for the pre-defined amount of time after which it makes the message disappear and waits for a second
pre-defined amount of time to display the second message.

The problem is that I want it displayed not in the window with the DOS prompt executing my file, but
on the screen. Like those subliminal messaging programs do. How can i now make the string (message) appear on the screen (how do I output it to the screen, not the DOS prompt)? And how do I make it disappear after
the pre-defined amount of time?

One last thing is this question: can I determine the coordinates of this string with gotoxy(x,y)?
If not, how do I do this then?

A well-meaned thanks in advance,

Peter

P.S. My compiler is the Borland C++ 5.5 compiler, in case it's vital to know this. The .exe files are executed in a DOS prompt.

A program is to be written primarily for humans to read, and only secondarily for computers to be able to execute.

jtrujillogomez6-Feb-06 23:44

jtrujillogomez

6-Feb-06 23:44

Hi guys, i've an execution error when i use a dll from VB in c++. I've debugged the code and i've seen that the problem is when a callback function is returning...the point is that this callback function only drop down when is called from one of the dll's functions, but is working succesfully with the rest of them.

The functions of de dll are defined like this:

typedef void __stdcall (*funcion_crear)(char*,int,char*);
typedef void __stdcall (*funcion_configurar)(int,int,int,int,int);
typedef void __stdcall (*funcion_cargar)(char*);
typedef void __stdcall (*funcion_guardar)(char*);
typedef int __stdcall (*funcion_entrenar)(char*,char*);
typedef void __stdcall (*funcion_evaluar)(char*);
typedef void __stdcall (*CallVBFunctionStringPtr)(int);
typedef void __stdcall (*CallVBFunctionReportPerformancePtr)(int);
typedef void __stdcall (*CallVBFunctionClassificationResultPtr)(int);
funcion_crear fcrear;
funcion_configurar fconfig;
funcion_entrenar fentrenar;
funcion_evaluar fevaluar;
funcion_guardar fguardar;
funcion_cargar fcargar;
CallVBFunctionStringPtr callstring;
CallVBFunctionReportPerformancePtr callperformance;
CallVBFunctionClassificationResultPtr callresult;

Then, the external callback functions (CallVBxxx) are implemented with this three functions:

void __stdcall fCString (char* cadena,int longitud)
{
}

void __stdcall fCReportPerformance (char* cadenaestado,int longitud,int estado)
{
}

void __stdcall fCResult (int indice_clase)
{
Form1->resultado_RNA=indice_clase;

}

and the funcions are loaded from the main form like this:

fconfig=(funcion_configurar)(GetProcAddress(libreria,"ConfigureParameters"));

fcrear=(funcion_crear)(GetProcAddress(libreria,"create_net"));

fentrenar=(funcion_entrenar)(GetProcAddress(libreria,"train_net"));

fevaluar=(funcion_evaluar)(GetProcAddress(libreria,"test_net_singlevector"));

fguardar=(funcion_guardar)(GetProcAddress(libreria,"save_net"));

fcargar=(funcion_cargar)(GetProcAddress(libreria,"load_net"));

callstring=(CallVBFunctionStringPtr)(GetProcAddress(libreria,"CallVBFunctionStringPtr"));

callperformance=(CallVBFunctionReportPerformancePtr)(GetProcAddress(libreria,"CallVBFunctionReportPerformancePtr"));

callresult=(CallVBFunctionClassificationResultPtr)(GetProcAddress(libreria,"CallVBFunctionClassificationResultPtr"));

if ((callstring==NULL) || (callperformance==NULL) || (callresult==NULL)) ShowMessage("cagada");

callstring(int(&(fCString)));

callperformance(int(&(fCReportPerformance)));

callresult(int(&(fCResult)));

The only function that is dropping down is fevaluar, and the problem is when fCString callfuction is returning...

Can Somebody help me????

thank you very much

Best Regards.

How can I implement a C++ interface in C#2

tiancaidao6-Feb-06 22:39

tiancaidao

6-Feb-06 22:39

hi all,

To strip off circular dependency between a C# proj and a C++ proj, I need to define an interface in C++ proj. and implement it with C#. The code is like this:

//in C++ proj.
using namespace A
__gc __interface IA
{
void display();
}

//in C# proj.
public class B : A.IA
{
void display(){}
}

the error message is like this: COM Interop registration failed. Could not find a type library for assembly "A.IA" ...

3q for help!

Dilly

Dilly

George L. Jackson8-Feb-06 9:45

8-Feb-06 9:45

Your Managed C++ interface must be compiled into an assembly (Code Library). Your C# code must reference the compiled assembly to have proper access to the Managed C++ interface.

tiancaidao8-Feb-06 17:57

tiancaidao

8-Feb-06 17:57

3q for help, but I don't know exactly how to compile the managed interface into an assembly (Code Libray) with VS.NET 2003. Could you plz say something more clearly? Thank you!

Dilly

tiancaidao8-Feb-06 18:10

tiancaidao

8-Feb-06 18:10

I create a class library with .net, and I can subclass CA from the library, but still can not implement the interface IA in it. The error is the same:
-----------------------------------------------
COM Interop registration failed. Could not find a type library for assembly 'CodeLibrary'.

Dilly

George L. Jackson9-Feb-06 8:03

9-Feb-06 8:03

If you are using .NET 2.0 Framework, create a new C++/CLI project choosing the project type of "CLR" and the template "Class Library". The wizard will create an empty class in the header file (ending in ".h"). Modify the empty class to be your interface and compile. This process will create an assembly (ending in .dll) that you can use to reference in your C# code.

while(0) ?

CiNN6-Feb-06 21:36

CiNN

6-Feb-06 21:36

#define R(l,r,i) do { l ^= p[i]; r ^= F(l); } while(0)

why a while(0) ? D'Oh! | :doh:

toxcct6-Feb-06 22:55

6-Feb-06 22:55

useless so...

but avoid using such a macro in your code...

TOXCCT >>> GEII power
[toxcct][VisualCalc 2.20][VCalc 3.0 soon...]

Michael Dunn7-Feb-06 7:24

Michael Dunn

7-Feb-06 7:24

The do/while is there to provide a block. Without the do/while, this code:

if (somefunc())
  R(a,b,c);

wouldn't give the right behavior because only the first statement would be inside the if block.

--Mike--
Visual C++ MVP Cool | :cool:

LINKS~! Ericahist | NEW!! PimpFish | CP SearchBar v3.0 | C++ Forum FAQ

toxcct7-Feb-06 21:35

7-Feb-06 21:35

but it could have provided these instructions into a block ( { } ) without do/while...

#define R(l,r,i) { l ^= p[i]; r ^= F(l); }

TOXCCT >>> GEII power
[toxcct][VisualCalc 2.20][VCalc 3.0 soon...]

-- modified at 4:49 Wednesday 8th February, 2006

Stephen Hewitt14-Feb-06 13:31

Stephen Hewitt

14-Feb-06 13:31

Not in all cases. Here's two versions of a macro:

#define FOO1(n) { return n; }<br />
#define FOO2(n) do { return n; } while(0)

Now given these two macros this will not complile:

if ( 1 )
  FOO1(1);
else
  return 0;

But this will:

if ( 1 )
  FOO2(1);
else
  return 0;

So there is method to the madness.

Steve

toxcct14-Feb-06 21:23