C / C++ / MFC

m_myList.ModifyStyle(0, LVS_SINGLESEL);

m_myList.ModifyStyle(LVS_SINGLESEL, 0);

int main()
{
  int *ptr[2];
  for (int i = 0; i < 2; i++) {
    ptr[i] = NULL;
  }
  //...
  if (ptr[0] == NULL) {
    cout << "this is empty" << endl;
  }
}

int* ptr[2]={0};
cout << ptr[0] << endl;
cout << ptr[1] << endl;

string input;
char *driver;

cout << "Please input the driver's name : ";
cin >> input;

driver = new char[input.length() + 1];
strcpy(driver, input.c_str());
driver[input.length()] = 0;

cout << driver << endl;

neodeaths wrote:

i tryed it and it works thanks and i understand it too

but i wanna know wht do i need this?
driver[input.length()] = 0;

y shld assigh to 0??

Nishant Sivakumar wrote:

C/C++ strings are considered to be 0-terminated. If you don't terminate your string with a 0, any function that expects a 0-terminated string would run into issues.

Roland Pibinger wrote:

Yes, but strcpy also copies the teminating '\0'.